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You can calculate: Central tendency Variability You could graph the data
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You can calculate: Central tendency Variability You could graph the data
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Bivariate Distribution
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Positive Correlation
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Positive Correlation
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Regression Line
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Correlation r = 1.00
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Regression Line . . . . . r = .64
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Regression Line . . . . . r = .64
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Practice
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Regression Line
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Regression Line . . . . .
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Regression Line . . . . .
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Negative Correlation
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Negative Correlation r =
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Negative Correlation . . . r = - .85 . .
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Zero Correlation
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Zero Correlation . . . . . r = .00
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Correlation Coefficient
The sign of a correlation (+ or -) only tells you the direction of the relationship The value of the correlation only tells you about the size of the relationship (i.e., how close the scores are to the regression line)
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Excel Example
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Which is a bigger effect?
r = or r = -.40 How are they different?
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Interpreting an r value
What is a “big r” Rule of thumb: Small r = .10 Medium r = .30 Large r = .50
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Practice Do you think the following variables are positively, negatively or uncorrelated to each other? Alcohol consumption & Driving skills Miles of running a day & speed in a foot race Height & GPA Forearm length & foot length Test #1 score and Test#2 score
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Statistics Needed Need to find the best place to draw the regression line on a scatter plot Need to quantify the cluster of scores around this regression line (i.e., the correlation coefficient)
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Covariance Correlations are based on the statistic called covariance
Reflects the degree to which two variables vary together Expressed in deviations measured in the original units in which X and Y are measured
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Note how it is similar to a variance
If Ys were changed to Xs it would be s2 How it works (positive vs. negative vs. zero)
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Computational formula
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Ingredients: ∑XY ∑X ∑Y N
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N = 5
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∑XY = 84 ∑Y = 23 ∑X = 15 N = 5
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∑XY = 84 ∑Y = 23 ∑X = 15 N = 5
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∑XY = 84 ∑Y = 23 ∑X = 15 N = 5
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∑XY = 84 ∑Y = 23 ∑X = 15 N = 5
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∑XY = 84 ∑Y = 23 ∑X = 15 N = 5
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Problem! The size of the covariance depends on the standard deviation of the variables COVXY = 3.75 might occur because There is a strong correlation between X and Y, but small standard deviations There is a weak correlation between X and Y, but large standard deviations
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Solution Need to “standardize” the covariance
Remember how we standardized single scores
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Correlation
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Correlation
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Correlation
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Practice You are interested in if candy intake is related to childhood depression. You collect data from 5 children.
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Practice Candy Depression Charlie 5 55 Augustus 7 43 Veruca 4 59 Mike
108 Violet 65 Scandy = 1.52 Sdepression = 24.82
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Practice Candy (X) Depression (Y) XY Charlie 5 55 275 Augustus 7 43
301 Veruca 4 59 236 Mike 3 108 324 Violet 65 260 ∑
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Practice Candy (X) Depression (Y) XY Charlie 5 55 275 Augustus 7 43
301 Veruca 4 59 236 Mike 3 108 324 Violet 65 260 ∑ 23 330 1396
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∑XY = 1396 ∑Y = 330 ∑X = 23 N = 5
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∑XY = 1396 ∑Y = 330 ∑X = 23 N = 5
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Correlation COV = -30.5 Sx = 1.52 Sy = 24.82
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Correlation COV = -30.5 Sx = 1.52 Sy = 24.82
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Hypothesis testing of r
Is there a significant relationship between X and Y (or are they independent) Like the X2
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Steps for testing r value
1) State the hypothesis 2) Find t-critical 3) Calculate r value 4) Calculate t-observed 5) Decision 6) Put answer into words
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Practice Determine if candy consumption is significantly related to depression. Test at alpha = .05
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Practice Candy Depression Charlie 5 55 Augustus 7 43 Veruca 4 59 Mike
108 Violet 65 Scandy = 1.52 Sdepression = 24.82
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Step 1 H1: r is not equal to 0 H0: r is equal to zero
The two variables are related to each other H0: r is equal to zero The two variables are not related to each other
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Step 2 Calculate df = N - 2 Page 747 First Column are df
Look at an alpha of .05 with two-tails
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t distribution df = 3
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t distribution tcrit = tcrit = 3.182
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t distribution tcrit = tcrit = 3.182
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Step 3 COV = -30.5 Sx = 1.52 Sy = 24.82
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Step 4 Calculate t-observed
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Step 4 Calculate t-observed
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Step 4 Calculate t-observed
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Step 5 If tobs falls in the critical region:
Reject H0, and accept H1 If tobs does not fall in the critical region: Fail to reject H0
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t distribution tcrit = tcrit = 3.182
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t distribution tcrit = tcrit = 3.182 -2.39
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Step 5 If tobs falls in the critical region:
Reject H0, and accept H1 If tobs does not fall in the critical region: Fail to reject H0
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Step 6 Determine if candy consumption is significantly related to depression. Test at alpha = .05 Candy consumption is not significantly related to depression Note: this finding is due to the small sample size
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SPSS
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Practice Is there a significant (.05) relationship between aggression and happiness?
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Mean aggression = 14. 50; S2aggression = 19. 63 Mean happiness = 6
Mean aggression = 14.50; S2aggression = Mean happiness = 6.00; S2happiness = 4.67
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Answer Cov = -7.33 r = -.76 t crit = 4.303 Thus, fail to reject Ho
Aggression was not significantly related to happiness
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SPSS
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