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Ordinary Differential Equations
Chapter 2 Ordinary Differential Equations
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2.1 Introduction Ordinary Differential Equation
(2.1) Partial Differential Equation (Chapter 8) (2.2)
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2.2 Order and Degree Order = 3, Degree =1, Non Linear
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Equations in which the variables can be separated Homogeneous
2.3 First Order Exact equations Equations in which the variables can be separated Homogeneous Equation solvable by an integrating factor.
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Equations in which the variables can be separated
Exact equations Equations in which the variables can be separated
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Homogeneous Equations
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Sparging chlorine gas into benzene
Example Batch Reactor Sparging chlorine gas into benzene How much chroline must be added to give maximum yield of C6H6Cl Assume isothermal
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p = moles of chlorine present q = moles of benzene present
Basis 1.0 mole of Chlorine, at time q, V=const p = moles of chlorine present q = moles of benzene present r = moles of monochlorobenzene present s = moles of dichlorobenzene present t = moles of trichlorobenzene present q+r+s+t =1 Amount of chlorine consumed y=r+2s+3t
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VI VII Divide VII by VI
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MatLab Divide VIII by VI gives
After eliminate r … using integrating factor The result is : MatLab To determine t using : q+r+s+t =1
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Equation Solved by Integrating Factors
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Example
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Example3 Horizontal tank 1m diameter 2 m long
Insulate with asbestos l = 4 cm. Charge 95 oC liquid Hold for 5 days
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k =0.2 W/m K h1=150 W/m2K r =1000 kg/m3 Cp = 2500 J/kg K h2=10 W/m2K Plot Liquid temperature with time
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Surface Area Rate of heat loss by liquid Rate of heat loss through lagging Rate of heat loss to surrounding All Rates are equal , eliminate Tw
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Thermal equilibrium of Liquid
Input rate Output rate Accumulation rate
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Second Order Differential Eqs
Non-linear Dependent Variables does not occur explicitly Independent Variables does not occur explicitly Homogeneous Equation Linear The coefficients in the equation are constant The coefficients are functions of independent varible
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Dependent variable does not occur explicitly
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Independent variable does not occur explicitly
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Homogeneous Second sub
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Second sub
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Independent variable does not occur explicitly
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Example Estimate the duty of water cooler h = 1.7 W/m2 oC 20 oC
Insulator Water Cooler 50 oC 1500 oC Furnace f = 15 cm 150 oC 30 cm Estimate the duty of water cooler
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Heat Balance Sectional area (A) = m2 Input Output Accumulation = 0
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By Integrating factor Back Substitution Can’t Integrate
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Assume constant heat loos
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Using negative because
As x increase T decrease
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But
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Linear Differential Equation
Second Order and Complementary Function 2 constants Particular Integral
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Complementary Function
Auxiliary Eqn Assume Solution Unequal roots
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Equal roots Example
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Example
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Particular Integral Undetermined Coefficients Inverse Operators
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Undetermined Coefficients
(i)f(x) constant ,C
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(ii) f(x) polynomial (iii) f(x) Terx
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Example
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(iv) f(x)
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(iv) Modified f(x) Example
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Example
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Example A B y,c =Conc. A Bulk Flow of A Diffusion of A k L=1 m u m3/s
dx x y,c =Conc. A Bulk Flow of A Diffusion of A
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Remove by reaction of A Input - Output
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Simultaneous : Elimination
t1 80 oC t2 t3 20 oC 0.96 kg/s Cp J/kgoC I II T2 45 oC T1 88 oC T oC 1.25 kg/s h1=1150 W/m2K h2=750 W/m2K V = 4500 kg A m2 A m2 Water stop for 1 hr: what are temperature 2. Then supply water at 1.25 kg/s for 1hr
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Water Failed In - out = Acc Tank 1 Tank 2
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Using Integrating Factor
At 1 hr
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Water Restore T1 T1 t2 t1
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At 1 hr oC
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