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Reading: Pierret 11.1-11.2; Hu 8.2-8.6
Lecture 25 OUTLINE The BJT (cont’d) Ideal transistor analysis Narrow base and narrow emitter Ebers-Moll model Base-width modulation Reading: Pierret ; Hu
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Notation (PNP BJT) NE NAE DE DN tE tn LE LN nE0 np0 = ni2/NE
NB NDB DB DP tB tp LB LP pB0 pn0 ni2/NB NC NAC DC DN tC tn LC LN nC0 np0 ni2/NC EE130/230M Spring 2013 Lecture 25, Slide 2
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“Game Plan” for I-V Derivation
Solve the minority-carrier diffusion equation in each quasi-neutral region to obtain excess minority-carrier profiles different set of boundary conditions for each region Find minority-carrier diffusion currents at depletion region edges Add hole & electron components together terminal currents EE130/230M Spring 2013 Lecture 25, Slide 3
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Emitter Region Analysis
Diffusion equation: General solution: Boundary conditions: Solution: EE130/230M Spring 2013 Lecture 25, Slide 4
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Collector Region Analysis
Diffusion equation: General solution: Boundary conditions: Solution: EE130/230M Spring 2013 Lecture 25, Slide 5
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Base Region Analysis Diffusion equation: General solution:
Boundary conditions: Solution: EE130/230M Spring 2013 Lecture 25, Slide 6
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Since we can write as EE130/230M Spring 2013 Lecture 25, Slide 7
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EE130/230M Spring 2013 Lecture 25, Slide 8
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BJT Terminal Currents We know: Therefore: EE130/230M Spring 2013
Lecture 25, Slide 9
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BJT with Narrow Base In practice, we make W << LB to achieve high current gain. Then, since we have: EE130/230M Spring 2013 Lecture 25, Slide 10
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BJT Performance Parameters
Assumptions: emitter junction forward biased, collector junction reverse biased W << LB EE130/230M Spring 2013 Lecture 25, Slide 11
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BJT with Narrow Emitter
Replace with WE’ if emitter is narrow EE130/230M Spring 2013 Lecture 25, Slide 12
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Ebers-Moll Model increasing (npn) or VEC (pnp) The Ebers-Moll model is a large-signal equivalent circuit which describes both the active and saturation regions of BJT operation. Use this model to calculate IB and IC given VBE and VBC EE130/230M Spring 2013 Lecture 25, Slide 13
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If only VEB is applied (VCB = 0):
aR : reverse common base gain aF : forward common base gain If only VCB is applied (VEB = 0): : Reciprocity relationship: EE130/230M Spring 2013 Lecture 25, Slide 14
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In the general case, both VEB and VCB are non-zero:
IC: C-B diode current + fraction of E-B diode current that makes it to the C-B junction IE: E-B diode current + fraction of C-B diode current that makes it to the E-B junction Large-signal equivalent circuit for a pnp BJT EE130/230M Spring 2013 Lecture 25, Slide 15
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Base-Width Modulation
Common Emitter Configuration, Active Mode Operation W IE IC P+ N P + VEB DpB(x) IC (VCB=0) x VEC W(VBC) EE130/230M Spring 2013 Lecture 25, Slide 16
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Ways to Reduce Base-Width Modulation
Increase the base width, W Increase the base dopant concentration NB Decrease the collector dopant concentration NC Which of the above is the most acceptable action? EE130/230M Spring 2013 Lecture 25, Slide 17
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Early Voltage, VA Output resistance:
A large VA (i.e. a large ro ) is desirable IC IB3 IB2 IB1 VEC VA EE130/230M Spring 2013 Lecture 25, Slide 18
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Derivation of Formula for VA
Output conductance: for fixed VEB where xnC is the width of the collector-junction depletion region on the base side xnC P+ N P EE130/230M Spring 2013 Lecture 25, Slide 19
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EE130/230M Spring 2013 Lecture 25, Slide 20
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Summary: BJT Performance Requirements
High gain (bdc >> 1) One-sided emitter junction, so emitter efficiency g 1 Emitter doped much more heavily than base (NE >> NB) Narrow base, so base transport factor aT 1 Quasi-neutral base width << minority-carrier diffusion length (W << LB) IC determined only by IB (IC function of VCE,VCB) One-sided collector junction, so quasi-neutral base width W does not change drastically with changes in VCE (VCB) Based doped more heavily than collector (NB > NC) (W = WB – xnEB – xnCB for PNP BJT) EE130/230M Spring 2013 Lecture 25, Slide 21
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