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Published byΦίλητος Αργυριάδης Modified over 6 years ago
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AB AC AD AE AF 5 ways If you used AB, then, there would be 4 remaining ODD vertices (C, D, E and F) CD CE CF 3 ways If you used CD, then, there would be 2 remaining ODD vertices (E and F) EF 1 way
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Here are the 15 ways AB BC CD DE EF AC BD CE DF AD BE CF AE BF AF
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A B C D E F G H
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What the examiner is looking for
You have stated the ODD VERTICES You have stated the different combinations and their distances You have stated which combination is repeated You have added the new edges to your diagram You have stated the total distance, showing the sum
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