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Significant models of claim number Introduction

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1 Significant models of claim number Introduction
Before we meet with complex risk model it can be useful to meet the most significant models of claim number. In this chapter we will sign with ฮท the number of claim during one pre-defined period (typically one year). The risk can be a contract, a business line or a product. Of course ฮท is a non-negative variate with integer value. We will consider the most useful models. Insurance mathematics VIII. lecture

2 Significant models of claim number (a,b,0) class of distributions I.
The most useable models are the so-called (a,b,0) class of distributions. Definition: ฮท is (a,b,0) class of distribution if ๐‘ƒ ฮท=๐‘› =(๐‘Ž+ ๐‘ ๐‘› )โˆ™๐‘ƒ ฮท=๐‘›โˆ’1 ; n=1,2,โ€ฆ As we will see later in this case the total amount of claims can be calculated exactly and in the most practical cases the real number of claims can be reached with this class of distribution. We have known from earlier this class as it follows from the next statement. Insurance mathematics VIII. lecture

3 Significant models of claim number (a,b,0) class of distributions II.
Statement: ฮท has (a,b,0) class of distribution if and only if either is true in the next 4 cases: (i) ๐‘ƒ ฮท=๐‘› = 1, ๐‘–๐‘“ ๐‘›=0 0, ๐‘–๐‘“ ๐‘›>0 (ii) ๐‘ƒ ฮท=๐‘› = ฮป ๐‘› ๐‘›! โˆ™ ๐‘’ โˆ’ฮป ;ฮป>0 (iii) ๐‘ƒ ฮท=๐‘› = ๐›ผ+๐‘›โˆ’1 ๐‘› โˆ™ ๐‘ ๐‘› โˆ™ 1โˆ’๐‘ ๐›ผ ; ๐›ผ>0;0<๐‘<1 (iv) ๐‘ƒ ฮท=๐‘› = ๐‘ ๐‘› โˆ™ ๐‘ ๐‘› โˆ™ 1โˆ’๐‘ ๐‘โˆ’๐‘› ; 0<๐‘<1;๐‘=1,2,โ€ฆ Insurance mathematics VIII. lecture

4 Significant models of claim number (a,b,0) class of distributions III.
Proof: If a+b<0 then ๐‘ƒ ฮท=0 and ๐‘ƒ ฮท=1 would have different signs, which is impossible (because of ๐‘ƒ ฮท=1 =(๐‘Ž+๐‘)โˆ™๐‘ƒ ฮท=0 ). If a+b=0 then ๐‘ƒ ฮท=1 = ๐‘Ž+๐‘ โˆ™๐‘ƒ ฮท=0 =0 and it follows ๐‘ƒ ฮท=๐‘› =0;๐‘›โ‰ฅ1. It means that ๐‘ƒ ฮท=0 has to be equal 1 (because ฮท is distribution). We get (i) case. ฮท is a distribution, it means: 1= ๐‘›=0 โˆž ๐‘ƒ ฮท=๐‘› =๐‘ƒ ฮท=0 โˆ™ ๐‘›=0 โˆž ๐‘ ๐‘› ๐‘›! = ๐‘ƒ ฮท=0 โˆ™ ๐‘’ ๐‘ ๐‘ƒ ฮท=0 = ๐‘’ โˆ’๐‘ ฮท is Poisson with b parameter, (ii) case. If a+b>0 and if a=0 then ๐‘ƒ ฮท=๐‘› = ๐‘ ๐‘› โˆ™๐‘ƒ ฮท=๐‘›โˆ’1 = ๐‘ ๐‘› โˆ™ ๐‘ ๐‘›โˆ’1 โˆ™๐‘ƒ ฮท=๐‘›โˆ’2 =โ€ฆ= ๐‘ ๐‘› ๐‘›! โˆ™๐‘ƒ(ฮท=0) Insurance mathematics VIII. lecture

5 Significant models of claim number (a,b,0) class of distributions IV.
Proof (continued): If a+b>0 and if a>0 then we sign ๐›ผ=1+ ๐‘ ๐‘Ž . With this notation we get ๐‘ƒ ฮท=๐‘› =(๐‘Ž+ ๐‘ ๐‘› )โˆ™๐‘ƒ ฮท=๐‘›โˆ’1 = 1+ ๐‘ ๐‘Ž +๐‘›โˆ’1 ๐‘› โˆ™๐‘Žโˆ™๐‘ƒ ฮท=๐‘›โˆ’1 = = ๐›ผ+๐‘›โˆ’1 ๐‘› โˆ™๐‘Žโˆ™๐‘ƒ ฮท=๐‘›โˆ’1 =โ€ฆ=๐‘ƒ(ฮท=0)โˆ™ ๐›ผ+๐‘›โˆ’1 ๐‘› โˆ™ ๐‘Ž ๐‘› In order that ๐‘›=1 โˆž ๐‘ƒ ฮท=๐‘› <1 we must have a<1. Then we get the negative binomial distribution with p=a, (iii) case. You might have noticed: ๐‘ƒ ฮท=0 = (1โˆ’๐‘Ž) ๐›ผ Insurance mathematics VIII. lecture

6 Significant models of claim number (a,b,0) class of distributions V.
Proof (continued): If a+b>0 and if a<0 then b>-a. It means that there are such K integer for which ๐‘Ž+ ๐‘ ๐‘› <0 โˆ€๐‘›>๐พ This is just only if can be true (because of avoiding negative probability) if ฦŽK for which ๐‘Ž+ ๐‘ ๐พ =0 Then let ๐‘=๐พโˆ’1 and ๐‘=โˆ’ ๐‘Ž 1โˆ’๐‘Ž , we will get the (iv) case. Insurance mathematics VIII. lecture

7 Significant models of claim number (a,b,0) class of distributions VI.
For these types the Poisson distribution the most applied distribution. The binomial distribution can be used naturally if related to one contract it can be just 0 or 1 claim. Regarding negative binomial distribution we can consider the next example: We assume that distribution of ฮท with fixed ฮฝ is Poisson distribution with ฮฝโˆ™๐‘ก parameter. It means that the conditional probability-generating function will be as next: ๐บ ฮท ฮฝ ๐‘ง =๐ธ ๐‘ง ฮท ฮฝ = ๐‘’ ฮฝโˆ™๐‘กโˆ™(๐‘งโˆ’1) From these equation we will get probability-generating function of ฮท as follows (based on law of total expectation): ๐บ ฮท ๐‘ง =๐ธ(๐ธ ๐‘ง ฮท ฮฝ )= ๐ธ(๐‘’ ๐œˆโˆ™๐‘กโˆ™ ๐‘งโˆ’1 )= ๐ฟ ฮฝ (๐‘กโˆ™(1โˆ’๐‘ง)) If ฮฝ is Gamma distribution with (ฮป,ฮฑ) parameters then its Laplace-transform is as next: ๐ฟ ฮฝ ๐‘  = ( ฮป ฮป+๐‘  ) ฮฑ Insurance mathematics VIII. lecture

8 Significant models of claim number (a,b,0) class of distributions VII.
Then we get: ๐บ ฮท ๐‘ง = ( ฮป ฮป+๐‘กโˆ™(1โˆ’๐‘ง) ) ฮฑ = (1โˆ’ ๐‘ก ฮป โˆ™(๐‘งโˆ’1)) โˆ’ฮฑ which is probability-generating function of negative binomial distribution with (๐›ผ, ๐‘ก ๐‘ก+ฮป ) parameters. It means that the negative binomial distribution is mixed Poisson distribution (the mixer variate is Gamma distribution). Memo: ฮท has mixed Poisson distribution if โˆƒ๐œ mixer variate for which the conditional distribution of ฮท with ๐œ condition is Poisson distribution with ๐œ parameter. Insurance mathematics VIII. lecture

9 Insurance mathematics VIII. lecture
Significant models of claim number (a,b,0) class of distributions VIII. Definition: ฮท is compound Poisson distribution, if ฮท= ๐‘€ 1 + ๐‘€ 2 +โ€ฆ+ ๐‘€ ๐‘ where N is Poisson distribution, ๐‘€ 1 , ๐‘€ 2 ,โ€ฆ, ๐‘€ ๐‘ are independent, identic distribution. Statement: Negative binomial distribution can be compound Poisson distribution. Insurance mathematics VIII. lecture

10 Significant models of claim number (a,b,0) class of distributions IX.
Proof: Let ๐‘€ ๐‘— the number of claim related to one claim event. We suppose that ๐‘€ ๐‘— is logarithmic distribution. It means that its probability-generating function will be as follows: ๐บ ๐‘€ ๐‘— ๐‘ง = lnโก(1โˆ’๐‘žโˆ™๐‘ง) lnโก(1โˆ’๐‘ž) If the number of claims (N) is Poisson distribution then the total claim number, ฮท= ๐‘€ 1 + ๐‘€ 2 +โ€ฆ+ ๐‘€ ๐‘ will be compound Poisson distribution. Probability-generating distribution of ฮท will be the next: ๐บ ฮท ๐‘ง =E ๐‘ง ๐‘› =๐ธ ๐ธ ๐‘ง ๐‘› ๐‘ =๐ธ (๐บ ๐‘€ ๐‘— ๐‘ง ) ๐‘ = ๐บ ๐‘ ๐บ ๐‘€ ๐‘— ๐‘ง = =exp(ฮปโˆ™ ๐บ ๐‘€ ๐‘— ๐‘ง โˆ’1 = exp ฮปโˆ™ ln 1โˆ’๐‘žโˆ™๐‘ง ln 1โˆ’๐‘ž โˆ’1 =( 1โˆ’๐‘žโˆ™๐‘ง 1โˆ’๐‘ž ) ฮป lnโก(1โˆ’๐‘ž) Insurance mathematics VIII. lecture

11 Significant models of claim number (a,b,0) class of distributions X.
Proof (continued): ๐บ ฮท ๐‘ง = (1โˆ’ ๐‘ž 1โˆ’๐‘ž ๐‘งโˆ’1 ) โˆ’(โˆ’ ฮป lnโก(1โˆ’๐‘ž) ) It means that ฮท is negative binomial distribution with (โˆ’ ฮป ln 1โˆ’๐‘ž ,๐‘ž) parameters. Insurance mathematics VIII. lecture

12 Significant models of claim number Other models I.
The other models which can be used as claim number can come from the next families: - generalizing (a,b,0) class of distributions; - compound distributions; - mixed distributions. Definition: ฮท is (a,b) class of distribution if ๐‘ƒ ฮท=๐‘› =(๐‘Ž+ ๐‘ ๐‘› )โˆ™๐‘ƒ ฮท=๐‘›โˆ’1 ; n=2,3,โ€ฆ It seems that there is just a small difference between (a,b,0) and (a,b) classes (we do not require the equation in case of n=1), the real difference is significant. Insurance mathematics VIII. lecture

13 Significant models of claim number Other models II.
Definition: ฮท is (a,b,1) class of distribution if ๐‘ƒ ฮท=๐‘› =(๐‘Ž+ ๐‘ ๐‘› )โˆ™๐‘ƒ ฮท=๐‘›โˆ’1 ; n=2,3,โ€ฆ and ๐‘ƒ ฮท=0 =0 It is affirmable if ฮท is (a,b) distribution then โˆƒ๐›ผ>0 and ฯ„ (a,b,0) or (a,b,1) distribution for which: ๐‘ƒ ฮท=0 =1โˆ’๐›ผ+๐›ผโˆ™๐‘ƒ ฯ„=0 ๐‘ƒ ฮท=๐‘› =๐›ผโˆ™๐‘ƒ ฯ„=๐‘› ;n>0 Insurance mathematics VIII. lecture

14 Significant models of claim number Other models III.
Compound distributions: - compound Poisson - compound geometric If ฮท is compound Poisson then its probability-generating function is as next: ๐บ ฮท ๐‘ง = exp ฮปโˆ™ ๐บ ๐‘€ ๐‘ง โˆ’1 where ๐บ ๐‘€ ๐‘ง is a probability-generating function of non-negative variate (with integer value). The two most important version will be the next: Definition: ฮท is Poisson-binomial distribution if its probability-generating function is the following: ๐บ ฮท ๐‘ง = exp ฮปโˆ™ (1+๐‘โˆ™ ๐‘งโˆ’1 ) ๐‘š โˆ’1 Insurance mathematics VIII. lecture

15 Significant models of claim number Other models IV.
Definition: ฮท is Neymanโ€™s type A distribution if its probability-generating function is the following: ๐บ ฮท ๐‘ง = exp ฮป 1 โˆ™ exp ฮป 2 โˆ™ ๐‘งโˆ’1 โˆ’1 We will consider the two most important compound geometric distributions also as follows. ฮท is geometric-geometric distribution if its probability-generating function is the following: ๐บ ฮท ๐‘ง = (1โˆ’ ๐›ฝ 1 โˆ™ 1 1โˆ’ ๐›ฝ 2 โˆ™ ๐‘งโˆ’1 โˆ’1 ) โˆ’1 Insurance mathematics VIII. lecture

16 Significant models of claim number Other models V.
Definition: ฮท is geometric-Poisson distribution if its probability-generating function is the following: ๐บ ฮท ๐‘ง = (1โˆ’๐›ฝโˆ™ exp ฮปโˆ™ ๐‘งโˆ’1 โˆ’1 ) โˆ’1 Mixed distributions Because of law of total expectation and law of total variance: E ฮท =๐ธ ๐ธ ฮท ฯ„ and ๐ท 2 ฮท = ๐ท 2 ๐ธ ฮท ฯ„ +๐ธ ๐ท 2 ฮท ฯ„ From these equation we will get the following in case of mixed Poisson distribution: E ฮท =ฮปโˆ™E(ฯ„) ๐ท 2 ฮท = ฮป 2 โˆ™๐ท 2 ฯ„ +ฮปโˆ™๐ธ ฯ„ Insurance mathematics VIII. lecture

17 Significant models of claim number Other models VI.
Definition: ฮท distribution is indefinitely divisible if โˆ€๐‘›โˆˆ๐‘ ฮท is a convolution of n identic distribution. Statement: We assume that ฮท distribution is such mixed Poisson distribution for which the mixer distribution is indefinitely divisible. Then ฮท is compound Poisson distribution. Insurance mathematics VIII. lecture

18 Significant models of claim number Other models VII.
Proof: We sign L the Laplace-transform of mixer distribution. Because of indefinitely divisible property ๐ฟ ๐‘› = ๐‘› ๐ฟ is Laplace-transform. We know from earlier that the probability-generating function of mixed Poisson distribution is as follows: ๐บ ฮท ๐‘ง =๐ฟ ฮปโˆ™ 1โˆ’๐‘ง = ( ๐ฟ ๐‘› ฮปโˆ™ 1โˆ’๐‘ง ) ๐‘› = ๐บ ๐‘› (๐‘ง) ๐‘› Because of ๐บ ๐‘› (๐‘ง) is a probability-generating function of a mixed Poisson distribution and the above formula can be written for each n, ฮท is indefinitely divisible. And if ฮท is indefinitely divisible, nonnegative with integer value then ฮท is compound Poisson distribution. Insurance mathematics VIII. lecture

19 Insurance mathematics VIII. lecture
Significant models of claim number Identification of distribution of claim number I. We assume that a database exists from which there is clear which contract has how many claims event. (In the practice there is not so easy because the starting date and the duration would be different. We assume that the collection of data and the systematization happened.) When we would like to identify the distribution of claim number at first we can try (a,b,0) class of distribution. What we know: Poisson, binomial or negative binomial; if we sign ๐‘ ๐‘› =๐‘ƒ ฮท=๐‘› then let ๐‘ž ๐‘› = ๐‘›+1 โˆ™ ๐‘ ๐‘›+1 ๐‘ ๐‘› =๐‘Ž+๐‘+๐‘›โˆ™๐‘Ž If the distribution is Poisson then ๐ท 2 ฮท =๐ธ ฮท and ๐‘Ž=0, it means ๐‘ž ๐‘› =๐‘๐‘ ๐‘ก. If the distribution is binomial then ๐ท 2 ฮท <๐ธ ฮท and ๐‘Ž<0, it means ๐‘ž ๐‘› is decreasing linear. Insurance mathematics VIII. lecture

20 Insurance mathematics VIII. lecture
Significant models of claim number Identification of distribution of claim number II. If the distribution is negative binomial then ๐ท 2 ฮท >๐ธ ฮท and ๐‘Ž>0, it means ๐‘ž ๐‘› is increasing linear. Because of above remarks our process will be as next: We sign ๐‘ˆ ๐‘– the number of such contracts which have exactly i claims. Let K is the number of contracts, and the maximum number of claim is j. Then the r-th empiric momentum will be as follows: ๐‘€ ๐‘Ÿ = 1 ๐พ ๐‘–=0 ๐‘— ๐‘– ๐‘Ÿ โˆ™ ๐‘ˆ ๐‘– The empiric variance will be the next: ๐‘† 2 = ๐‘€ 2 โˆ’ ๐‘€ 1 2 Let ๐‘‡ ๐‘› =(๐‘›+1)โˆ™ ๐‘ˆ ๐‘›+1 ๐‘ˆ ๐‘› . Insurance mathematics VIII. lecture

21 Insurance mathematics VIII. lecture
Significant models of claim number Identification of distribution of claim number III. If ๐‘† 2 โ‰ˆ ๐‘€ 1 and ๐‘‡ ๐‘› โ‰ˆ๐‘๐‘ ๐‘ก then the distribution of claim number will be approximated with Poisson distribution. If ๐‘† 2 < ๐‘€ 1 and ๐‘‡ ๐‘› is decreasing then the distribution of claim number will be approximated with binomial distribution. If ๐‘† 2 > ๐‘€ 1 and ๐‘‡ ๐‘› is increasing then the distribution of claim number will be approximated with negative binomial distribution. But there is insecure that the distribution of claim number comes from (a,b,0)-class of distribution. For example if we find that ๐‘‡ ๐‘› is changing faster than linear then it can be useful to calculate third empiric momentum. Let ฮบ= ๐‘€ 3 โˆ’3 ๐‘€ 2 ๐‘€ 1 +2 ๐‘€ 1 3 If ฮท is negative binomial distribution then its third momentum is 3 ๐ท 2 ฮท โˆ’2๐ธ ฮท + 2( ๐ท 2 ฮท โˆ’๐ธ ฮท ) 2 ๐ธ ฮท Insurance mathematics VIII. lecture

22 Insurance mathematics VIII. lecture
Significant models of claim number Identification of distribution of claim number IV. It means that we have to compare ฮบ with 3 ๐‘† 2 โˆ’2 ๐‘€ 1 + 2( ๐‘† 2 โˆ’ ๐‘€ 1 ) 2 ๐‘€ 1 . If there are similar we can accept negative binomial distribution. If ฮบ is much more then we are using Neymanโ€™s type A distribution or Poisson-geometric distribution. If ฮบ is much less then we can try divers mixed distribution. Neymanโ€™s type A distribution or Poisson-geometric distribution. After determination of distribution type we can calculate estimation of parameters. Insurance mathematics VIII. lecture

23 Significant models of claim number Estimating the parameters I.
Example (the method of moments): Let ฮท 1 , ฮท 2 ,โ€ฆ, ฮท ๐พ independent NB(r,q) data sample. It means that ๐‘ƒ ฮท ๐‘– =๐‘›+๐‘Ÿ = ๐‘›+๐‘Ÿโˆ’1 ๐‘Ÿโˆ’1 โˆ™ 1โˆ’๐‘ž ๐‘Ÿ โˆ™ ๐‘ž ๐‘› ;๐‘›=0,1,โ€ฆ ๐ธ ฮท = ๐‘Ÿ 1โˆ’๐‘ž ; ๐ท 2 ฮท = ๐‘Ÿ๐‘ž (1โˆ’๐‘ž) 2 From above equations we will get the following equation system: ๐‘€ 1 = ๐‘Ÿ 1โˆ’๐‘ž ; ๐‘† 2 = ๐‘Ÿ๐‘ž (1โˆ’๐‘ž) 2 Insurance mathematics VIII. lecture

24 Significant models of claim number Estimating the parameters II.
Example continued: From the solution of the equation system we will get the estimation of parameters: ๐‘ž = ๐‘† 2 ๐‘† 2 + ๐‘€ 1 ; ๐‘Ÿ = ๐‘€ 1 (1โˆ’๐‘ž)= ๐‘€ 1 ๐‘† 2 ๐‘† 2 + ๐‘€ 1 We can use maximum likelihood estimation also. The likelihood function will be as next: ๐ฟ ๐‘Ÿ,๐‘ž = ๐‘ƒ ๐‘Ÿ,๐‘ž ฮท 1 = ๐‘› 1 , ฮท 2 = ๐‘› 2 ,โ€ฆ ฮท ๐พ = ๐‘› ๐พ = ๐‘–=1 ๐พ ฮ“(๐‘Ÿ+ ๐‘› ๐‘– ) ฮ“(๐‘Ÿ)โˆ™ ๐‘› ๐‘– ! โˆ™ 1โˆ’๐‘ž ๐‘Ÿ โˆ™ ๐‘ž ๐‘› ๐‘– Insurance mathematics VIII. lecture

25 Significant models of claim number Estimating the parameters III.
Example continued: The log likelihood function will be as follows: ๐‘™ ๐‘Ÿ,๐‘ž =๐‘™๐‘›๐ฟ ๐‘Ÿ,๐‘ž =๐‘Ÿ๐พ๐‘™๐‘› 1โˆ’๐‘ž +๐‘™๐‘›๐‘žโˆ™ ๐‘–=1 ๐พ ๐‘› ๐‘– + ๐‘–=1 ๐พ ๐‘š=0 ๐‘› ๐‘– โˆ’1 ln ๐‘Ÿ+๐‘š โˆ’ ๐‘–=1 ๐พ ๐‘™๐‘› ๐‘› ๐‘– ! After derivation we will get the likelihood equations: ๐œ•๐‘™ ๐œ•๐‘ž =โˆ’๐‘Ÿ๐พ 1 1โˆ’๐‘ž + 1 ๐‘ž โˆ™ ๐‘–=1 ๐พ ๐‘› ๐‘– =0 ๐œ•๐‘™ ๐œ•๐‘Ÿ =๐พ๐‘™๐‘› 1โˆ’๐‘ž + ๐‘–=1 ๐พ ๐‘š=0 ๐‘› ๐‘– โˆ’1 1 ๐‘Ÿ+๐‘š =0 Insurance mathematics VIII. lecture

26 Significant models of claim number Estimating the parameters IV.
Example continued: From this equation system we will get the next: ๐‘Ÿ 1โˆ’๐‘ž = ๐‘€ 1 ln 1โˆ’๐‘ž = 1 ๐พ ๐‘–=1 ๐พ ๐‘š=0 ๐‘› ๐‘– โˆ’1 1 ๐‘Ÿ+๐‘š It can be approved that if ๐‘† 2 >๐‘€ 1 then there exists unique solution of above equation system. Insurance mathematics VIII. lecture

27 Significant models of claim number Remarks
It can be a lot of changes related to property of claim number thatโ€™s why these process has to be repeated year by year. Some possibilities regarding changes as follows: There is a trend in claim frequency (for example mortality changes, motorization changes, etc.) Periodicity with short period (for example yearly climate changes). Periodicity with long period (because of changes of financial environment). Simple occasional fluctuation. Insurance mathematics VIII. lecture


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