1. Five-Minute Check (over Lesson 6–5) Then/Now New Vocabulary
Theorems: Isosceles Trapezoids
Proof: Part of Theorem 6.23
Example 1: Real-World Example: Use Properties of Isosceles Trapezoids
Example 2: Isosceles Trapezoids and Coordinate Geometry
Theorem 6.24: Trapezoid Midsegment Theorem
Example 3: Standardized Test Example
Theorems: Kites
Example 4: Use Properties of Kites
Lesson Menu

2. A B C D LMNO is a rhombus. Find x. A. 5 B. 7 C. 10 D. 12
5-Minute Check 1

3. A B C D LMNO is a rhombus. Find y. A. 6.75 B. 8.625 C. 10.5 D. 12
5-Minute Check 2

4. A B C D QRST is a square. Find n if mTQR = 8n + 8. A. 10.25 B. 9
5-Minute Check 3

5. A B C D QRST is a square. Find w if QR = 5w + 4 and RS = 2(4w – 7)._ A B C D
5-Minute Check 4

6. A B C D QRST is a square. Find QU if QS = 16t – 14 and QU = 6t + 11.
5-Minute Check 5

7. Which statement is true about the figure shown whether it is a square or a rhombus?
C. JM║LM D. A B C D
5-Minute Check 6

8. Splash Screen

9. Lesson 6-6 Trapezoids and Kites (Pg. 435)
TARGETS
Recognize and apply properties of trapezoids.
Recognize and apply properties of kites.
Then/Now

10. Content Standards G-CO.11 Prove geometric theorems.
G-CO.12 Make geometric constructions.
G-GPE.4 Use coordinates to prove simple geometric theorems algebraically.
Mathematical Practices
1 Make sense of problems and persevere in solving them
2 Reason abstractly and quantitatively.
6 Attend to precision.
Then/Now

11. You used properties of special parallelograms. (Lesson 6–5)
Apply properties of trapezoids.
Apply properties of kites.
Then/Now

12. Trapezoid – a quadrilateral with exactly one pair of parallel sides
Bases – the parallel sides
legs of a trapezoid – the nonparallel sides
base angles – formed by a base and one leg
Vocabulary

13. isosceles trapezoid – a trapezoid with congruent legs
midsegment of a trapezoid – the segment that connects the midpoints of the legs
Kite – a quadrilateral with exactly two pairs of consecutive congruent sides

14. Concept 1

15. Use Properties of Isosceles Trapezoids
A. BASKET Each side of the basket shown is an isosceles trapezoid. If mJML = 130, KN = 6.7 feet, and LN = 3.6 feet, find mMJK.
Example 1A

16. Since JKLM is a trapezoid, JK║LM.
Use Properties of Isosceles Trapezoids
Since JKLM is a trapezoid, JK║LM.
mJML + mMJK = 180 Consecutive Interior Angles Theorem
mJML = 180 Substitution
mJML = 50 Subtract 130 from each side.
Answer: mJML = 50
Example 1A

17. Use Properties of Isosceles Trapezoids
B. BASKET Each side of the basket shown is an isosceles trapezoid. If mJML = 130, KN = 6.7 feet, and JL is 10.3 feet, find MN.
Example 1B

18. JL = KM Definition of congruent JL = KN + MN Segment Addition
Use Properties of Isosceles Trapezoids
Since JKLM is an isosceles trapezoid, diagonals JL and KM are congruent.
JL = KM Definition of congruent
JL = KN + MN Segment Addition
10.3 = MN Substitution
3.6 = MN Subtract 6.7 from each side.
Answer: MN = 3.6
Example 1B

19. A. Each side of the basket shown is an isosceles trapezoid
A. Each side of the basket shown is an isosceles trapezoid. If mFGH = 124, FI = 9.8 feet, and IG = 4.3 feet, find mEFG.
A. 124
B. 62
C. 56
D. 112 A B C D
Example 1A

20. B. Each side of the basket shown is an isosceles trapezoid
B. Each side of the basket shown is an isosceles trapezoid. If mFGH = 124, FI = 9.8 feet, and EG = 14.1 feet, find IH.
A. 4.3 ft
B. 8.6 ft
C. 9.8 ft
D ft A B C D
Example 1B

21. Concept 3

22. In the figure, MN is the midsegment of trapezoid FGJK
In the figure, MN is the midsegment of trapezoid FGJK. What is the value of x.
Example 3

23. Trapezoid Midsegment Theorem
Read the Test Item
You are given the measure of the midsegment of a trapezoid and the measures of one of its bases. You are asked to find the measure of the other base.
Solve the Test Item
Trapezoid Midsegment Theorem
Substitution
Example 3

24. Subtract 20 from each side.
Multiply each side by 2.
Subtract 20 from each side.
Answer: x = 40
Example 3

25. WXYZ is an isosceles trapezoid with median Find XY if JK = 18 and WZ = 25.
A. XY = 32
B. XY = 25
C. XY = 21.5
D. XY = 11 A B C D
Example 3

26. Concept 4

27. A. If WXYZ is a kite, find mXYZ.
Use Properties of Kites
A. If WXYZ is a kite, find mXYZ.
Example 4A

28. mW + mX + mY + mZ = 360 Polygon Interior Angles Sum Theorem
Use Properties of Kites
Since a kite only has one pair of congruent angles, which are between the two non-congruent sides, WXY  WZY. So, WZY = 121.
mW + mX + mY + mZ = 360 Polygon Interior Angles Sum Theorem
mY = 360 Substitution
mY = 45 Simplify.
Answer: mY = 45
Example 4A

29. B. If MNPQ is a kite, find NP.
Use Properties of Kites
B. If MNPQ is a kite, find NP.
Example 4B

30. NR2 + MR2 = MN2 Pythagorean Theorem (6)2 + (8)2 = MN2 Substitution
Use Properties of Kites
Since the diagonals of a kite are perpendicular, they divide MNPQ into four right triangles. Use the Pythagorean Theorem to find MN, the length of the hypotenuse of right ΔMNR.
NR2 + MR2 = MN2 Pythagorean Theorem
(6)2 + (8)2 = MN2 Substitution
= MN2 Simplify.
100 = MN2 Add.
10 = MN Take the square root of each side.
Example 4B

31. Since MN  NP, MN = NP. By substitution, NP = 10.
Use Properties of Kites
Since MN  NP, MN = NP. By substitution, NP = 10.
Answer: NP = 10
Example 4B

32. A B C D A. If BCDE is a kite, find mCDE. A. 28° B. 36° C. 42° D. 55°
Example 4A

33. B. If JKLM is a kite, find KL.
C. 7
D. 8 A B C D
Example 4B

34. Homework p – 20 even, 26, 27