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Algebra 2 โ€“ Outcomes Construct a quadratic equation from its roots.

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Presentation on theme: "Algebra 2 โ€“ Outcomes Construct a quadratic equation from its roots."โ€” Presentation transcript:

1 Algebra 2 โ€“ Outcomes Construct a quadratic equation from its roots.
Solve systems of equations with one linear and one quadratic equation. Solve linear inequalities. Change the subject of a formula. Solve exponential equations.

2 Construct a Quadratic Equation
Recall a previous quadratic equation ๐‘ฅ 2 +5๐‘ฅ+4=0: ๐‘ฅ+4 ๐‘ฅ+1 =0 โ‡’๐‘ฅ=โˆ’4 or ๐‘ฅ=โˆ’1 -4 and -1 are called the roots of the equation. Graphically, where the equation crosses the ๐‘ฅ axis. We can create a quadratic equation from given roots if we work backwards.

3 Construct a Quadratic Equation
e.g. ๐‘ฅ=โˆ’4 or ๐‘ฅ=โˆ’1 โ‡’๐‘ฅ+4=0 or ๐‘ฅ+1=0 โ‡’ ๐‘ฅ+4 ๐‘ฅ+1 =0 โ‡’ ๐‘ฅ 2 +๐‘ฅ+4๐‘ฅ+1=0 โ‡’ ๐‘ฅ 2 +5๐‘ฅ+1=0

4 Construct a Quadratic Equation
e.g. Construct a quadratic equation with each of the following pairs of roots: ๐‘ฅ=6 and ๐‘ฅ=1 ๐‘ฅ=4 and ๐‘ฅ=10 ๐‘ฅ=5 and ๐‘ฅ=โˆ’4 ๐‘ฅ=โˆ’3 and ๐‘ฅ=7 ๐‘ฅ= 1 2 and ๐‘ฅ=4 ๐‘ฅ=โˆ’ 8 5 and ๐‘ฅ= 1 2

5 Solve Linear-Quadratic Systems
Recall solving linear-circle problems in coordinate geometry, for example: ๐‘ฅ+๐‘ฆ=4โ‡’๐‘ฅ=4โˆ’๐‘ฆ ๐‘ฅ 2 + ๐‘ฆ 2 =10 โ‡’ 4โˆ’๐‘ฆ 2 + ๐‘ฆ 2 =10 โ‡’16โˆ’4๐‘ฆโˆ’4๐‘ฆ+ ๐‘ฆ 2 + ๐‘ฆ 2 =10 โ‡’2 ๐‘ฆ 2 โˆ’8๐‘ฆ+6=0 โ‡’ ๐‘ฆ 2 โˆ’4๐‘ฆ+3=0 โ‡’ ๐‘ฆโˆ’3 ๐‘ฆโˆ’1 =0 โ‡’๐‘ฆ=3, 1 Rearrange line to ๐‘ฅ= or ๐‘ฆ= Substitute into circle eqn Simplify and solve quadratic

6 Solve Linear-Quadratic Systems
๐‘ฅ=4โˆ’๐‘ฆ ๐‘ฆ=3, 1 ๐‘ฅ=4โˆ’3=1โ‡’(1,3) or ๐‘ฅ=4โˆ’1=3โ‡’(3,1) Substitute ๐‘ฆ values back into line equation

7 Solve Linear-Quadratic Systems
2004 OL P1 Q3 Solve for ๐‘ฅ and ๐‘ฆ ๐‘ฅ+๐‘ฆ=1 ๐‘ฅ 2 + ๐‘ฆ 2 =13 2006 OL P1 Q3 Solve for ๐‘ฅ and ๐‘ฆ ๐‘ฅโˆ’2๐‘ฆ=10 ๐‘ฅ 2 + ๐‘ฆ 2 =20 2012 OL P1 Q3 Solve for ๐‘ฅ and ๐‘ฆ ๐‘ฅโˆ’๐‘ฆ+5=0 ๐‘ฅ 2 + ๐‘ฆ 2 =17 Which solution gives the lesser value of ๐‘ฅโˆ’2๐‘ฆ? Write down this value.

8 Solve Linear Inequalities (Graphic)
Given the function ๐‘“ ๐‘ฅ =3๐‘ฅโˆ’2, Plot a graph of ๐‘“ ๐‘ฅ in the domain โˆ’3โ‰ค๐‘ฅโ‰ค3. Use your graph to solve the inequality ๐‘“(๐‘ฅ)โ‰ค0. Given the function ๐‘” ๐‘ฅ = 4๐‘ฅ 3 +1, Plot a graph of ๐‘”(๐‘ฅ) in the domain โˆ’6โ‰ค๐‘ฅโ‰คโˆ’2. Use your graph to solve the inequality ๐‘” ๐‘ฅ <0. Given the functions โ„Ž ๐‘ฅ =3๐‘ฅโˆ’4 and ๐‘˜ ๐‘ฅ =๐‘ฅโˆ’2 Plot โ„Ž(๐‘ฅ) and ๐‘˜(๐‘ฅ) in the domain โˆ’2โ‰ค๐‘ฅโ‰ค4. Use your graph to solve the inequality โ„Ž ๐‘ฅ >๐‘˜(๐‘ฅ).

9 Solve Linear Inequalities (Algebraic)
The rules for solving inequalities are almost the same as the rules for solving equalities. ๐Ÿ‘<๐Ÿ” 3+3<6+3โ‡’6<9 Addition valid 3โˆ’3<6โˆ’3โ‡’0<3 Subtraction valid 3ร—3<6ร—3โ‡’9<18 Multiplication valid 3 3 < 6 3 โ‡’1<2 Division valid 3ร—โˆ’3<6ร—โˆ’3โ‡’โˆ’9โ‰ฎโˆ’18 Negative multiplication invalid 3 โˆ’3 < 6 โˆ’3 โ‡’โˆ’1โ‰ฎโˆ’2 Negative division invalid

10 Solve Linear Inequalities (Algebraic)
Multiplying or dividing by a negative number makes the inequality invalid. When multiplying or dividing by a negative number, the direction of the inequality must be reversed. e.g. 3ร—โˆ’3<6ร—โˆ’3โ‡’โˆ’9>โˆ’18

11 Solve Linear Inequalities (Algebraic)
โ‡’3๐‘ฅโ‰ค2 โ‡’๐‘ฅโ‰ค 2 3 Solve 4๐‘ฅ 3 +1<0 โ‡’ 4๐‘ฅ 3 <โˆ’1 โ‡’4๐‘ฅ<โˆ’3 โ‡’๐‘ฅ<โˆ’ 3 4

12 Solve Linear Inequalities (Algebraic)
โ‡’3๐‘ฅโˆ’๐‘ฅ>โˆ’2+4 โ‡’2๐‘ฅ>2 โ‡’๐‘ฅ> 2 2 โ‡’๐‘ฅ>1

13 Solve Linear Inequalities (Algebraic)
Recall the sets: โ„• - natural positive whole numbers โ„ค - integers all whole numbers โ„ - real all numbers Sometimes we must plot our solutions on number lines, which varies with set. e.g. plot ๐‘ฅ>โˆ’3 for ๐‘ฅโˆˆโ„•, ๐‘ฅโˆˆโ„ค, ๐‘ฅโˆˆโ„ on number lines. ๐‘ฅโˆˆโ„• ๐‘ฅโˆˆโ„ค ๐‘ฅโˆˆโ„ For ๐‘ฅโ‰ฅโˆ’3, simply add a dot to โˆ’3 for ๐‘ฅโˆˆโ„ค and ๐‘ฅโˆˆโ„

14 Solve Linear Inequalities (Algebraic)
e.g. solve each of the following and plot their solutions on an appropriate number line. ๐‘ฅ+3<10;๐‘ฅโˆˆโ„• 3๐‘ฅโˆ’2โ‰ค0;๐‘ฅโˆˆโ„ค 4๐‘ฅ 3 +1<0;๐‘ฅโˆˆโ„ 3๐‘ฅโˆ’4>๐‘ฅโˆ’2;๐‘ฅโˆˆโ„ค 4๐‘ž+3โ‰ค2 ๐‘ž+3 ;๐‘ฅโˆˆโ„ 4 3 ๐‘ฅโˆ’6<7๐‘ฅ+2;๐‘ฅโˆˆโ„ค 7 3๐‘ฅ+2 โˆ’5 2๐‘ฅโˆ’3 >7;๐‘ฅโˆˆโ„• ๐‘ฅโˆ’7 3 > 2๐‘ฅโˆ’3 2 ;๐‘ฅโˆˆโ„•

15 Solve Linear Inequalities (Algebraic)
2003 OL P1 Q3 Find the solution set of 5๐‘ฅโˆ’3<12, ๐‘ฅโˆˆโ„• 2007 OL P1 Q3 Find the solution set of 4๐‘ฅโˆ’15<1, ๐‘ฅโˆˆโ„• 2010 OL P1 Q3 Find the values of ๐‘ฅ which satisfy 2 3+4๐‘ฅ โ‰ค22, ๐‘ฅโˆˆโ„• 2006 OL P1 Q2 Find the smallest natural number ๐‘˜ such that 2๐‘ฅ+4 ๐‘ฅ ๐‘ฅ+4 <20(๐‘ฅ+๐‘˜)

16 Solve Linear Inequalities (Algebraic)
2005 OL P1 Q3 Find ๐ด, the solution set of 3๐‘ฅโˆ’2<4, ๐‘ฅโˆˆโ„ค Find ๐ต, the solution set of 1โˆ’3๐‘ฅ 2 <5, ๐‘ฅโˆˆโ„ค List the elements of ๐ดโˆฉ๐ต. 2011 OL P1 Q3 Find ๐ด, the solution set of 3๐‘ฅโˆ’5<7, ๐‘ฅโˆˆโ„ค Find ๐ต, the solution set of โˆ’2โˆ’3๐‘ฅ 4 <1, ๐‘ฅโˆˆโ„ค List the elements of ๐ดโˆฉ๐ต.

17 Change the Subject of a Formula
When a variable is expressed as an expression of other variables, we call it the subject of the equation. e.g. for ๐‘ฆ=๐‘š๐‘ฅ+๐‘ we call ๐‘ฆ the subject because we are expressing it as a combination of the other variables ๐‘š, ๐‘ฅ, and ๐‘. e.g. identify the subject of each of the following: ๐‘ฃ=๐‘ข+๐‘Ž๐‘ก ๐‘‰=๐œ‹ ๐‘Ÿ 2 โ„Ž ๐‘๐‘โˆ’๐‘‘=๐‘Ž ๐‘‡ 2 = 4 ๐œ‹ 2 ๐‘… 3 ๐บ๐‘€

18 Change the Subject of a Formula
To change the subject of a formula, apply the normal rules of algebra so that the given variable is the new subject: e.g. change the subject of ๐ถ= 5 9 (๐นโˆ’32) to ๐น ๐ถ= 5 9 (๐นโˆ’32) Multiply by 9 โ‡’9๐ถ=5(๐นโˆ’32) Divide by 5 โ‡’ 9๐ถ 5 =๐นโˆ’32 Add 32 โ‡’ 9๐ถ 5 +32=๐น

19 Change the Subject of a Formula
Express ๐‘š= ๐‘ฃ ๐‘ข in terms of ๐‘ฃ. Express ๐‘ƒ๐‘‰=๐‘›๐‘…๐‘‡ in terms of ๐‘…. Express ๐น=๐‘ƒ 1+๐‘– ๐‘ก in terms of ๐‘ƒ. Express ๐น= 1 4๐œ‹๐œ€ ๐‘ž 1 ๐‘ž 2 ๐‘‘ 2 in terms of ๐œ€. Express 1 ๐‘“ = 1 ๐‘ข + 1 ๐‘ฃ in terms of ๐‘“. Express ๐‘‡ 2 = 4 ๐œ‹ 2 ๐‘… 3 ๐บ๐‘€ in terms of ๐œ‹. Express ๐‘ฅ= โˆ’๐‘ยฑ ๐‘ 2 โˆ’4๐‘Ž๐‘ 2๐‘Ž in terms of ๐‘Ž.

20 Change the Subject of a Formula
Find ๐‘ if 5๐‘Ž+๐‘Ž๐‘=3๐‘Ž Find ๐‘Ÿ if 3 2๐‘Ÿโˆ’5 =27 Find ๐‘ฅ if 0.5 ๐‘ฅโˆ’8 =0.2๐‘ฅ+11 Find ๐‘› if 9โˆ’2๐‘›=3 ๐‘›+2 Find ๐‘Ž if ๐‘Ž 2 =49 Find ๐‘ if 2๐‘โˆ’8 4 =๐‘โˆ’3 Find ๐‘ฆ if 0.1๐‘ฆ+7 2 = ๐‘ฆ 2.5

21 Solve Problems by Rearranging
Consider an animal pen measuring ๐‘š metres long and ๐‘› metres wide. Write down a formula for the perimeter of the pen. If the pen is 5 metres long and 4 metres wide, calculate the perimeter of the pen. If the perimeter of the pen is 200 metres and its length is 10 metres, calculate the width of the pen. If the total area of land is 400 square metres, what is the width of the largest possible square pen?

22 Solve Problems by Rearranging
The acceleration of an object is given by ๐‘Ž= ๐‘ฃโˆ’๐‘ข ๐‘ก , where ๐‘ฃ is the final speed, ๐‘ข is the starting speed, and ๐‘ก is the time taken to accelerate. Write this formula in terms of ๐‘ฃ. If a car accelerates from rest at 5 metres per second per second over 4 seconds, what is its final speed? The car then comes to a sudden stop at a red light, stopping in just 2 seconds. What is its acceleration? The distance travelled by the car is given by ๐‘ = ๐‘ข+๐‘ฃ 2 ร—๐‘ก. Create a formula for ๐‘  in terms of ๐‘ข, ๐‘Ž, and ๐‘ก.

23 Solve Problems by Rearranging
The first โ‚ฌ of annual income for a single person is taxed at 20%. The remainder of their annual earnings is taxed at 40%. Single people are exempt from โ‚ฌ1650 of tax per year (called their tax credit). Write a formula for the amount of tax paid by a single person each year. If a single person earns โ‚ฌ in one year, how much tax do they pay? If a single person pays โ‚ฌ2 000 in tax in one year, what was their income before tax?

24 Change the Subject of a Formula
2005 OL P1 Q3 Given that ๐‘Ž๐‘ฅ+๐‘=๐‘, express ๐‘ฅ in terms of ๐‘Ž, ๐‘ and ๐‘, where ๐‘Žโ‰ 0. 2008 OL P1 Q3 Given that ๐‘Ž ๐‘ฅ+5 =8, express ๐‘ฅ in terms of ๐‘Ž. 2002 OL P1 Q3 Express ๐‘ in terms of ๐‘Ž and ๐‘ where 8๐‘Žโˆ’5๐‘ ๐‘ =๐‘

25 Solve Exponential Equations
Pg 21 of F&T booklet Recall the rules for indices: ๐‘Ž ๐‘ ๐‘Ž ๐‘ž = ๐‘Ž ๐‘+๐‘ž ๐‘Ž ๐‘ ๐‘ž = ๐‘Ž ๐‘โˆ’๐‘ž ๐‘Ž ๐‘ ๐‘ž = ๐‘Ž ๐‘๐‘ž ๐‘Ž 0 =1 ๐‘Ž โˆ’๐‘ = 1 ๐‘Ž ๐‘ ๐‘Ž 1 ๐‘ž = ๐‘ž ๐‘Ž ๐‘Ž ๐‘ ๐‘ž = ๐‘ž ๐‘Ž ๐‘ = ๐‘ž ๐‘Ž ๐‘ ๐‘Ž๐‘ ๐‘ = ๐‘Ž ๐‘ ๐‘ ๐‘ ๐‘Ž ๐‘ ๐‘ = ๐‘Ž ๐‘ ๐‘ ๐‘ These formulas can be applied in either direction

26 Solve Exponential Equations
Exponential equations are solved in two parts: Write the equation so that each side is in index form with the same base. Write a new equation from the powers and solve. 3ร— 3 ๐‘ฅ =9 โ‡’ 3 1 ร— 3 ๐‘ฅ = 3 2 Write in index form โ‡’ 3 ๐‘ฅ+1 = 3 2 Using ๐‘Ž ๐‘ ๐‘Ž ๐‘ž = ๐‘Ž ๐‘+๐‘ž โ‡’๐‘ฅ+1=2 Set power = power โ‡’๐‘ฅ=1

27 Solve Exponential Equations
e.g. Solve 2 ๐‘ฅ+4 = 4 2๐‘ฅ โ‡’ 2 ๐‘ฅ+4 = ๐‘ฅ Using 2 2 =4 โ‡’ 2 ๐‘ฅ+4 = 2 4๐‘ฅ Using ๐‘Ž ๐‘ ๐‘ž = ๐‘Ž ๐‘๐‘ž โ‡’๐‘ฅ+4=4๐‘ฅ Set power = power โ‡’4=3๐‘ฅ โ‡’ 4 3 =๐‘ฅ

28 Solve Exponential Equations
Solve each of the following: 2 ๐‘ฅ =2 2 ๐‘ฅ+5 = 2 5 3 2๐‘ฅ+1 = 3 3 125 ๐‘ฅ =5 3 9๐‘ฅโˆ’2 =27 64 ๐‘ฅ+1 = 16 2๐‘ฅ+5 81 ๐‘˜+2 = 27 ๐‘˜+4 25 1โˆ’2๐‘ฅ = 5 4 Adapted from FHSST grade 10

29 Solve Exponential Equations
2004 OL P1 Q2 Evaluate Express in the form 2 ๐‘˜ . ๐‘˜โˆˆโ„š Solve for ๐‘ฅ the equation = 2 5โˆ’๐‘ฅ 2003 OL P1 Q2 Solve for ๐‘ฅ the equation 25 ๐‘ฅ = 5 6โˆ’๐‘ฅ 2001 OL P1 Q2 Solve each of the following equations for ๐‘ 9 ๐‘ = 1 3 2 3๐‘โˆ’7 = 2 6 โˆ’ 2 5

30 Solve Exponential Equations
2007 OL P1 Q2 Find the value of ๐‘ฅ for which 2 ๐‘ฅ+3 = 4 ๐‘ฅ . 2008 OL P1 Q2 Find the value of ๐‘ฅ for which 5 ๐‘ฅ 3 = 2009 OL P1 Q2 Find the value of Write 27 in the form 3 ๐‘˜ , where ๐‘˜โˆˆโ„•. Find the value of ๐‘ฅ for which 27ร— 3 ๐‘ฅ = 1 729


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