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Different Types of Formulas
Molecular Formula – shows # of atoms in one molecule or formula unit Empirical Formula – shows smallest whole number mole ratio Structural Formula- molecular formula info PLUS bonding electrons and atomic arrangement C6H6 CH All different types of formulas for the same compound…benzene!
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Finding an Empirical Formula from Experimental Data
1. Find mass of each element (grams) 2. Find mols of each element (convert from grams to mols) 3. Divide each “# of mol” by the smallest “# of mol” (ratios) 4. Write out formula with ratios from step 3 as subscripts (multiply by smallest integer possible for whole #’s if needed) PRACTICE... A compound is 45.5% yttrium and 54.5% chlorine. Find its empirical formula. YCl3
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A ruthenium/sulfur compound is 67.7% Ru. Find its empirical formula.
RuS1.5 Ru2S3
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(Empirical Formula)n = Molecular Formula
To find molecular formula… A. Find empirical formula. B. Find mass of empirical formula. C. Find n = Molar Mass molecular empirical mass D. Multiply all parts of empirical formula by n. “How many empiricals fit into the molecular?”
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A carbon/hydrogen compound is 7.7% H and has a
molar mass of 78 g. Find its molecular formula. emprical formula = CH Empirical mass = 78 g 13 g n = = 6 C6H6 13 g
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92 g 46 g MMempirical = 46 g n = = 2 N2O4 ÷ 1.879 ÷ 1.879
A compound has g nitrogen, g oxygen, and molar mass 92 g. Find molecular formula. ÷ 1.879 ÷ 1.879 Empirical formula = NO2 92 g 46 g MMempirical = 46 g n = = 2 N2O4
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QUICK SUMMARY the mole is a chemist’s bridge out of the atomic world (amu) into the real world (g)!
Atomic Mass vs Molar Mass 6.022x1023 particles H2 = _______ H2O = ________ MgSO4 = ________ (NH4)3PO4 = ________ 2 amu 18 amu 120 amu 149 amu H2 = _____ H2O = _____ MgSO4 = _____ (NH4)3PO4 = _____ 2 g 18 g 120 g 149 g
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LET’S REVIEW… 6.02 x 1023 100 3 2 1 # of O atoms # of H atoms
# of H2O molecules 2 1 4 2 6 3 200 100 2 (6.02 x 1023) 6.02 x 1023 molar mass: the mass of one mole of a substance 18.0 g/mol 2.0 g/mol 16.0 g/mol
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Nitric Acid MOLAR MASS PRACTICE… Ammonium Phosphate # # (NH4)3PO4 HNO3
Element MM (g) Total (g) 1 H 1.01 N 14.01 3 O 16.00 48.00 TOTAL MOLAR MASS 63.02 # Element MM (g) Total (g) 3 N 14.01 42.03 12 H 1.01 12.12 1 P 30.97 4 O 16.00 64.00 TOTAL MOLAR MASS 149.12 Nitric Acid Ammonium Phosphate
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percentage composition: the mass % of each element in a compound
mass % of element = g element molar mass of compound x 100 Find the % composition of ammonium phosphate. (NH4)3PO4 42.03 g N : g = % N 12.12 g H : g = % H 30.97 g P : g = % P 64.00 g O : g = % O
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Review Problems A g sample of a technetium/oxygen compound contains g of Tc. Find the empirical formula. TcO3.5 Tc2O7
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n = Review Problems A compound contains 70.35 g C and 14.65 g H.
Its molar mass is 58 g. Find its molecular formula. emp. form. C2H5 58 g n = MMemp = 29 g = 2 C4H10 29 g
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? PbN4O8 ? Pb(NO2)4 Pb? 4 NO21– Review Problems
A compound contains 4.63 g lead, 1.25 g nitrogen, and 2.87 g oxygen. Name the compound. ? PbN4O8 ? lead (IV) nitrite Pb(NO2)4 (plumbic nitrite) Pb? 4 NO21–
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