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Mathematical Induction I
Lecture 21 Section 4.2 Fri, Feb 23, 2007
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The Principle of Mathematical Induction
Let P(n) be a predicate defined for integers n. Let a be an integer. If the following two statements are true P(a) For all integers k a, if P(k), then P(k + 1) then the statement For all integers n a, P(n) is true.
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The Idea The first part shows that the statement is true for the integer a. The second part shows that Since it is true for a, it is true for a + 1. Since it is true for a + 1, it is true for a + 2. Since it is true for a + 2, it is true for a + 3. And so on. Therefore, it is true for all integers a.
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Like Dominos
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Proof by Mathematical Induction
Basic Step Choose a starting point a (typically 0 or 1). Prove P(a). Inductive Step Suppose P(k) for some arbitrary integer k a. Prove P(k + 1), using the assumption P(k). Conclude P(n) for all n a.
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Example: Mathematical Induction
Theorem: For any integer n 4, we can obtain n¢ using only 2¢ and 5¢ coins. Let P(n) be the predicate “we can obtain n¢ using only 2¢ and 5¢ coins.” Proof: Basic Step: (Start at a = 4.) P(4) is true since 4¢ = 2¢ + 2¢.
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Proof continued Inductive Step
Suppose that P(k) is true for some k 4. We must show that P(k + 1) is true. Consider two cases: Case 1: k¢ uses a 5¢ coin. Case 2: k¢ does not use a 5¢ coin.
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Proof concluded Case 1: k¢ uses a 5¢ coin.
Then remove it and replace it with three 2¢ coins, thereby obtaining (k + 1)¢. Case 2: k¢ does not use a 5¢ coin. Then it must use at least two 2¢ coins. Replace two 2¢ coins with one 5¢ coin, thereby obtaining (k + 1)¢.
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Proof concluded Therefore, P(n) is true for all n 4.
Therefore, P(k + 1) is true. Therefore, P(n) is true for all n 4.
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Example: Mathematical Induction
Theorem: For all n 1, Proof: Basic Step When n = 1, we have
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Proof and Therefore, the statement is true when n = 1.
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Proof Inductive Step Suppose that the statement is true when
n = k, for some k 1. That is, suppose that
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Proof Then
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Proof Therefore, the statement is true for all n 1.
Therefore, the statement is true when n = k + 1. Therefore, the statement is true for all n 1.
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Example: Mathematical Induction
Theorem: For all n 1, Proof: Basic Step Show… Inductive Step Suppose…
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Sums of Powers of Integers
We can also prove by induction that
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Mathematical Induction
Mathematical induction requires that we “know” the answer in advance. The method verifies the answer. How would we come up with the guess that in the first place?
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Finding the Formula We might conjecture that the answer is a cubic polynomial in n. Why? That is, for some real numbers a, b, c, and d. Then figure out what a, b, c, and d are. How?
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Finding the Formula Substitute the values 0, 1, 2, and 3 into the equation to get a system of four equations. d = 0. a + b + c + d = 12 = 1. 8a + 4b + 2c + d = = 5. 27a + 9b + 3c + d = = 14.
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Finding the Formula Solve the system of equations and get
b = 1/2, c = 1/6, d = 0. Then verify using mathematical induction.
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Let’s Play “Find the Flaw”
Theorem: For every positive integer n, in any set of n horses, all the horses are the same color. Proof: Basic Step. When n = 1, there is only one horse, so trivially they are (it is) all the same color.
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Find the Flaw Inductive Step
Suppose that any set of k horses are all the same color. Consider a set of k + 1 horses. Remove one of the horses from the set. The remaining set of k horses are all the same color.
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Find the Flaw Replace that horse and remove a different horse.
Again, the remaining set of k horses are all the same color. Therefore, the two horses that were removed are the same color as the other horses in the set. Thus, the k + 1 horses are all the same color.
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Find the Flaw Thus, in any set of n horses, the horses are all the same color.
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The Paradox of the Pop Quiz
A professor wants to give a pop quiz to his class on a day when they are not expecting it. Theorem: For all n 0, the professor cannot give the pop quiz n days before the last day. Corollary: The professor cannot give a pop quiz.
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