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Quarterly # 3 Algebra 1A Review: Multiple Choice, Select All That Apply, Open-Ended
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infinitely many solutions
1. infinitely many solutions one solution no solution cannot be determined
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infinitely many solutions
1. Graph the first line. Graph the second line. The equations are of the same line. infinitely many solutions Answer:
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infinitely many solutions
2. infinitely many solutions one solution no solution cannot be determined
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2. The graphs intersect at one point. Answer: Graph the first line.
Graph the second line. The graphs intersect at one point. one solution Answer:
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infinitely many solutions
3. infinitely many solutions one solution no solution cannot be determined
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3. The graphs do not intersect. Answer: Graph the first line.
Graph the second line. The graphs do not intersect. no solution Answer:
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4. (2, 2) (2, 2) (4, 2) (2, 4)
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4. The graphs intersect at the point (2, 4). Answer:
Graph the first line. Graph the second line. The graphs intersect at the point (2, 4). (2, 4) Answer:
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5. 1 1 7 7
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5. Substitute 5 into the equation: 2x + y = 3 2(5) + y = 3 10 + y = 3
10 y = 7 7 Answer:
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6. (2, 5) (2, 5) (5, 2) (4, 7)
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6. 1 x + y = 3 x y = 7 If you add the equations, y cancels out.
x = 2 x + y = 3 Use either equation to find y: (2, 5) Answer: 2 + y = 3 – –2 y = 5
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7. 2 2 5 5
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7. 6x + 5y = 27 +5y cancels with 5y 5y
5( ) +5y cancels with 5y 6x + 5y = 27 5y In order to get 5y, multiply the bottom row by 5. 5 Answer:
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8. (2, 4) (2, 4) (4, 2) (4, 2)
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8. Answer: Cancel x by making 20x and 20x. 4 ( ) 5 ( )
4 ( ) 5 ( ) Get either variable to cancel. 20x + 28y = 136 20x 15y = 110 Substitute into any equation to find x: 13y = 26 4x + 3y = 22 y = 2 4x + 3(2) = 22 4x + 6 = 22 6 6 4x = 16 (4, 2) Answer: x = 4
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9. (1, 6) (3, 2) (2, 3) (4, 1)
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9. Answer: See which point is NOT shaded in the graph.
Plot each point: (1, 6), (3, 2), (2, 3), (4, 1) The point (1, 6) is outside of the shaded region. (1, 6) Answer:
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10. (3, 1) (0, 0) (1, 0) (2, 4)
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10. Answer: See which point is shaded in the graph. Plot each point:
(3, 1), (0, 0), (1, 0), (2, 4) The point (2, 4) is inside of the shaded region. (2, 4) Answer:
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11. y ≥ x + 4 1 3 y ≤ x + 4 1 3 y ≥ 3x + 4 y ≤ 3x + 4
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11. Answer: The shading is above the line: use ≥.
The y-intercept is 4. The inequality is in the form y ≥ mx + 4. Find the slope, m. Use (0, 4) and (1, 1). Answer: y ≥ 3x + 4 m = 1 – 4 1 – 0 = – 3 1 = – 3
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12. 7x 8 7x 6 8x 8 8x 6
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12. (7x )(x ) = 7x x When multiplying powers, add the exponents and keep the base. = 7x 4+2 = 7x 6 7x 6 Answer:
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13. y 20 4y 5 y 9 4y 9
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13. Answer: (y ) When raising powers, multiply the exponents
5 4 When raising powers, multiply the exponents and keep the base. = y 54 = y 20 y 20 Answer:
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14. a 8 a 3 a 12 a 4
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14. Answer: a When dividing powers, subtract the exponents
6 2 When dividing powers, subtract the exponents and keep the base. = a 6 – 2 There are 4 more factors of “a” in the numerator. = a 4 a 4 Answer:
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15. 3x 4 y 5 14 x 4 y 5 3x 6 y 5 14x 4 y 5
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15. = = Answer: Divide the coefficients. 21x y 21 ÷ 7 = 3 7x y
5 3 7x y 1 8 Divide the coefficients. 21 ÷ 7 = 3 Place the x as x in the numerator. 3x x y y 8 = 3x 5+1 y 8 – 3 = Mult. add exponents. Div. subtract exponents 3x 6 y 5 Answer:
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16. 4x + 5x y + 3xy + 6y 5x y 4x + 3xy + 6y 6y + 3xy + 5x y 4x
5x y 4x + 3xy + 6y 6y + 3xy + 5x y 4x 6y + 5x y + 3xy 4x
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16. Answer: Descending Order: greatest power of x to
least power of x. 5x y y 4x x y 4x + 5x y + 3xy + 6y Answer: Separate the terms and determine their signs.
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17. 7m – 3 2 2 7m + 11 7m – 18m – 3 2 2 6m – 18m – 3
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17. Answer: 6m – 9m + 4 Line up the like terms. Add the coefficients.
2 Line up the like terms. Add the coefficients. + 1m – 9m – 7 2 7m – 18m – 3 2 Answer:
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18. 3 4 73 a = the cost of an adult c = the cost of a child
a = the cost of an adult c = the cost of a child 3a + 4c = adults & 4 children 3a + 7c = adults & 7 children Highlight the important information in order to answer the question. The group number is not important for writing the system.
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18. 3a + 4c = 73 3a + 7c = 94 3a + 4c = 73 3a 7c = 94 3a + 4c = 73
1( ) 3a + 4(7) = 73 3a + 28 = 73 3c = 21 28 28 3 Adult ticket = $15 Child’s ticket = $7 3a = 45 c = 7 a = 15 Take the opposite of one row (multiply by 1) for “a” to cancel. Solve for c. Substitute into any of the equation to find “a”. Explain what the solution means.
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19. 7x x When dividing powers, subtract the exponents.
2 x 10 When dividing powers, subtract the exponents. The “7” is a coefficient and cannot change location. = 7x 210 = 7x 8 A negative exponent in the numerator = a positive exponent in the denominator. 7 x 8 =
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20. 4y3 + 8x3 6xy y3 – 4x3 + 12xy Line up the like terms. 18xy
Combine the like terms. 4y3 + 8x3 6xy
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20. 4y3 + 8x3 6xy Find the degree of each polynomial.
1+1 = 2 The highest degree of the polynomials = 3
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20. 4y3 + 8x3 6xy The polynomial has 3 terms: 4y3, 8x3, 6xy
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20. 8x3 – 6xy – 4y3 terms and look at the exponents of x.
Separate the terms and look at the exponents of x. 4y3 + 8x3 6xy 4y3 + 8x3 6x1y1 The exponents of x are decreasing (getting lower). 8x3 – 6xy – 4y3
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Keep studying for your Quarterly Exam.
The End Keep studying for your Quarterly Exam.
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