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CIRCLES AND SEGMENT MEASUREMENT
Section 10-7 Jim Smith JCHS
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COPY THESE NOTES AND DRAW THE DIAGRAMS
COPY THESE NOTES AND DRAW THE DIAGRAMS. USE THESE AND THE PRACTICE PROBLEMS AT THE END AS EXAMPLES FOR THE CLASS ASSIGNMENT
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ab = cd a d c b THE PRODUCT OF THE PARTS OF ONE CHORD = THE PRODUCT
THE OTHER CHORD ab = cd
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7 x 4 5 7x = 4(5) 7x = 20 7x= 20 7 7 X = 2.86
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. Radius = 6, so one part= 6+x and the other part= 6-x The diameter is
FOIL 4 (6+x) (6-x) = 4∙4 36-x²=16 36-x²-36 = 16-36 -x²= -20 -x²/-1 = -20/-1 x² = 20 √x² = √20 X = 4.47 The diameter is perpendicular to the chord, so it bisects the chord
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Whole segment B A The outside part of segment AB x the
whole segment AB = the outside part of segment CB x the whole segment CB C
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5 x 7 5(x+5) = 7(15+7) 15 5x+25 = 7(22) 5x+25 = 154 5x = 129 X = 25.8
Outside x Whole = Outside x Whole 5(x+5) = 7(15+7) little+little = big 15 5x+25 = 7(22) 5x+25 = 154 5x = 129 X = 25.8
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x Tangent (the outside is also the whole) 4 Outside x Whole = Outside x Whole x∙x = 4∙9 9 x² = 36 √x² = √36 X = 6 We know the whole so we don’t need to add the little parts
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TRY THESE 1 2 X 8 X 7 3 5 5 14
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Answers 1) 7X = 8(5) 7X = 40 X = 40/7 X = 5.71 2) 3(X+3) = 5(14)
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