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Natural Deduction Hurley, Logic 7.1
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Our First 4 Argument Forms
Modus Ponens: p → q p _______ q Modus Tollens ~q ~p Hypothetical Syllogism: p → q q → r _______ p → r Disjunctive Syllogism p v q ~p q Remember that p, q, and r stand for any well-formed formula, no matter how complex. For instance, below is an example of disjunctive syllogism: ~(K v J) v ~B ~~(K v J) __________ ~B
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Practice Finding Proof Steps
1. A → B 2. ~A → (C v D) 3. ~B 4. ~C / D 5. ~A 1,3 MT 6. C v D 2,5 MP 7. D 4,6 DS
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Practice Finding Proof Steps
F → G F v H ~G H → (G → I) / F → I ~ F ,3 MT H ,5 DS G → I ,6 MP F → I ,7 HS
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Practice Finding Proof Steps
~J J v K K → L / L K ,2 DS L ,4 MP
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Practice Finding Proof Steps
T → U R → S / R → U S → U ,2 HS R → U ,4 HS
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Practice Finding Proof Steps
E → (K → L) (Example from Hurley 12th edition) F → (L → M) G v E ~G F / K → M L → M ,5 MP E ,4 DS K → L ,7 MP K → M ,8 HS
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Practice Finding Proof Steps
~(A ● B) v [~(E ● F) → (C → D)] (Example from Hurley 11th edition) ~~(A ● B) ~(E ● F) D → G / C → G ~(E ● F) → (C → D) ,2, DS C → D ,5, MP C → G ,6, HS
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Practice Finding Proof Steps
G → [~O → (G → D)] O v G ~O / D G ,3, DS ~O → (G → D) ,4, MP G → D ,5, MP D ,6, MP
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Practice Finding Proof Steps
~M v (B v ~T) B → W ~~M ~W / ~T B v ~T ,3, DS ~B ,4, MT ~T ,6, DS
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Practice Finding Proof Steps
(L Ξ N) → C (L Ξ N) v (P → ~E) ~E → C ~C / ~P ~~E ,4, MT ~(L Ξ N) ,4, MT P → ~E ,6, DS ~P ,7, MT
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