1. Limiting reagents

2. Happy Mole Day

3. A + 3 B  5 C
In this reaction, for every mole of A you need 3 moles of B to completely react.
If you only have 2 moles of B, then not all of the A can completely react to form the maximum amt of product C.
B is a limiting reagent. It limits the amount of product that can be produced.

4. A + 3 B  5 C
The fastest and easiest way to determine a limiting reagent is to calculate the amt. Of product that each reactant can produce if they are allowed to completely react.
1.0 mole A x 5 C/1A = moles C
2.0 moles B x 5C/3B = moles C
B limits the amt of product that can form

5. 2N O2  2 N205
If 6.0 moles of Nitrogen are place in a container with 16 moles of oxygen, how much product can be formed?
Calculate how much product each reactant can create if completely consumed.
6.0 moles N2 x 2N2O5/2N2 = 6.0 moles prod.
16 moles O2 x 2 N2O5/5O2 =