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Published byElinor Simpson Modified over 5 years ago
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5.2 Section 5.1 – Increasing and Decreasing Functions
The First Derivative Test and its documentation 5.2
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The Theory First…… THE FIRST DERIVATIVE TEST If c is a critical number and f ‘ changes signs at x = c, then f has a local minimum at x = c if f ‘ is negative to the left of c and positive to the right of c. f has a local maximum at x = c if f ‘ is positive to the left of c and negative to the right of c.
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_ _ 1 3 -3 5 + There is a rel min at x = 1 because f ‘ changes from neg to pos at 1 There is a rel max at x = 3 because f ‘ changes from pos to neg at 3
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The Theory…Part II EXTREME VALUE THEOREM If a function f is continuous on a closed interval [a, b] then f has a global (absolute) maximum and a global (absolute) minimum value on [a, b]. GLOBAL (ABSOLUTE) EXTREMA A function f has: A global maximum value f(c) at c if f(x) < f(c) for every x in the domain of f. A global minimum value f(c) at c if f(x) > f(c) for every x in
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The Realities….. On [1, 8], the graph of any continuous function HAS to Have an abs max Have an abs min
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_ + There is an abs min at x = -1/2 because f ‘ (x) < 0 FOR ALL x < -1/2 and f ‘ (x) > 0 FOR ALL x > -1/2
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Justify your answer. _ _ -2 -1 3 + +
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_ +
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Justify your answer. _ _ +
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Justify your answer. _ +
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GRAPHING CALCULATOR REQUIRED
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1.684 0.964
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[0, 0.398), (1.351, 3]
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The absolute max is 1.366 and occurs when x = 3
The absolute min is –0.098 and occurs when x = 1.351
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Let k = 2 and proceed
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_ + + 3 6
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_ _ 1 +
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CALCULATOR REQUIRED
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