Presentation is loading. Please wait.

Presentation is loading. Please wait.

Section 8.2 Problem Solving in Geometry With Proportions

Similar presentations


Presentation on theme: "Section 8.2 Problem Solving in Geometry With Proportions"— Presentation transcript:

1

2 Section 8.2 Problem Solving in Geometry With Proportions
Chapter 8 Similarity Section 8.2 Problem Solving in Geometry With Proportions

3 Example: 4 is the geometric mean between 2 and 8

4 The Ratio of the tops = The ratio of the bottom
Example The Ratio of the tops = The ratio of the bottom Example It’s OK to add the bottom to the top on each side

5

6 True: Reciprocal Property
False True: Ratio of Bottoms = Ratio of Tops False

7 x2 = 60 x2 = 96 x2 = 120

8 x2 = 150 x2 = 192 x2 = 480

9 Fill in the numbers and solve for JN
14 14(JN) = 48

10 Fill in the numbers and solve for PQ
4(PQ) = 6(16 – PQ) 4(PQ) = 96 – 6(PQ) 10 PQ = 96 16 - PQ

11 Fill in the numbers and solve
Let x represent the price you paid in dollars 9.52x = 450 x = 47.27 You paid $47.27 for the Jacket

12 Fill in the numbers and solve
Let x represent the price you paid in dollars x = 20.4 You paid $20.40 for the sweater

13 Need to know the distance:
d = rt = 10(12) = 120 Let x represent the wingspan 3x = 120 x = 40 The plane’s wingspan was 40 feet.


Download ppt "Section 8.2 Problem Solving in Geometry With Proportions"

Similar presentations


Ads by Google