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Equations of Lines in Another Format
Slideshow 31, Mathematics Mr Richard Sasaki, Room 307
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Objectives Understand how to draw a line to an equation in the form ππ₯+ππ¦+π=0 by making π¦ the subject. Understand how to draw a line to an equation in the form ππ₯+ππ¦+π=0 by connecting two pairs of co-ordinates
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Drawing Graphs We now know how to draw a graph based on two simple pieces of information: The lineβs gradient The y-intercept it passes through This is great when the function is in the form π¦=ππ₯+π but not when itβs in a different form!
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Changing The Subject Another common way to write down the name of a line is in the form ππ₯+ππ¦+π=0. But now itβs not so clear what the gradient or y-intercept isβ¦so what should we do? Thatβs right, change the subject!
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Changing The Subject Letβs try changing ππ₯+ππ¦+π=0 (the general form) so that π¦ becomes the subject. ππ₯+ππ¦+π=0βΉ ππ₯+π=βππ¦ βΉπ¦=β ππ₯ π β π π So in this form, the gradient is β π π and the constant is β π π . Sounds messy doesnβt itβ¦ Anyway, letβs try changing the subject with numbers!
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Example Draw the graph 3π₯+2π¦β4=0. Letβs change it so π¦ is the subject.
3π₯+2π¦β4=0βΉ 3π₯β4=β2π¦ βΉπ¦=β 3π₯ β΄π¦=β 3π₯ 2 +2 The gradient is β 3 2 and the y-intercept is 2. Letβs draw it!
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Example 3π₯+2π¦β4=0 (π¦=β 3π₯ 2 +2) So it passes through y=2β¦
And itβs gradient is β So we go right two and down three to meet our line again. Something like thisβ¦
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Answers Shown are not ideal titles but the equation where y is the subject. π¦=π₯+2 π¦= 3 2 π₯+3 π¦=β 1 2 π₯+ 1 2 π¦=β6
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Finding co-ordinates If we are given a line ππ₯+ππ¦+π=0, can you see an easy pair of co-ordinates that we could find? When written in this form, itβs easy to find the two pointsβ¦ Because when π¦=0, we get ππ₯+π=0β¦ And when π₯=0, we get ππ¦+ π=0. We can then easily find π₯ and π¦ at those points!
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Example Draw the line 16π₯+4π¦β8=0 by finding two suitable pairs of co-ordinates. Letβs find co-ordinates π₯, 0 and (0, π¦) where π₯ and π¦ are numbers. When π₯=0β¦ 4π¦β8=0 4π¦=8 π¦=2 So we get (0, 2). When π¦=0β¦ 16π₯β8=0 16π₯=8 π₯= 1 2 So we get ( 1 2 , 0).
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Example This time we are drawing a line! What do we do? 16π₯+4π¦β8=0
(Note: Last time when we had two pairs of co-ordinates we used π= π¦ 2 β π¦ 1 π₯ 2 β π₯ 1 because we were calculating the line. This time we are drawing a line! What do we do? 16π₯+4π¦β8=0 Simply place our co- ordinates , 0 and (0, 2) onto the graph and join the dots! Note: You must use a ruler!!
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Answers The square would have co-ordinates (5, 0), (0, 5), (-5, 0) and (0, -5) and would have 4 line segments π¦=π₯+5, π¦=π₯β5, π¦=βπ₯+5, π¦=βπ₯β5. 3, 0 πππ (0, 3) 0, 6 πππ (β2, 0) β2, 0 πππ 0, 1 2 0, 9 πππ (β4, 0)
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