1. FLAME TEST

2. - range of wavelengths of electromagnetic radiation
ATOMIC SPECTRA
- range of wavelengths of electromagnetic radiation
- wavelengths of visible light are separated when a beam of white light passes through a prism

4. SPECTROSCOPE

5. WAVELENGTH (λ) – distance between two adjacent crests or two adjacent troughs
FREQUENCY (υ) – number of cycles or waves per second
SPEED OF LIGHT (c) – 3 x 10 8 m/s
c = λ υ

7. ENERGY LEVELS of ELECTRONS in HYDROGEN1
x J 2
x J 3
x J 4
x J 5
x J 6
x J

8. To solve for the wavelength of light emitted by a change in the energy level of the electron, use the formula:
λ = hc ΔE
where h = x J/s (Planck’s constant)
c = 3.00 x 10 8 m/s (speed of light)
ΔE = change in energy
λ = wavelength of photon emitted in nanometers (nm)

9. Find the wavelength of a photon emitted when an electron jumps from the n = 3 energy level down to the n = 2 energy level. Where is this photon in the electromagnetic spectrum?
λ = hc = (6.626 x J/s) (3.00 x 10 8 m/s)
ΔE ( x J) - ( x J)
= x m or nm