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Ordinary Differential Equations

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Presentation on theme: "Ordinary Differential Equations"— Presentation transcript:

1 Ordinary Differential Equations
Chapter 2 Ordinary Differential Equations

2 2.1 Introduction Ordinary Differential Equation
(2.1) Partial Differential Equation (Chapter 8) (2.2)

3 2.2 Order and Degree Order = 3, Degree =1, Non Linear

4 Equations in which the variables can be separated Homogeneous
2.3 First Order Exact equations Equations in which the variables can be separated Homogeneous Equation solvable by an integrating factor.

5 Equations in which the variables can be separated
Exact equations Equations in which the variables can be separated

6 Homogeneous Equations

7 Sparging chlorine gas into benzene
Example Batch Reactor Sparging chlorine gas into benzene How much chroline must be added to give maximum yield of C6H6Cl Assume isothermal

8 p = moles of chlorine present q = moles of benzene present
Basis 1.0 mole of Chlorine, at time q, V=const p = moles of chlorine present q = moles of benzene present r = moles of monochlorobenzene present s = moles of dichlorobenzene present t = moles of trichlorobenzene present q+r+s+t =1 Amount of chlorine consumed y=r+2s+3t

9 VI VII Divide VII by VI

10

11

12 MatLab Divide VIII by VI gives
After eliminate r … using integrating factor The result is : MatLab To determine t using : q+r+s+t =1

13

14 Equation Solved by Integrating Factors

15 Example

16

17 Example3 Horizontal tank 1m diameter 2 m long
Insulate with asbestos l = 4 cm. Charge 95 oC liquid Hold for 5 days

18 k =0.2 W/m K h1=150 W/m2K r =1000 kg/m3 Cp = 2500 J/kg K h2=10 W/m2K Plot Liquid temperature with time

19 Surface Area Rate of heat loss by liquid Rate of heat loss through lagging Rate of heat loss to surrounding All Rates are equal , eliminate Tw

20 Thermal equilibrium of Liquid
Input rate Output rate Accumulation rate

21

22 Second Order Differential Eqs
Non-linear Dependent Variables does not occur explicitly Independent Variables does not occur explicitly Homogeneous Equation Linear The coefficients in the equation are constant The coefficients are functions of independent varible

23 Dependent variable does not occur explicitly

24 Independent variable does not occur explicitly

25 Homogeneous Second sub

26 Second sub

27 Independent variable does not occur explicitly

28 Example Estimate the duty of water cooler h = 1.7 W/m2 oC 20 oC
Insulator Water Cooler 50 oC 1500 oC Furnace f = 15 cm 150 oC 30 cm Estimate the duty of water cooler

29 Heat Balance Sectional area (A) = m2 Input Output Accumulation = 0

30

31 By Integrating factor Back Substitution Can’t Integrate

32 Assume constant heat loos

33

34 Using negative because
As x increase T decrease

35 But

36

37 Linear Differential Equation
Second Order and Complementary Function 2 constants Particular Integral

38 Complementary Function
Auxiliary Eqn Assume Solution Unequal roots

39 Equal roots Example

40 Example

41 Particular Integral Undetermined Coefficients Inverse Operators

42 Undetermined Coefficients
(i)f(x) constant ,C

43 (ii) f(x) polynomial (iii) f(x) Terx

44 Example

45 (iv) f(x)

46 (iv) Modified f(x) Example

47 Example

48 Example A B y,c =Conc. A Bulk Flow of A Diffusion of A k L=1 m u m3/s
dx x y,c =Conc. A Bulk Flow of A Diffusion of A

49 Remove by reaction of A Input - Output

50

51 Simultaneous : Elimination
t1 80 oC t2 t3 20 oC 0.96 kg/s Cp J/kgoC I II T2 45 oC T1 88 oC T oC 1.25 kg/s h1=1150 W/m2K h2=750 W/m2K V = 4500 kg A m2 A m2 Water stop for 1 hr: what are temperature 2. Then supply water at 1.25 kg/s for 1hr

52 Water Failed In - out = Acc Tank 1 Tank 2

53 Using Integrating Factor
At 1 hr

54 Water Restore T1 T1 t2 t1

55 | | | | | | | | | | |

56

57 At 1 hr oC


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