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Solving Multi-Step Equations

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Presentation on theme: "Solving Multi-Step Equations"β€” Presentation transcript:

1 Solving Multi-Step Equations
Lesson 6.2.4 Solving Multi-Step Equations

2 Remember These? 1. βˆ’3 π‘₯+4 2. βˆ’2π‘Žβˆ’3+4π‘Ž+8 3. βˆ’4π‘Žβˆ’3(π‘Ž+8)
Take a minute and simplify the following three expressions. 1. βˆ’3 π‘₯ βˆ’2π‘Žβˆ’3+4π‘Ž+8 3. βˆ’4π‘Žβˆ’3(π‘Ž+8) Give students a few minutes to simplify these, then review.

3

4 Prior… In previous chapters we learned how to simplify expressions using the distributive property and by combining the β€œlike terms”. So far in Chapter 6, we have been concentrating mainly on equations that can be solved in one step or in two steps like the equation 2x + 5 = 17. In this lesson we will look at solving multi-step equations. As the name suggests… there are steps you must do before you can solve the equation.

5 Steps for Solving any Equation
Distribute if you can. Then combine the like terms. Now you have a more simplified equation. Solve it by undoing in reverse. Check your answer.

6 To be successful with multi-step equations… you will have to be able to analyze the equation and decide what steps must be taken to solve it… Be on the look out for opportunities to distribute and to combine like terms when solving the equations today! Don’t work these problems. Just review the types of problems that they will be seeing today and what to look out for. Examples

7 Let’s Get Started… Section 1: Combining Like Terms Section 2: Distributive Property Section 3: Multi-Steps with Fractions.

8 πŸ•π’™ – πŸ‘π’™ – πŸ– = πŸπŸ’ πŸ’π± – πŸ– = πŸπŸ’ Step 1 Distribute
Step 2 Combine like terms Step 3 Solve by undoing in reverse. Step 4 Check Guided Practice #1 πŸ•π’™ – πŸ‘π’™ – πŸ– = πŸπŸ’ Step 1 is not needed but… on the left side of the equation I notice that I have two like terms (πŸ•π± and βˆ’πŸ‘π±). Since the variables are alike I can combine them to get πŸ’π±. πŸ’π± – πŸ– = πŸπŸ’ Make sure student is working along with you in their notes as you review this β€œanimated” problem. After I combine the terms I have a 2-step equation. To solve this equation… Undo the subtract 1st. Then undo the multiplication.

9 πŸ’π± – πŸ– = πŸπŸ’ πŸ’π± – πŸ– = πŸπŸ’ + πŸ– + πŸ– πŸ’π± = πŸ‘πŸ 24 + 8 = 32 Step 1 Distribute
Step 2 Combine like terms Step 3 Solve by undoing in reverse. Step 4 Check πŸ’π± – πŸ– = πŸπŸ’ Since this equation has – 8, I will add 8 to both sides = 32 πŸ’π± – πŸ– = πŸπŸ’ + πŸ– + πŸ– The 8’s on the left cancel out πŸ’π± = πŸ‘πŸ I am left with a 1-step equation

10 The solution that makes the statement true is x = 8
πŸ’π± = πŸ‘πŸ In this instance 4x means 4 times x. To undo the multiplication divide both sides by 4 32 ο‚Έ 4 = 8 The 4’s on the left cancel out leaving x πŸ’π± = πŸ‘πŸ πŸ’ πŸ’ 𝐱 = πŸ– The solution that makes the statement true is x = 8

11 Step 1 Distribute Step 2 Combine like terms Step 3 Solve by undoing in reverse. Step 4 Check πŸ•π± – πŸ‘π± – πŸ– = πŸπŸ’ πŸ•(πŸ–)βˆ’πŸ‘(πŸ–) – πŸ– = πŸπŸ’ πŸ“πŸ”βˆ’πŸπŸ’ – πŸ– = πŸπŸ’ πŸπŸ’= πŸπŸ’

12 You Try #1 πŸ–π±βˆ’πŸ‘π±βˆ’πŸπŸŽ = 𝟐𝟎 Answer: x = 6

13 Moving On… Section 1: Combining Like Terms Section 2: Distributive Property Section 3: Multi-Steps with Fractions.

14 5x + 3(x +4) = 28 5x + 3(x +4) = 28 5x +3x + 12 = 28 8x + 12 = 28
Step 1 Distribute Step 2 Combine like terms Step 3 Solve by undoing in reverse. Step 4 Check Guided Practice #2 5x + 3(x +4) = 28 In this instance I begin on the left side of the equation… I recognize the distributive property as 3(x+4). I must simplify that before I can do anything else. 5x + 3(x +4) = 28 5x +3x + 12 = 28 After I do the distributive property I see that I have like terms (5x and 3x) that I have to combine them to get 8x before I can solve this equation… 8x + 12 = 28

15 I am now left with a 2-step equation
Step 1 Distribute Step 2 Combine like terms Step 3 Solve by undoing in reverse. Step 4 Check 8x + 12 = 28 I am now left with a 2-step equation The left side has To undo the +12, I subtract 12 from both sides 8x + 12 = 28 28 – 12 = 16 The 12’s on the left cancel out leaving 8x 8x = 16 I am left with a 1-step equation

16 8x = 16 On the left side 8x means 8 times x. To undo the multiplication I divide both sides by 8 8x = 16 The 8’s on the left cancel out leaving x 16 ο‚Έ 8 = 2 x = 2 The solution that makes the statement true is x = 2

17 Step 1 Distribute Step 2 Combine like terms Step 3 Solve by undoing in reverse. Step 4 Check πŸ“π± + πŸ‘(𝐱 +πŸ’) = πŸπŸ– πŸ“ 𝟐 +πŸ‘(𝟐+πŸ’) = πŸπŸ– 𝟏𝟎+πŸ‘(πŸ”) = πŸπŸ– 𝟏𝟎+πŸπŸ– = πŸπŸ– πŸπŸ–= πŸπŸ–

18 You Try #2 𝟐 π±βˆ’πŸ +πŸ‘π± =πŸ‘ Answer: x = 1

19 Distributing a Negative
Distributing a negative number is similar to using the distributive property. However, students get this wrong because they forget to use the rules of integers Quickly the rules are…when multiplying, if the signs are the same the answer is positive. If the signs are different the answer is negative

20 Step 1 Distribute Step 2 Combine like terms Step 3 Solve by undoing in reverse. Step 4 Check Guided Practice #3 4x – 3(x – 2) = 21 I begin by working on the left side of the equation… In this problem I have to use the distributive property. However, the 3 in front of the parenthesis is a negative 3. When multiplying here, multiply the -3 by both terms within the parenthesis. Use the rules of integers. 4x – 3(x – 2) = 21 4x – 3x + 6 = 21 After doing the distributive property, I see that I can combine the 4x and the -3x to get 1x or x : x = 21

21 The 6’s cancel out leaving x
Step 1 Distribute Step 2 Combine like terms Step 3 Solve by undoing in reverse. Step 4 Check x = 21 After combining those like terms, you are left with a simple one step equation. To undo the +6 subtract 6 from both sides of the equation 21 – 6 = 15 x = 21 The 6’s cancel out leaving x x = 15 The solution is x = 15

22 Step 1 Distribute Step 2 Combine like terms Step 3 Solve by undoing in reverse. Step 4 Check πŸ’π’™ – πŸ‘(𝒙 – 𝟐) = 𝟐𝟏 πŸ’ πŸπŸ“ βˆ’πŸ‘(πŸπŸ“βˆ’πŸ) = 𝟐𝟏 πŸ”πŸŽβˆ’πŸ‘(πŸπŸ‘) = 𝟐𝟏 πŸ”πŸŽβˆ’πŸ‘πŸ— = 𝟐𝟏 𝟐𝟏= 𝟐𝟏

23 You Try #3 πŸ”π±βˆ’πŸ π±βˆ’πŸ“ =πŸ’πŸ” Answer: x = 9

24 Moving On… Section 1: Combining Like Terms Section 2: Distributive Property Section 3: Multi-Steps with Fractions and Decimals.

25 Clearing the Fractions
Review Step 1: Look at all of the denominators in the equation and find the LCD. Step 2: Multiply both sides of the equation by the LCD. 𝐱 𝟐 + πŸ‘ πŸ“ =πŸ‘ 𝟏𝟎 ( 𝐱 𝟐 + πŸ‘ πŸ“ )=πŸ‘ (𝟏𝟎) 10 ( 𝒙 𝟐 ) + 𝟏𝟎 ( πŸ‘ πŸ“ ) = 10(3) The LCM is the smallest number that both 2 and 5 divide into evenly. πŸ“π± + πŸ” = πŸ‘πŸŽ Fractions are gone! LCD of 2,5 =𝟏𝟎 Clearing the Fractions

26 Clearing the Decimals Review 𝟏𝟎𝟎 𝟎.πŸπŸ“π’™+𝟎.πŸ” =𝟏𝟎𝟎 𝟎.𝟏
Step 1: Look for the decimal with the most digits. Step 2: Multiply both sides of the equation by that power of 10. Decimal with the most digits. 𝟎.πŸπŸ“π’™+𝟎.πŸ”=𝟎.𝟏 𝟏𝟎𝟎 𝟎.πŸπŸ“π’™+𝟎.πŸ” =𝟏𝟎𝟎 𝟎.𝟏 Teachers… skip this slide if you have your students deal with decimals the normal way. 𝟏𝟎𝟎 𝟎.πŸπŸ“π’™ +𝟏𝟎𝟎 𝟎.πŸ” =𝟏𝟎𝟎(𝟎.𝟏) πŸπŸ“π’™+πŸ”πŸŽ = 𝟏𝟎 Decimals are gone! Clearing the Decimals

27 πŸ‘ 𝟏𝟎 𝐱+𝟐 = 𝟏𝟐 πŸ‘ 𝟏𝟎 𝐱+𝟐 =𝟏𝟐 πŸ‘ 𝟏𝟎 𝐱 + πŸ” 𝟏𝟎 =𝟏𝟐 Step 1 Distribute
Step 2 Combine like terms Step 3 Solve by undoing in reverse. Step 4 Check Guided Practice #4 πŸ‘ 𝟏𝟎 𝐱+𝟐 = 𝟏𝟐 In this example, there are actually a couple of ways that you can correctly handle the fraction… However, we are going to keep with our steps and distribute first. Then we will clear fractions. πŸ‘ 𝟏𝟎 𝐱+𝟐 =𝟏𝟐 πŸ‘ 𝟏𝟎 𝐱 + πŸ” 𝟏𝟎 =𝟏𝟐 Now we will clear these fractions.

28 πŸ‘ 𝟏𝟎 𝐱 + πŸ” 𝟏𝟎 = 𝟏𝟐 πŸ‘π±+πŸ”=𝟏𝟐𝟎 Step 1 Distribute
Step 2 Combine like terms Step 3 Solve by undoing in reverse. Step 4 Check 10 πŸ‘ 𝟏𝟎 𝐱 + πŸ” 𝟏𝟎 = 𝟏𝟐 10 10 To clear the fractions, we multiply both sides of the equation by the LCD… which is 10. The result is an equation without fractions. πŸ‘π±+πŸ”=𝟏𝟐𝟎 There are no like terms to combine. All we need to do now is to solve the 2-step equation by undoing in reverse.

29 πŸ‘π±+πŸ”=𝟏𝟐𝟎 βˆ’ πŸ” βˆ’πŸ” πŸ‘π± = πŸπŸπŸ’ πŸ‘ πŸ‘ 𝐱 =πŸ‘πŸ– Step 1 Distribute
Step 2 Combine like terms Step 3 Solve by undoing in reverse. Step 4 Check Subtract 6 from both sides πŸ‘π±+πŸ”=𝟏𝟐𝟎 βˆ’ πŸ” βˆ’πŸ” πŸ‘π± = πŸπŸπŸ’ Then divide by 3. πŸ‘ πŸ‘ 𝐱 =πŸ‘πŸ– The solution to the equation is x = 38 Let’s move on to another practice problem… but don’t forget that you should always check your solution.

30 Guided Practice #4 πŸ‘ 𝟐 πŸ‘π±+πŸ“ =βˆ’πŸπŸ’ Answer: x = -7

31 You Try #4 𝟏 πŸ’ πβˆ’πŸ‘ =βˆ’πŸπŸ“ Answer: x = -57

32 Guided Practice #5 𝟎.πŸ•πŸ“ πŸ”+𝐝 =𝟏𝟐 Answer: d = 10

33 You Try #5 𝟎.𝟐 πœβˆ’πŸ‘ =βˆ’πŸπŸŽ Answer: c = -47

34 Always More Than One Way
Take this opportunity to show students that there is always more than one way to solve a problem. Problems like this may appear on state test and students need to know how to answer it.

35 Always More Than One Way

36 Summary With multi-step equations… you have to be able to analyze the equation and decide what steps must be taken to solve it…

37 Summary Distribute if you can. Then combine the like terms.
Now you have a more simplified equation. Solve it by undoing in reverse. Check your answer. These steps can be used to solve any equation. You will not always have to do Step 1 and Step 2.

38 Summary There is always more than one way to solve a problem.
In this equation, you can distribute first if you want to, but… we learned today that you can also divide both sides by 3.


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