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Bellwork 3(x + 4) = 14 5(a - 4) = 3a 5 + 3(n - 7) = 10

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Presentation on theme: "Bellwork 3(x + 4) = 14 5(a - 4) = 3a 5 + 3(n - 7) = 10"— Presentation transcript:

1 Bellwork 3(x + 4) = 14 5(a - 4) = 3a 5 + 3(n - 7) = 10
Quiz Solve the following: 3(x + 4) = 14 5(a - 4) = 3a 5 + 3(n - 7) = 10 7(c + 2) = 3(c - 3) 5 - 2(y - 4) = 19 x = 2/3 1.) a = 10 2.) n = 26/3 3.) c = -23/4 4.) y = -3 5.)

2 Bellwork 1.) 3(x + 4) = 14 3x + 12 = 14 3x + 12 - 12 = 14 - 12 3x = 2
Back

3 Bellwork 2.) 5(a - 4) = 3a 5a - 20 = 3a 5a -5a -20 = 3a - 5a -20 = -2a
Back

4 Bellwork 3.) 5 + 3(n - 7) = 10 5 + 3n - 21 = 10 3n - 16 = 10
Back

5 Bellwork 4.) 7(c + 2) = 3(c - 3) 7c + 14 = 3c - 9
Back

6 Bellwork 5.) 5 - 2(y - 4) = 19 5 - 2y + 8 = 19 -2y + 13 = 19
x = -3 Back

7 Bellwork Do the Integrated Review on page 152 ( odd). 51.) 12 1 -8/5 2 -4/7 57.) 53.) 59.) 55.)

8 51.) |-3| + n = 15 3 + n = 15 n = 15 -3 n = 12 back

9 53.) 5x + (-4)2 =21 5x + 16 =21 5x + 16 -16 =21 -16 5x = 5 5x/5 = 5/5
back

10 55.) 3t -(-2t) + 14 = 6 5t + 14 = 6 5t + 14 -14 = 6 -14 5t = -8
back

11 57.) 3(10y - 12) + 15y = 54 30y y = 54 45y -36 = 54 45y = 45y = 90 45y/45 = 90/45 y = 2 back

12 59.) x = 8 - 5x 12 + 2x +5x = 8 - 5x +5x 12 + 7x = 8 x = 8 -12 7x = -4 7x/7 = -4/7 x = -4/7 back

13 To be able to solve Literal Equations.
Today’s Objective To be able to solve Literal Equations. Equations with more than one variable

14 The dirt formula (d = rt)
d = distance, r = rate, t = time What if you wanted to find the rate (r) instead of the distance (d), how could you change this formula???

15 The dirt formula (d = rt)
Divide Both sides of the equation by t If d = rt, Then d/t = rt/t d/t = r

16 Be ready to name what happened on each step below
d = rt d/t = rt/t d/t = r divide by t

17 What do you need to get rid of inorder to get w by itself?
Solve v = lwh for w What do you need to get rid of inorder to get w by itself? v = lwh lh

18 What do you need to divide both sides by?
Solve v = lwh for w What do you need to divide both sides by? v = lwh v = lwh lh lh v/lh = w

19 Subtract 2 from both sides
Solve ab + 2 = c for a ab = c -2 ab = c -2 Divide both sides by b Subtract 2 from both sides ab + 2 = c /b ab = (c-2) /b a = (c-2)/b

20 Solve ab = c for b Divide both sides by a Now you try this one ab = c
b = c/a Now you try this one

21 Solve xy +4 = z for x What do you divide both sides by?
Subtract 4 from both sides xy + 4 = z What do you divide both sides by? xy = z -4 -4 Now you try this one xy = z - 4 xy = (z - 4) /y /y x = (z - 4)/y

22 Explain the following to your neighbor
What a literal equation is? An equation with more than 1 variable….

23 Explain the following to your neighbor
How do you determine what the Best First Step (BFS) is when solving a literal equation?

24 How do you determine what the Best First Step (BFS) is when solving a literal equation?
Use the 4 Steps!

25 classwork Do worksheet 3.6 ( 1-17)
You must use a separate sheet of paper. homework pg.157 (1-18)


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