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Binary Lesson 6 Classful Subnetting
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Slash Notation Consider a class A address of 1.2.3.4
The network portion is the first octet 1 This situation can be written /8 The number after the / is the number of bits in the network portion 2
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Subnet Mask Consider a class A address of 1.2.3.4 /8 in binary
The subnet mask is The network address is In Binary: IP: Subnt Msk: Net Addr: 3
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AND To find the network address, take a node's IP address and do this:
If the Subnet mask bit is 1, keep the IP address bit If the Subnet mask bit is 0, that bit changes to 0 This is called a bitwise AND operation IP: Subnt Msk: Net Addr: 4
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Class B Class B address: 147.144.1.212 /16
The subnet mask is The network address is In Binary: IP: Subnt Msk: Net Addr: 5
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Class C Class C address: 192.168.1.10 /24
The subnet mask is The network address is In Binary: IP: Subnt Msk: Net Addr: 6
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192.168.1.0 /25 You can split a class C in half with a /25
IP: /25 Subnet Mask: Network: IP: Subnt Msk: Net Addr: 7
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192.168.1.0 /25 There are only 128 addresses in a /25 block
Network: /25 1st Usable: Last Usable: Broadcast: Net Addr: First Use: Last Use: Broadcast: 8
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192.168.1.128 /25 There are only 128 addresses in a /25 block
Network: /25 1st Usable: Last Usable: Broadcast: Net Addr: First Use: Last Use: Broadcast: 9
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192.168.1.0 /26 There are only 64 addresses in a /26 block
Network: /26 1st Usable: Last Usable: Broadcast: Net Addr: First Use: Last Use: Broadcast: 10
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192.168.1.64 /26 There are only 64 addresses in a /26 block
Network: /26 1st Usable: Last Usable: Broadcast: Net Addr: First Use: Last Use: Broadcast: 11
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192.168.1.128 /26 There are only 64 addresses in a /26 block
Network: /26 1st Usable: Last Usable: Broadcast: Net Addr: First Use: Last Use: Broadcast: 12
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192.168.1.192 /26 There are only 64 addresses in a /26 block
Network: /26 1st Usable: Last Usable: Broadcast: Net Addr: First Use: Last Use: Broadcast: 13
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