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An Introduction to Direct and Inverse Proportion
Slideshow 26, Mathematics Mr Richard Sasaki, Room 307
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Objectives Recall the meaning of proportional and learn two common forms See how the rate of change differs between both forms Practice finding the rate of change for functions where there is no constant
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Proportion Two things are proportional when there is no constant added to them (b = 0). π π₯ =ππ₯ β π π₯ Ξ± π₯ Here, π π₯ and π₯ are directly proportional. (Their relation is only affected by a multiple.) Letβs look at an example.
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Example (Direct Proportion)
Letβs look at an example. A boy bakes cakes at a rate of 8 cakes per hour. Represent this as a function where π₯ is the number of hours after he starts. π π₯ = 8π₯ As b (the constant) = 0, π π₯ Ξ± π₯. 8π₯ means that for every hour he works, he makes 8 cakes.
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Example (Direct Proportion)
Letβs look at this in the form of a table. π π₯ = 8π₯ π 1 2 3 π(π₯) 8 16 24 We can see that the way that π₯ and π(π₯) are increasing relate to each other. They also start at (0, 0) because of no b constant. This shows that they are directly proportional. The rate of change will remain the same. (π = π)
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Example (Inverse Proportion)
Letβs look at another example. A girl bakes 24 cakes and needs to split them between π₯ people (π₯ is the number of people). Represent this as a function where π π₯ is the amount of cake that each person gets. 24 π₯ π π₯ = As b (the constant) = 0, π π₯ Ξ± 1 π₯ . This shows that π π₯ and π₯ are inversely proportional (π π₯ Ξ± 1 π₯ ).
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Example (Inverse Proportion)
Try the worksheet! Letβs look at this in the form of a table. 24 π₯ π π₯ = π 1 2 3 π(π₯) β 24 12 8 We can see that the way that π₯ and π(π₯) are changing relate to each other. As one goes up, the other goes down. There is no b constant but they do not start at (0,0) because the function is not linear. This implies that they are inversely proportional. What is happening with the rate of change? It is changingβ¦
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ππππππ‘ππ¦ πππππππ‘πππππ
π π₯ =2500π₯ ππππππ‘ππ¦ πππππππ‘πππππ π 1 2 3 π(π₯) 0 Yen 2500 Yen 5000 Yen 7500 Yen π π₯ = π₯ πππ£πππ πππ¦ πππππππ‘πππππ π 1 2 3 4 π(π₯) 48000 Yen 24000 Yen 16000 Yen 12000 Yen π π₯ =β 1 2 π₯ ππππππ‘ππ¦ πππππππ‘πππππ
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