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Published byTamara Бјелица Modified over 6 years ago
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Baseline (flightpath D): To know that forces acting in a non-parallel direction can be resolved by drawing a parallelogram. Further (flightpath C): Demonstrate that forces acting in a non-parallel direction can be resolved as a parallelogram of forces. Challenge (flightpath B&A): Apply their knowledge of the parallelogram of forces to resolves examples of pairs of forces.
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Starter – follow these instructions to draw a shape…
Starting towards the bottom right corner of the graph paper (don’t start right at the edge!) draw a vertical line 8cm long. Turning clockwise by 70° draw a line 6cm long. Turning clockwise again by 110° draw a line 8cm long. Finally turn clockwise again 70° and draw a line 6cm long. (you should have finished back where you started!) What is this shape called?
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Starter – follow these instructions to draw a shape…
Starting towards the bottom right corner of the graph paper (don’t start right at the edge!) draw a vertical line 8cm long. Turning clockwise by 70° draw a line 6cm long. Turning clockwise again by 110° draw a line 8cm long. Finally turn clockwise again 70° and draw a line 6cm long. (you should have finished back where you started!) What is this shape called? A parallelogram
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Tug o’ War A tug o’ war contest is going on. There is 1 adult on one side of the rope and 2 children on the other. Both sides are pulling with an equal force. We can represent the forces in a freebody diagram like this: 23N 50N 27N The resultant force is 0N and therefore it is in equilibrium and will not move, but what will happen if the children pull on two different ropes like this: 23N 50N 27N The children are still pulling with an equal force but now the forces are not acting parallel to each other. If you know the magnitude and direction of each force then you can calculate the resultant force.
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