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OUTCOME QUESTION(S): C12-3-06 REACTION RATES Vocabulary & Concepts
Formulate an operational definition of reaction rate and solve rate problems. Include: average rate, instantaneous rates Relate the rate of formation of a product to the rate of disappearance of a reactant given experimental rate data and reaction stoichiometry. Use the Collision Theory to explain the rate of chemical reactions. Include: Activation energy Vocabulary & Concepts
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The key is a measurement taken over time
Kinetics Branch of chemistry that studies: Speed or rate that a species / reaction changes. 2. Steps or mechanism, of a reaction. Some reactions do not occur in one simple step, some occur in as a series of steps creating a complex reaction Rate can be found by measuring different properties/variables - depending on the reaction: Concentration (mol/L·s) Temperature (°C/min) Pressure (kPa/h) Mass (g/s) Colour, pH, conductivity… The key is a measurement taken over time
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A(s) + B(l) C(g) + heat Rate = Measured change in a property
change in energy A(s) + B(l) C(g) heat change in mass change in pressure We will use concentrations most of the time Rate = Measured change in a property Time for change to occur Average Rate is described as total change in concentration over time. RateP = Δ[P] Δt slow Final RateP = [P]final - [P]initial tfinal - tinitial Average (secant) fast Initial All reactions have quick initial rates, but slow down over time
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Units will match those given in the table
a. What is rate of production of B over the 50 seconds? Initial RateB = Δ[B] Δt Final RateB = [B]final - [B]initial tfinal - tinitial RateB = [0.67]f - [0.0]i 50.0f - 0.0i Units will match those given in the table RateB = mol/L·s moles per litre per second
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b. What is the production rate for interval 20 s to 40 s?
Initial RateB = Δ[B] Δt Final RateB = [B]final - [B]initial tfinal - tinitial RateB = [0.65]f - [0.50]i 40.0f i RateB = mol/L·s
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Decomposition of nitrogen dioxide produces nitrogen monoxide and oxygen:
2 NO2 (g) NO (g) O2 (g) Time (min) [NO2] (mol/L) [NO] (mol/L) [O2] (mol/L) 0.0 0.100 0.00 10 0.066 0.034 0.017 20 0.048 0.052 0.026 30 0.038 0.062 0.031 40 0.030 0.070 0.035 Notice the rates are slowing down over time Notice reactants are decreasing and products are increasing
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– a. Ave. rate of decomposition of NO2 over 40 min.
Time (min) [NO2] (mol/L) [NO] (mol/L) [O2] (mol/L) 0.0 0.100 0.00 10 0.066 0.034 0.017 20 0.048 0.052 0.026 30 0.038 0.062 0.031 40 0.030 0.070 0.035 Negative rate equation communicates decrease with time Rate = 1.75 x 10-3 mol/L·min RateNO2 = Δ[NO2] Δt – Rate value will always be expressed as a positive value Rate = – [0.030]f - [0.100]i 40f - 0i Rate = – ( – )
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Notice rate equation is a positive value – increasing with time
b. Ave. rate of production of O2 over 40 min. Time (min) [NO2] (mol/L) [NO] (mol/L) [O2] (mol/L) 0.0 0.100 0.00 10 0.066 0.034 0.017 20 0.048 0.052 0.026 30 0.038 0.062 0.031 40 0.030 0.070 0.035 RateO2 = Δ[O2] Δt Notice rate equation is a positive value – increasing with time Rate = [0.035]f - [0.00]i 40f - 0i Notice the relationship between the values of O2 and the previous rate of NO2? Rate = x 10-4 mol/L·s
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How is the rate calculated for a specific time?
2 NO2 (g) NO (g) O2 (g) How is the rate calculated for a specific time? Time (min) [NO2] (mol/L) [NO] (mol/L) [O2] (mol/L) 0.0 0.100 0.00 10 0.066 0.034 0.017 20 0.048 0.052 0.026 30 0.038 0.062 0.031 40 0.030 0.070 0.035 We still need a “final” and “initial” point, so we must extend the point and create a line
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As opposed to over an interval of time
Instantaneous rate - rate at a specific point in time. Determined by calculating the slope of the line tangent to a point on the curve. As opposed to over an interval of time RateNO2 = [NO2]final - [NO2]initial tfinal - tinitial Think of it as extending the point in both directions to create a line that estimates the rate at that moment [NO2]f (tangent) [NO]i ti tf
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Rates can be predicted from reaction stoichiometry.
2 NO2 (g) NO (g) O2 (g) How does the graph match the information of the equation?
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What is the rate of production of O2 and the rate of disappearance of NO2 if NO is made at a rate of 0.60 mol/Ls? 2 NO2 (g) NO (g) O2 (g) Look at the equation and try to predict the value before attempting to solve 0.60 mol/L·s NO 2 mol NO 1 mol O2 = mol/L·s O2 0.60 mol/L·s NO 2 mol NO 2 mol NO2 = mol/L·s NO2
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2 N2O5 (g) NO2 (g) O2 (g) The rate of N2O5 is half the rate of NO2 The rate of O2 is half the rate of N2O5 The rate of NO2 is 4x the rate of O2 Reaction Rate – numerical value of ANY reactant or product change, equalized to a coefficient of 1. Rate of the reaction is a consistent value regardless of which species is investigated - all values are equivalent and give same reaction rate value
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aA + bB cC 2 N2O5 (g) 4 NO2 (g) + 1 O2 (g) Reaction Rate _ 1 Δ[A] a Δt
b Δt 1 Δ[C] c Δt 1 Δ[D] d Δt RateReaction = = = = + 2 N2O5 (g) NO2 (g) O2 (g) _ 1 Δ[N2O5] 2 Δt 1 Δ[NO2] 4 Δt Δ[O2] Δt RateReaction = = = + The equations all give a consistent value for the rate of the reaction at that time interval
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CAN YOU / HAVE YOU? C12-3-06 REACTION RATES Vocabulary & Concepts
Formulate an operational definition of reaction rate and solve rate problems. Include: average rate, instantaneous rates Relate the rate of formation of a product to the rate of disappearance of a reactant given experimental rate data and reaction stoichiometry. Use the Collision Theory to explain the rate of chemical reactions. Include: Activation energy Vocabulary & Concepts
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