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Shortest Paths and Minimum Spanning Trees
David Kauchak cs302 Spring 2012
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Admin
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Dijkstra’s algorithm
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What about Dijkstra’s on…?
1 B D 1 5 A 10 -10 E C
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What about Dijkstra’s on…?
Dijkstra’s algorithm only works for positive edge weights 1 B D 1 5 A 10 E C
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Bounding the distance Another invariant: For each vertex v, dist[v] is an upper bound on the actual shortest distance start off at only update the value if we find a shorter distance An update procedure
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Can we ever go wrong applying this update rule?
We can apply this rule as many times as we want and will never underestimate dist[v] When will dist[v] be right? If u is along the shortest path to v and dist[u] is correct
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Consider the shortest path from s to v
dist[v] will be right if u is along the shortest path to v and dist[u] is correct Consider the shortest path from s to v s p1 p2 p3 pk v
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What happens if we update all of the vertices with the above update?
dist[v] will be right if u is along the shortest path to v and dist[u] is correct What happens if we update all of the vertices with the above update? s p1 p2 p3 pk v
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What happens if we update all of the vertices with the above update?
dist[v] will be right if u is along the shortest path to v and dist[u] is correct What happens if we update all of the vertices with the above update? s p1 p2 p3 pk v correct
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What happens if we update all of the vertices with the above update?
dist[v] will be right if u is along the shortest path to v and dist[u] is correct What happens if we update all of the vertices with the above update? s p1 p2 p3 pk v correct correct
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Does the order that we update the vertices matter?
dist[v] will be right if u is along the shortest path to v and dist[u] is correct Does the order that we update the vertices matter? yes! If we did it in the order of the correct path, we’d be done. s p1 p2 p3 pk v correct correct
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dist[v] will be right if u is along the shortest path to v and dist[u] is correct
How many times do we have to do this for vertex pi to have the correct shortest path from s? i times s p1 p2 p3 pk v
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dist[v] will be right if u is along the shortest path to v and dist[u] is correct
How many times do we have to do this for vertex pi to have the correct shortest path from s? i times s p1 p2 p3 pk v correct correct
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dist[v] will be right if u is along the shortest path to v and dist[u] is correct
How many times do we have to do this for vertex pi to have the correct shortest path from s? i times s p1 p2 p3 pk v correct correct correct
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dist[v] will be right if u is along the shortest path to v and dist[u] is correct
How many times do we have to do this for vertex pi to have the correct shortest path from s? i times s p1 p2 p3 pk v correct correct correct correct
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dist[v] will be right if u is along the shortest path to v and dist[u] is correct
How many times do we have to do this for vertex pi to have the correct shortest path from s? i times s p1 p2 p3 pk v … correct correct correct correct
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dist[v] will be right if u is along the shortest path to v and dist[u] is correct
What is the longest (vetex-wise) the path from s to any node v can be? |V| - 1 edges/vertices s p1 p2 p3 pk v … correct correct correct correct
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Bellman-Ford algorithm
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Bellman-Ford algorithm
Initialize all the distances do it |V| -1 times iterate over all edges/vertices and apply update rule
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Bellman-Ford algorithm
check for negative cycles
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Negative cycles What is the shortest path from a to e? B D A E C 1 1 5
10 -10 E C 3
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Bellman-Ford algorithm
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Bellman-Ford algorithm
10 How many edges is the shortest path from s to: S A 8 1 -4 B G A: 2 1 1 -2 C F 3 -1 E D -1
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Bellman-Ford algorithm
10 How many edges is the shortest path from s to: S A 8 1 -4 B G A: 3 2 1 1 -2 C F 3 -1 E D -1
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Bellman-Ford algorithm
10 How many edges is the shortest path from s to: S A 8 1 -4 B G A: 3 2 1 1 B: -2 C F 3 -1 E D -1
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Bellman-Ford algorithm
10 How many edges is the shortest path from s to: S A 8 1 -4 B G A: 3 2 1 1 B: 5 -2 C F 3 -1 E D -1
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Bellman-Ford algorithm
10 How many edges is the shortest path from s to: S A 8 1 -4 B G A: 3 2 1 1 B: 5 -2 C F 3 -1 D: E D -1
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Bellman-Ford algorithm
10 How many edges is the shortest path from s to: S A 8 1 -4 B G A: 3 2 1 1 B: 5 -2 C F 3 -1 D: 7 E D -1
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Bellman-Ford algorithm
10 S A Iteration: 0 8 1 -4 B G 2 1 1 -2 C F 3 -1 E D -1
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Bellman-Ford algorithm
10 10 S A Iteration: 1 8 1 -4 B 8 G 2 1 1 -2 C F 3 -1 E D -1
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Bellman-Ford algorithm
10 10 S A Iteration: 2 8 1 -4 B 8 G 2 1 1 -2 C F 9 3 -1 E D -1 12
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Bellman-Ford algorithm
5 10 S A Iteration: 3 8 1 10 -4 B A has the correct distance and path 8 G 2 1 1 -2 C F 9 3 -1 E D -1 8
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Bellman-Ford algorithm
5 10 S A Iteration: 4 8 1 6 -4 B 8 G 2 1 1 -2 C 11 F 9 3 -1 E D -1 7
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Bellman-Ford algorithm
5 10 S A Iteration: 5 8 1 5 -4 B B has the correct distance and path 8 G 2 1 1 -2 C 7 F 9 3 -1 E D -1 14 7
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Bellman-Ford algorithm
5 10 S A Iteration: 6 8 1 5 -4 B 8 G 2 1 1 -2 C 6 F 9 3 -1 E D -1 10 7
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Bellman-Ford algorithm
5 10 S A Iteration: 7 8 1 5 -4 B D (and all other nodes) have the correct distance and path 8 G 2 1 1 -2 C 6 F 9 3 -1 E D -1 9 7
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Correctness of Bellman-Ford
Loop invariant:
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Correctness of Bellman-Ford
Loop invariant: After iteration i, all vertices with shortest paths from s of length i edges or less have correct distances
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Runtime of Bellman-Ford
O(|V| |E|)
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Runtime of Bellman-Ford
Can you modify the algorithm to run faster (in some circumstances)?
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All pairs shortest paths
Simple approach Call Bellman-Ford |V| times O(|V|2 |E|) Floyd-Warshall – Θ(|V|3) Johnson’s algorithm – O(|V|2 log |V| + |V| |E|)
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Minimum spanning trees
What is the lowest weight set of edges that connects all vertices of an undirected graph with positive weights Input: An undirected, positive weight graph, G=(V,E) Output: A tree T=(V,E’) where E’ E that minimizes
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MST example 1 A C E 3 4 4 2 5 4 B D F 4 6 1 A C E 4 2 5 4 B D F
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MSTs Can an MST have a cycle? 1 A C E 4 2 5 4 B D F 4
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MSTs Can an MST have a cycle? 1 A C E 4 2 5 4 B D F
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Applications? Connectivity
Networks (e.g. communications) Circuit design/wiring hub/spoke models (e.g. flights, transportation) Traveling salesman problem? MST is a lower bound on TSP. 2 * MST is one approximate solution to the TSP problem.
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Algorithm ideas? 1 A C E 3 4 4 2 5 4 B D F 4 6 1 A C E 4 2 5 4 B D F
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Cuts A cut is a partitioning of the vertices into two sets S and V-S
An edge “crosses” the cut if it connects a vertex uV and vV-S 1 A C E 3 4 4 2 5 4 B D F 4 6
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Minimum cut property Prove this!
Given a partion S, let edge e be the minimum cost edge that crosses the partition. Every minimum spanning tree contains edge e. Prove this!
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Minimum cut property Given a partion S, let edge e be the minimum cost edge that crosses the partition. Every minimum spanning tree contains edge e. S V-S e e’ Consider an MST with edge e’ that is not the minimum edge
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Minimum cut property Given a partion S, let edge e be the minimum cost edge that crosses the partition. Every minimum spanning tree contains edge e. S V-S e e’ Using e instead of e’, still connects the graph, but produces a tree with smaller weights
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Kruskal’s algorithm Given a partition S, let edge e be the minimum cost edge that crosses the partition. Every minimum spanning tree contains edge e.
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MST G Kruskal’s algorithm
Add smallest edge that connects two sets not already connected 1 A C E 3 4 5 4 2 4 MST B D F 4 6 A C E G B D F
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MST G Kruskal’s algorithm
Add smallest edge that connects two sets not already connected 1 A C E 3 4 5 4 2 4 MST B D F 1 4 6 A C E G B D F
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MST G Kruskal’s algorithm
Add smallest edge that connects two sets not already connected 1 A C E 3 4 5 4 2 4 MST B D F 1 4 6 A C E G 2 B D F
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MST G Kruskal’s algorithm
Add smallest edge that connects two sets not already connected 1 A C E 3 4 5 4 2 4 MST B D F 1 4 6 A C E G 2 4 B D F
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MST G Kruskal’s algorithm
Add smallest edge that connects two sets not already connected 1 A C E 3 4 4 2 5 4 MST B D F 1 4 6 A C E G 4 2 4 B D F
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MST G Kruskal’s algorithm
Add smallest edge that connects two sets not already connected 1 A C E 3 4 4 2 5 4 MST B D F 1 4 6 A C E G 4 2 5 4 B D F
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Correctness of Kruskal’s
Never adds an edge that connects already connected vertices Always adds lowest cost edge to connect two sets. By min cut property, that edge must be part of the MST
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Running time of Kruskal’s
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Running time of Kruskal’s
|V| calls to MakeSet O(|E| log |E|) 2 |E| calls to FindSet |V| calls to Union
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Running time of Kruskal’s
Disjoint set data structure O(|E| log |E|) + MakeSet FindSet |E| calls Union |V| calls Total |V| O(|V| |E|) |V| O(|V||E| + |E| log |E|) Linked lists O(|V| |E|) |V| O(|E| log |V|) |V| O(|E| log |V|+ |E| log |E|) Linked lists + heuristics O(|E| log |E| )
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Prim’s algorithm
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Prim’s algorithm
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Prim’s algorithm
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Prim’s algorithm Start at some root node and build out the MST by adding the lowest weighted edge at the frontier
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Prim’s 1 A C E 3 4 5 MST 4 2 4 B D F A C E 4 6 B D F
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Prim’s 1 A C E 3 4 5 MST 4 2 4 B D F A C E 4 6 B D F
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Prim’s 1 A C E 3 4 5 MST 4 2 4 5 4 B D F A C E 4 6 B D F 6
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Prim’s 1 A C E 3 4 5 MST 4 2 4 5 4 B D F A C E 4 6 B D F 6
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Prim’s 1 A C E 3 4 5 MST 4 2 4 5 1 4 B D F A C E 4 6 B D F 4 2
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Prim’s 1 A C E 3 4 5 MST 4 2 4 5 1 4 B D F A C E 4 6 B D F 4 2
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Prim’s 1 A C E 3 4 5 MST 4 2 4 5 1 4 B D F A C E 4 6 B D F 4 2
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Prim’s 1 A C E 3 4 5 MST 4 2 4 5 1 4 B D F A C E 4 6 B D F 4 2
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Prim’s 1 A C E 3 4 5 MST 4 2 4 5 1 4 B D F A C E 4 6 B D F 4 2
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Prim’s 1 A C E 3 4 5 MST 4 2 4 5 1 4 B D F A C E 4 6 B D F 4 2
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Prim’s 1 A C E 3 4 5 MST 4 2 4 5 1 4 B D F A C E 4 6 B D F 4 2
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Prim’s 1 A C E 3 4 5 MST 4 2 4 5 1 4 B D F A C E 4 6 B D F 4 2
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Correctness of Prim’s? Can we use the min-cut property?
Given a partion S, let edge e be the minimum cost edge that crosses the partition. Every minimum spanning tree contains edge e. Let S be the set of vertices visited so far The only time we add a new edge is if it’s the lowest weight edge from S to V-S
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Running time of Prim’s
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Running time of Prim’s Θ(|V|) Θ(|V|) |V| calls to Extract-Min
|E| calls to Decrease-Key
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Running time of Prim’s Same as Dijksta’s algorithm
1 MakeHeap |V| ExtractMin |E| DecreaseKey Total Array O(|V|) O(|V|2) O(|E|) O(|V|2) Bin heap O(|V|) O(|V| log |V|) O(|E| log |V|) O((|V|+|E|) log |V|) O(|E| log |V|) Fib heap O(|V|) O(|V| log |V|) O(|E|) O(|V| log |V| + |E|) Kruskal’s: O(|E| log |E| )
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