1. Lecture 4.4 – Particles to Particles and Complex Stoichiometry

2. Today’s Learning Targets
LT 4.7 – I can convert from particles of one compound to particles of another compound
LT 4.8 – I can complete a complex stoichiometric conversion that incorporates molarity, particles, mass, moles, and volumes of substances.

3. Molarity of Substance A Molarity of Substance B
Moles of A
Moles of B
Grams of Substance B
Grams of Substance A
Atoms of Substance A
Atoms of Substance B

4. Our Focus for Today Moles of A Moles of B
Atoms of Element or Compound B
Atoms of Element or Compound A

5. How do we convert particles of one substance to particles of another substance?

6. I. Moles to Particles Conversion Factor
Our conversion factor for moles  particles is:
6.022 x 1023 particles
mole
Can be reversed to fit conversion

7. II. Moles to Particles Between 2 Substances
We can utilize what we know about converting between moles to convert between particles for a different substance.
We simply follow the same rules and conversion factors

8. Class Example
You react 30 x 1023 particles of HCl for the following reaction:
HCl + MnO2  MnCl H2O
How many molecules of MnCl4 did you use for this reaction?

9. Example You react 3 moles of MnO2 for the following reaction:
HCl + MnO2  MnCl H2O
How many molecules of HCl did you use for this reaction?

10. NH4SCN + FeCl3NH3(g) + HCl + Fe(SCN) 3
Table Talk
For the following reaction:
NH4SCN + FeCl3NH3(g) + HCl + Fe(SCN) 3
If you react 4 moles of FeCl3, how many particles of NH3 would you produce?

11. Table Talk
If you react 12 x 1023 particles of MnO2 with HCl in the following reaction:
HCl + MnO2  MnCl H2O
How many moles of MnCl4 did you use in this reaction?

12. How do I complete complex stoichiometry problems?

13. Molarity of Substance A Molarity of Substance B
Moles of A
Moles of B
Grams of Substance B
Grams of Substance A
Have students fill in all arrows with the necessary conversion factors
Atoms of Substance A
Atoms of Substance B

14. (C2OH5)2S + 2 HCl → (C2H4Cl)2S + 2 H2O
Class Example
You wish to make mustard gas using the reaction:
(C2OH5)2S + 2 HCl → (C2H4Cl)2S + 2 H2O
If I add 52 g of HCl, then how many particles of H2O will I produce?

15. Molarity of Substance A Molarity of Substance B
Moles of A
Moles of B
Grams of Substance B
Grams of Substance A
Have students fill in all arrows with the necessary conversion factors
Atoms of Substance A
Atoms of Substance B

16. (C2OH5)2S + 2 HCl → (C2H4Cl)2S + 2 H2O
Table Talk
You wish to make mustard gas using the reaction:
(C2OH5)2S + 2 HCl → (C2H4Cl)2S + 2 H2O
If I add 143 g of (C2OH5)2S , then how many grams of (C2H4Cl)2S will I produce?

17. Molarity of Substance A Molarity of Substance B
Moles of A
Moles of B
Grams of Substance B
Grams of Substance A
Have students fill in all arrows with the necessary conversion factors
Atoms of Substance A
Atoms of Substance B

18. Table Talk You run the Haber – Bosh Reaction to make NH3:
N2 + 3H2  2NH3
If you begin with 15 x 1023 particles of H2, then how many grams of NH3 do you produce?

19. Molarity of Substance A Molarity of Substance B
Moles of A
Moles of B
Grams of Substance B
Grams of Substance A
Have students fill in all arrows with the necessary conversion factors
Atoms of Substance A
Atoms of Substance B