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Lecture 12: Electroweak Kaon Regeneration & Oscillation
The Mass of the W The Massless Photon & Broken Symmetry The Higgs Mixing and the Weinberg Angle The Mass of the Z Z Decay Useful Sections in Martin & Shaw: Chapter 9, Chapter 10
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So what are kaons??? that depends... who wants to know?!
Regeneration So what are kaons??? that depends... who wants to know?! Ko, Ko states of definite strangeness K1o, K2o states of definite CP KSo, KLo states of definite lifetime KL KL + KS strong interaction with matter picks out Ko & Ko which then re-mix
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So what are kaons??? ''Regeneration"
that depends... who wants to know?! Ko, Ko states of definite strangeness K1o, K2o states of definite CP KSo, KLo states of definite lifetime KL ''Regeneration" KL + KS strong interaction with matter picks out Ko & Ko which then re-mix
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Strangeness Oscillation
Amplitudes for decaying states KSo and KLo as a function of time are AS(t) = AS(0) exp(imSt) exp(St/2) S ℏ/S AL(t) = AL(0) exp(imLt) exp(Lt/2) L ℏ/L K1o = 1/2 ( Ko + Ko ) K2o = 1/2 ( Ko Ko ) or Ko = 1/2 ( K1o + K2o ) Ko = 1/2 ( K1o K2o ) ≃ 1/2 ( KSo + KLo ) ≃ 1/2 ( KSo KLo ) AK(t) = 1/2 ( AS(t) + AL(t) ) AK(t) = 1/2 ( AS(t) AL(t) )
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Strangeness Oscillation Intensities
Thus, if we start with a pure Ko beam at t=0, the intensity at time t will be I(Ko) = 1/2 [AS(t) + AL(t)][AS*(t) + AL*(t)] (setting AS(0) = AL(0) = 1) = 1/4 {exp(St) + exp(Lt) + 2 exp[(S+L)t/2] cosmt } and similarly, = 1/4 {exp(St) + exp(Lt) 2 exp[(S+L)t/2] cosmt } I(Ko) = 1/2 [AS(t) AL(t)][AS*(t) AL*(t)] Ko where m mLmS = 3.49x1012 MeV (m/m ≃ 7x1015)
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K, W and Z A B C D E F G H I J L M N O P Q R S T U V X Y
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Weak Coupling & the W Mass
Recall that the ''matrix element" for scattering from a Yukawa potential is f V o = g2/(q2+M2) In the Fermi theory of decay, this is what essentially becomes GF or, more precisely, GF/2 = g2/(q2+M2) = 4W/(q2+M2) GF2 and the relatively small value of GF characterizes the fact that the weak interaction is so weak We can get this small value either by making W small or by making M large So what if we construct things so W = ??? UNIFICATION !! Assuming M ≫ q2 , M = 4 2 / GF M ~ 100 GeV CERN, 1983 MW = 80 GeV !! = 1/137 GF = 105 GeV2
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p W- u hadrons d e, , u e-, -, - d hadrons
Stochastic Cooling Electron Cooling
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Electroweak Interlude
A Brief Theoretical Interlude (electroweak theory... at pace!!)
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( )L ( )L Wo 1/2 ( )
Weak Isospin But how can this be the ''same" force when the W’s are charged and the photon certainly isn’t !? Is there a way we can ''bind up" the W’s along with a neutral exchange particle to form a ''triplet" state (i.e. like the pions) ?? Well, like with the pions, we seem to have a sort of ''Weak" Isospin since the weak force appears to see the following left-handed doublets e e ( )L u d ( )L c s t b as essentially two different spin states: IW(3) = 1/2 (like p-n symmetry) e e W+ Thus, in the process The W+ must carry away +1 units of IW(3) so let’s symbolically denote W+ and, similarly, W If IW = 1 for the W’s then, similar to the o, there is also a neutral state: Wo 1/2 ( ) (which completes the triplet)
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Higgs Mechanism 1/2 ( )
The Higgs There is, however, another orthogonal state: 1/2 ( ) If we ascribe this to the photon, then perhaps we might expect to see weak ''neutral currents" associated with the exchange of a Wo with a similar mass to the W so we’d have a nice ''single package" which describes EM and weak forces! Hold on... any simple symmetry is obviously very badly broken the photon is massless and the W’s are certainly not! The photon is also blind to weak isospin and also couples to right-handed leptons & quarks as well Assume the symmetry was initially perfect and all states were massless Then postulate that there exists some overall (non-zero) ''field" which couples to particles and gives them additional virtual loop diagrams : (kind of like an ''aether" which produces a sort of ''drag") but in the limit of zero momentum transfer (rest mass), so represent as Higgs Mechanism
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Further suppose that this field is blind to weak isospin
Mixing: the Photon & Z Further suppose that this field is blind to weak isospin and, thus, allows for it’s violation. This would allow the neutral weak isospin states to mix like with the mesons (the W are charged and cannot mix) We will call the ''pure," unmixed states Wo and And we will call the physical, mixed states Zo and
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M2 W = W + W M2 W = W + W + M2 = + + Wo
Masses and Couplings Think about mathematically introducing this Higgs coupling by applying some ''mass-squared" operator to the initial states (since mass always enters as the square in the propagator) M2 W = W W GW GW M2 W = W W GW GW GW GG M2 = Wo GG GG GG GW where the right-most terms represent the weak isospin - violating terms Assume couplings to W’s are all the same (GW) but coupling to may be different (GG ) For the W the mass would then simply be given by MW2 = GW2 (where G2 contains the coupling plus a few other factors) For the latter 2 equations, we can think of M2 as an operator which yields the mass-squared, M2 , for the coupled state: M2 Wo = GW2 Wo + GW GG M2 = GG2 + GW GG W
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Massless Photon / Massive Z
= Wo GW GG (M2-GG2) From the second of these: M2 Wo = GW2 Wo Wo GW2 GG2 (M2-GG2) Substituting into the first: M4 M2 GG2 = M2 GW2 GW2 GG2 + GW2 GG2 M2 ( M2 GG2 GW2) = 0 M2 = or M2 = GW2 + GG2 Thus, associate M2 = 0 and MZ2 = GW2 + GG2 Note also that MZW
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Ql + 3Qq = 0 MZ = MW/cosW
Weinberg Angle & Z Mass We can parameterize the as a mixture of Wo and as follows: W ''Weinberg Angle" sinW Wo cosW Thus, applying M2 : M2 = M2 ( sinW Wo cosW) = 0 0 = ( GG2 + GW GGW ) sinW (GW2 Wo GW GG cosW Coefficient of Wo GW GGsinW GW2 cosW = 0 Coefficient of GG2sinW GW GG cosW = 0 tan W = GG / GW ''unification condition" Ql + 3Qq = 0 ''anomaly condition" (leptons) (quarks) MZ2/MW2 = (GW2 + GG2)/GW2 = 1/cos2W MZ = MW/cosW is satisfied separately for each generation
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Neutral Current Event p (Gargamelle Bubble Chamber, CERN, 1973)
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sin2W = 0.226 MW = 80 GeV MZ = 91 GeV (predicted)
Z Discovery Z e+ e From comparing neutral and charged current rates sin2W = 0.226 MW = 80 GeV MZ = 91 GeV (predicted) MZ = 91 GeV (observed!!)
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Flavour-changing neutral currents
While we’re here... pre-ABBA weak doublet = u d cosqC + s sinqC ( ) d´ = ( ) So, consider the coupling to the Z0 : Z0 (d cosqC + s sinqC) Z0 u + Probability ∝ product of wave functions: uu + (dd cos2qC + ss sin2qC) (sd + ds ) sinqC cosqC DS = 0 DS = 1 “Flavour-Changing Neutral Currents” never seen!
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( ) ( ) ( ) ( ) & + + Postulate 2 doublets:
GIM mechanism Postulate 2 doublets: (Glashow, Iliopolis & Maiaini: “GIM” mechanism) u d cosqC + s sinqC ( ) d´ = ( ) c s cosqC - d sinqC ( ) s´ = ( ) & Z0 u (d cosqC + s sinqC) + Z0 c (s cosqC - d sinqC) + uu + cc + (dd+ss)cos2qC + (ss+dd) sin2qC) + (sd + ds - sd - sd) sinqC cosqC DS = 0 DS = 1
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Resonant Cross Section
Blam ! formation ''rate" of initial state (recall = ℏ/) ( ) W = dP dN 0 prob for decay to particular final state given the total number of available states Transition Rate = 0 ( ) dP dE dE dN dP f dE (E-E0)2 + 2/4 = dN dE ( ) 1 V q2 dq d (2) dE ( ) = 1 W = vB / V But recall that V q2 2 v ( ) 1 = 0 f q2 (E-E0)2 + 2/4
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Relativistic Treatment
But this is non-relativistic! From considering scattering from a Yukawa potential (which followed from the relativistic Klein-Gordon equation) we found the ''propagator" 1/(q2 + M2) So consider the diagram: Under a fully relativistic treatment, q is the 4-momentum transfer and, if we sit in the rest frame of the intermediate state, q2 = p2 E2 = E2 Also note that, for a decaying state, the intermediate mass takes on an imaginary component M M i / since ~ exp(iE0t) = exp(iMt) exp{i(Mi/2)}t = exp(iMt) exp(t/2)
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Relativistic Breit-Wigner
Thus, the propagator goes like 1 (Mi/2)2 E2 1 M2 /4 iM E2 = 1 M2 iM E2 (in the limit ≪ M) ≃ And the cross section will be proportional to the square of the propagator : ( )( ) 1 M2 iM E2 M2 iM E2 ~ 1 (E2 M2)2 + M2 = = 0 f q2 (E-E0)2 + 2/4 compare so, roughly, /2 M and we’d expect something like ~ M2 0 f E2 (E2-M2)2 + M22 = M2 0 f E2 (E2 M2)2 + M22 CM In fact, a full relativistic treatment yields
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[ ] (e+e X) = MZ2 ee X
The Z Resonance Thus, for the production of Z0 near resonance and the subsequent decay to some final state ''X" : (e+e X) = MZ ee X E (E2 MZ2)2 + MZ22 CM [ ] since ee can be related by time-reversal to ee Peak of resonance MZ Height of resonance product of branching ratios ee X BreeBrX=
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Z Decay: Generation Limit
Results: MZ = GeV Z = GeV hadrons= GeV l l = GeV (3 x ) = ≠ !! (limit for light, ''active" neutrinos) So what’s left ??? ''Invisible modes" Neutrinos !!
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An End To The Generation Game ???
End To Generation Game An End To The Generation Game ??? (not necessarily a bad thing!)
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