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Math 181 7.8 β Improper Integrals
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ββ π π π π
π = π₯π’π¦ πβββ π π π π π
π
In general, these types of improper integrals (Type I) are defined like this: π β π π π
π = π₯π’π¦ πββ π π π π π
π ββ π π π π
π = π₯π’π¦ πβββ π π π π π
π ββ β π π π
π = ββ π π π π
π + π β π π π
π
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ββ π π π π
π = π₯π’π¦ πβββ π π π π π
π
In general, these types of improper integrals (Type I) are defined like this: π β π π π
π = π₯π’π¦ πββ π π π π π
π ββ π π π π
π = π₯π’π¦ πβββ π π π π π
π ββ β π π π
π = ββ π π π π
π + π β π π π
π
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ββ π π π π
π = π₯π’π¦ πβββ π π π π π
π
In general, these types of improper integrals (Type I) are defined like this: π β π π π
π = π₯π’π¦ πββ π π π π π
π ββ π π π π
π = π₯π’π¦ πβββ π π π π π
π ββ β π π π
π = ββ π π π π
π + π β π π π
π
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In each case above, if the limit is finite, we say the improper integral __________. If the limit does not exist, the improper integral __________.
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In each case above, if the limit is finite, we say the improper integral __________. If the limit does not exist, the improper integral __________. converges
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In each case above, if the limit is finite, we say the improper integral __________. If the limit does not exist, the improper integral __________. converges diverges
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Ex 1. Does 1 β 1 π₯ ππ₯ converge or diverge?
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Ex 2. Evaluate: ββ β ππ₯ 1+ π₯ 2
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Ex 3. For what values of π does the integral 1 β ππ₯/ π₯ π converge
Ex 3. For what values of π does the integral 1 β ππ₯/ π₯ π converge? When the integral does converge, what is its value?
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1 β 1 π₯ π ππ₯ β¦ β¦converges to 1 πβ1 if π>1. β¦diverges if πβ€1.
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In general, these types of improper integrals (Type II) are defined like this: If π(π₯) continuous on π,π and discontinuous at π, then π π π π π
π = π₯π’π¦ πβ π + π π π π π
π If π(π₯) continuous on π,π and discontinuous at π, then π π π π π
π = π₯π’π¦ πβ π β π π π π π
π If π π₯ discontinuous at π, where π<π<π, and continuous on π,π βͺ π,π , then π π π π π
π = π π π(π) π
π+ π π π(π) π
π
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In general, these types of improper integrals (Type II) are defined like this: If π(π₯) continuous on π,π and discontinuous at π, then π π π π π
π = π₯π’π¦ πβ π + π π π π π
π If π(π₯) continuous on π,π and discontinuous at π, then π π π π π
π = π₯π’π¦ πβ π β π π π π π
π If π π₯ discontinuous at π, where π<π<π, and continuous on π,π βͺ π,π , then π π π π π
π = π π π(π) π
π+ π π π(π) π
π
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In general, these types of improper integrals (Type II) are defined like this: If π(π₯) continuous on π,π and discontinuous at π, then π π π π π
π = π₯π’π¦ πβ π + π π π π π
π If π(π₯) continuous on π,π and discontinuous at π, then π π π π π
π = π₯π’π¦ πβ π β π π π π π
π If π π₯ discontinuous at π, where π<π<π, and continuous on π,π βͺ π,π , then π π π π π
π = π π π(π) π
π+ π π π(π) π
π
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In each case above, if the limit is finite, we say the improper integral __________. If the limit does not exist, the improper integral __________.
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In each case above, if the limit is finite, we say the improper integral __________. If the limit does not exist, the improper integral __________. converges
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In each case above, if the limit is finite, we say the improper integral __________. If the limit does not exist, the improper integral __________. converges diverges
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Ex 4. Evaluate: βπ₯ ππ₯
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Ex 5. Evaluate: π₯β1 2/3 ππ₯
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To determine if an integral converges or diverges, you can use the Direct Comparison Test, or the Limit Comparison Test, which are described below.
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Comparison Test Suppose π and π are continuous on π,β and 0β€π π₯ β€π(π₯) in π,β . If π β π(π₯) ππ₯ converges, then π β π(π₯) ππ₯ converges. If π β π(π₯) ππ₯ diverges, then π β π(π₯) ππ₯ diverges.
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Ex 6. Does 1 β sin 2 π₯ π₯ 2 ππ₯ converge or diverge?
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Ex 7. Does 1 β 1 π₯ 2 β0.1 ππ₯ converge or diverge?
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