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HKN ECE 210 Exam 3 Review Session

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1 HKN ECE 210 Exam 3 Review Session
Corey Snyder Grant Greenberg

2 Topics Fourier Transform Signal Energy and Bandwidth
LTI System Response with Fourier Transform Modulation, AM, Coherent Demodulation Impulse Response and Convolution Sampling and Analog Reconstruction LTIC and BIBO Stability

3 Fourier Transform The Fourier Transform of a signal shows the frequency content of that signal In other words, we can see how much energy is contained at each frequency for that signal This is a big deal! This is the biggest deal! 𝐹 πœ” = βˆ’βˆž ∞ 𝑓 𝑑 𝑒 βˆ’π‘—πœ”π‘‘ 𝑑𝑑 𝑓 𝑑 = 1 2πœ‹ βˆ’βˆž ∞ 𝐹 πœ” 𝑒 π‘—πœ”π‘‘ π‘‘πœ”

4 Important Signals for Fourier Transform
π‘Ÿπ‘’π‘π‘‘ 𝑑 𝑇 = 1, π‘“π‘œπ‘Ÿ 𝑑 < 𝑇 2 0, π‘“π‘œπ‘Ÿ 𝑑 > 𝑇 2 𝑒 𝑑 = 0, π‘“π‘œπ‘Ÿ 𝑑<0 1, π‘“π‘œπ‘Ÿ 𝑑>0 Ξ” 𝑑 𝑇 = 1+ 2𝑑 𝑇 , π‘“π‘œπ‘Ÿ βˆ’π‘‡ 2 <𝑑<0 1 βˆ’ 2𝑑 𝑇 , π‘“π‘œπ‘Ÿ 0<𝑑< 𝑇 2 𝑠𝑖𝑛𝑐 𝑑 = sin 𝑑 𝑑 , π‘“π‘œπ‘Ÿ 𝑑≠0 1, π‘“π‘œπ‘Ÿ 𝑑=0

5 Fourier Transform Tips
Convolution in the time domain is multiplication in the frequency domain 𝑓 𝑑 βˆ—π‘” 𝑑 β„± 𝐹 πœ” 𝐺(πœ”) Conversely, multiplication in the time domain is convolution in the frequency domain 𝑓 𝑑 𝑔 𝑑 β„± 1 2πœ‹ 𝐹 πœ” βˆ—πΊ(πœ”) Scaling your signal can force properties to appear; typically time delay Ex: 𝑒 βˆ’2 𝑑+1 𝑒 π‘‘βˆ’1 β†’ 𝑒 βˆ’4 𝑒 βˆ’2 π‘‘βˆ’1 𝑒(π‘‘βˆ’1) The properties really do matter! Take the time to acquaint yourself with them. Remember that the Fourier Transform is linear, so you can express a spectrum as the sum of easier spectra Ex: Staircase function Magnitude Spectrum is even symmetric, Phase Spectrum is odd symmetric for real valued signals

6 Signal Energy and Bandwidth
πΈπ‘›π‘’π‘Ÿπ‘”π‘¦=π‘Š= βˆ’βˆž ∞ 𝑓 𝑑 2 𝑑𝑑= 1 2πœ‹ βˆ’βˆž ∞ 𝐹 πœ” 2 π‘‘πœ” Energy signals can be either low-pass or band-pass signals Why not high-pass? Bandwidth for Low-pass Signals 3dB BW 𝐹 Ξ© 𝐹 = 1 2 r% BW 1 2πœ‹ βˆ’Ξ© Ξ© 𝐹 πœ” 2 π‘‘πœ”=π‘Ÿπ‘Š Bandwidth for Band-pass signals 1 2πœ‹ πœ” 𝑙 πœ” 𝑒 𝐹 πœ” 2 π‘‘πœ”= π‘Ÿπ‘Š 2 , Ξ©= πœ” 𝑒 βˆ’ πœ” 𝑙

7 LTI System Response using Fourier Transform
Given the following LTI system: 𝑓 𝑑 β†’ →𝑦(𝑑) π‘Œ πœ” =𝐹 πœ” 𝐻(πœ”) Computationally speaking, and in future courses, we prefer to use Fourier Transforms instead of convolution to evaluate an LTI system Why? So much faster: 𝑂 π‘›π‘™π‘œπ‘”π‘› 𝑣𝑠. 𝑂( 𝑛 2 ) 𝐻(πœ”)

8 Modulation, AM Radio, Coherent Demodulation
Modulation Property 𝑓 𝑑 ↔𝐹 πœ” , 𝑓 𝑑 cos πœ” π‘œ 𝑑 ↔ 1 2 [𝐹 πœ”βˆ’ πœ” π‘œ +𝐹 πœ”+ πœ” π‘œ ] In general, for Amplitude Modulation in communications, we modulate with cosine in order to shift our frequency spectrum into different frequency bands Coherent Demodulation refers to the process of modulating a signal in order to make it band-pass, then modulating it back to the original low-pass baseband before low-pass filtering in order to recover the original signal Envelope detection is the process of Full-wave Rectification (absolute value), then low-pass filtering in order to extract the signal

9 Impulse Response and Convolution
π‘₯ 𝑑 βˆ—π‘¦ 𝑑 = βˆ’βˆž ∞ π‘₯ 𝜏 𝑦 π‘‘βˆ’πœ π‘‘πœ= βˆ’βˆž ∞ π‘₯ π‘‘βˆ’πœ 𝑦 𝜏 π‘‘πœ We β€œflip and shift” one signal and evaluate the integral of the product of the two signals at any value of t (our delay for the shift) Representing LTI Systems 𝑦 𝑑 =π‘₯ 𝑑 βˆ—β„Ž 𝑑 , π‘€β„Žπ‘’π‘Ÿπ‘’ β„Ž 𝑑 𝑖𝑠 π‘‘β„Žπ‘’ π’Šπ’Žπ’‘π’–π’π’”π’† 𝒓𝒆𝒔𝒑𝒐𝒏𝒔𝒆 π‘œπ‘“ π‘‘β„Žπ‘’ π‘ π‘¦π‘ π‘‘π‘’π‘š Impulse Response is the system output to a 𝛿 𝑑 input Graphical convolution helps to visualize the process of flipping and shifting

10 Helpful Properties for Convolution
Derivative β„Ž 𝑑 βˆ—π‘“ 𝑑 =𝑦 𝑑 β†’ 𝑑 𝑑𝑑 β„Ž 𝑑 βˆ—π‘“ 𝑑 =β„Ž 𝑑 βˆ— 𝑑 𝑑𝑑 𝑓 𝑑 = 𝑑 𝑑𝑑 𝑦(𝑑) Use of Derivative property: Finding the impulse response from the unit-step response 𝐼𝑓 𝑦 𝑑 =𝑒 𝑑 βˆ—β„Ž 𝑑 , π‘‘β„Žπ‘’π‘› 𝑑 𝑑𝑑 𝑦 𝑑 = 𝑑 𝑑𝑑 𝑒 𝑑 βˆ—β„Ž 𝑑 =𝛿 𝑑 βˆ—β„Ž 𝑑 =β„Ž(𝑑) Start Point If the two signals have start points at 𝑑 1 π‘Žπ‘›π‘‘ 𝑑 2 , then the start point of their convolution will be at 𝑑 1 + 𝑑 2 End Point Similarly for the end points, if the two signals have end points at 𝑑 1 π‘Žπ‘›π‘‘ 𝑑 2 , then the end point of their convolution will be at 𝑑 1 + 𝑑 2 Width From the above two properties, we can see that if the two signals have widths π‘Š 1 and π‘Š 2 , then the width of their convolution will be π‘Š 1 + π‘Š 2

11 The Impulse Function 𝜹(𝒕)
The impulse function is the limit of 1 𝑇 π‘Ÿπ‘’π‘π‘‘ 𝑑 𝑇 π‘Žπ‘  𝑇→0 Infinitesimal Width Infinite Height Of course, it integrates to 1. (0βˆ—βˆž=1) Sifting π‘Ž 𝑏 𝛿 π‘‘βˆ’ 𝑑 π‘œ 𝑓 𝑑 𝑑𝑑= 𝑓 𝑑 0 , 𝑑 0 ∈[π‘Ž,𝑏] 0, 𝑒𝑙𝑠𝑒 Sampling 𝑓 𝑑 𝛿 π‘‘βˆ’ 𝑑 π‘œ =𝑓 𝑑 π‘œ 𝛿(π‘‘βˆ’ 𝑑 π‘œ ) Unit-step derivative 𝑑𝑒 𝑑𝑑 =𝛿(𝑑)

12 Sampling and Analog Reconstruction
If we have an original analog signal 𝑓(𝑑) Our digital samples of the signal are obtained through sampling property as: 𝑓 𝑛 =𝑓 𝑛𝑇 where T is our sampling period; this is Analog to Digital (A/D) conversion We must make sure to satisfy Nyquist Criterion: 𝑇< 1 2𝐡 π‘œπ‘Ÿ 𝑓 𝑠 >2𝐡, 𝐡= π΅π‘Žπ‘›π‘‘π‘€π‘–π‘‘π‘‘β„Ž (in Hz) To learn more about Nyquist Criterion and Sampling take ECE 110!

13 Sampling and Analog Reconstruction
If we have an original analog signal 𝑓(𝑑) Our digital samples of the signal are obtained through sampling property as: 𝑓 𝑛 =𝑓 𝑛𝑇 where T is our sampling period; this is Analog to Digital (A/D) conversion We must make sure to satisfy Nyquist Criterion: 𝑇< 1 2𝐡 π‘œπ‘Ÿ 𝑓 𝑠 >2𝐡, 𝐡= π΅π‘Žπ‘›π‘‘π‘€π‘–π‘‘π‘‘β„Ž (in Hz) To learn more about Nyquist Criterion and Sampling take ECE 110! Just kidding, take ECE 310

14 Sampling and Analog Reconstruction
If we have an original analog signal 𝑓(𝑑) Our digital samples of the signal are obtained through sampling property as: 𝑓 𝑛 =𝑓 𝑛𝑇 where T is our sampling period; this is Analog to Digital (A/D) conversion This results in infinitely many copies of the original signal’s Fourier Transform spaced by 2πœ‹ 𝑇 We must make sure to satisfy Nyquist Criterion: 𝑇< 1 2𝐡 π‘œπ‘Ÿ 𝑓 𝑠 >2𝐡, 𝐡= π΅π‘Žπ‘›π‘‘π‘€π‘–π‘‘π‘‘β„Ž (in Hz) To learn more about Nyquist Criterion take ECE 110! Just kidding, take ECE 310 Following A/D conversion, we perform D/A conversion, then low-pass filter our signal in order to obtain our original signal according to the following relation 𝑓 𝑑 = 𝑛 𝑓 𝑛 𝑠𝑖𝑛𝑐 πœ‹ 𝑇 π‘‘βˆ’π‘›π‘‡ For a more complete explanation, take ECE 310!

15 Sampling and Analog Reconstruction (cont’d)
The complete mathematical relationship between the continuous frequency spectrum and the discrete time (sampled) spectrum in analog frequency 𝐹 𝑠 πœ” = 1 𝑇 π‘˜=βˆ’βˆž ∞ 𝐹 πœ”+ 2πœ‹π‘˜ 𝑇 The nuances of this representation will be explored and clarified in ECE 310!

16 BIBO Stability A system is BIBO stable if for any bounded input, we obtain a bounded output Two ways to check BIBO stability By the definition: 𝐼𝑓 𝑓 𝑑 ≀𝛼<∞, π‘‘β„Žπ‘’π‘› 𝑦 𝑑 ≀𝛽<∞, βˆ€ 𝑑 By Absolute Integrability βˆ’βˆž ∞ β„Ž 𝑑 𝑑𝑑<∞

17 LTIC LTIC stands for Linearity Time-Invariance and Causality Linearity
Satisfy Homogeneity and Additivity Can be summarized by Superposition If π‘₯ 1 (𝑑)β†’ 𝑦 1 (𝑑) π‘Žπ‘›π‘‘ π‘₯ 2 (𝑑)β†’ 𝑦 2 (𝑑), π‘‘β„Žπ‘’π‘› π‘Ž π‘₯ 1 (𝑑)+𝑏 π‘₯ 2 (𝑑)β†’π‘Ž 𝑦 1 (𝑑)+𝑏 𝑦 2 (𝑑) Shift Invariance If π‘₯(𝑑)→𝑦(𝑑) π‘‘β„Žπ‘’π‘› π‘₯(π‘‘βˆ’ 𝑑 π‘œ )→𝑦(π‘‘βˆ’ 𝑑 π‘œ ) βˆ€ 𝑑 0 π‘Žπ‘›π‘‘ π‘₯(𝑑) Causality Output cannot depend on future input values β„Ž 𝑛 =0 for 𝑛<0.

18 Problem 1 SP16 Consider a real-valued function 𝑓(𝑑) with bandwidth Ξ© and let πœ” 𝑐 >Ξ©. Obtain the bandwidth of the following functions All answers may be left in terms of Ξ© and πœ” 𝑐 . (a) 𝑔 1 𝑑 =𝑓 𝑑 sin πœ” 𝑐 𝑑 (b) 𝑔 2 𝑑 =𝑓 𝑑 + sin πœ” 𝑐 𝑑 (c) 𝑔 3 𝑑 =𝑓 𝑑 sin 2 πœ” 𝑐 𝑑 (d) 𝑔 4 𝑑 = 𝑓 2 𝑑 sin πœ” 𝑐 𝑑 (e) 𝑔 5 𝑑 =𝑓 𝑑 βˆ— sin πœ” 𝑐 𝑑

19 Problem 3 FA16 Given the circuit on the right: Find the step response
Find the response to π‘₯ 𝑑 =π‘Ÿπ‘’π‘π‘‘ π‘‘βˆ’1 2

20 Problem 3 SP14

21 Problem 2 SP13

22 Problem 2 FA15

23 Problem 4 SP14 iii) Determine y(t)

24 Problem 5 FA13 a)i. Determine h(t) ii. Is the system causal?
iii. Is the system BIBO stable? b)i. Determine h(t)


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