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Work in Electrical Systems
Chapter 2 Section 3 Work in Electrical Systems
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Objectives Explain the relationship between work, charge and potential difference (voltage). Calculate electrical charge in a circuit. Define units of electric current. Solve problems in electrical work. Identify effects of electrical work. Explain efficiency in terms of work in and work out in electrical systems.
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Coulombs The unit of electric charge is the coulomb (C).
The fundamental charge on an electron is 1.6 X C. 1 C = 1/ 1.6 X = 6.25 X 1018 electrons or 6,250,000,000,000,000,000 electrons.
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Work in electrical systems
The electric field is given by E = F / q (Sec 1.3). Thus F=Eq. Potential difference (voltage) is given by V=Ed (Sec 1.3) W = Fd = Eqd Thus W = Vq
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Work - cont Thus Work = potential difference X charge moved W=Vq
The work needed to move one coulomb of charge though a potential difference of one volt is one joule. 1J = 1 V . C 1V = 1 J/C
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Electric Charge & Current
Electric current is the rate at which charge flows through a circuit. Current = charge / time; I = q / t Current is measured in amperes or amps (A) 1 amp = 1 coulomb per second; A = 1 C/s
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Efficiency Efficiency = work out / work in; Wout / Win
% Efficiency = (Wout / Win) x 100% Efficiency can never be equal to or greater than 100% Work out will always be less than work in.
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Summary Electric work is done when a charge is moved through a potential difference. W = Vq 1 joule = 1 volt X 1 coulomb; 1J = 1V.C Current is the rate at which charge flows. 1 Amp = 1 coulomb per second; 1A=1C/s. % Efficiency = (Wout / Win) x 100%
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