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As always… OWL Lon-Capa assignments Lecture videos Textbook Read
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Exam III Thursday, December 6, 7:00-9:00 pm; rooms are on the website (same as Exam II). Conflict: (12/6) 4:30-6:30 pm in 219 Greg; sign up in 1026 Chem Annex starting Friday Conflict with conflict? me right away. Review sessions: 1024 Chem Annex, 6-8 pm Monday, December 3 Tuesday, December 4
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Clicker Questions Pure N2O3 was placed in a rigid vessel and allowed to decompose: 2N2O3(g) 2N2(g) + 3O2(g). The following data were collected in an experiment at a certain temperature. Determine: the rate law of the reaction. the first half-life for the reaction the pressure of O2(g) at t = minutes Time (min) Ptotal (atm) 10.000 10.00 15.071 20.00 18.428 30.00 20.649 40.00 22.120 50.00 23.094
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Rate Laws From Elementary Steps
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Clicker Question The experimental rate law for the decomposition of nitrous oxide (N2O) to N2 and O2 is rate = k[N2O]2. Two mechanisms are proposed: I. N2O N2 + O N2O + O N2 + O2 II. 2N2O N4O2 N4O2 2N2 + O2 Which of the following could be a correct mechanism? a) Mechanism I with the first step as the rate-determining step. b) Mechanism I with the second step as the rate-determining step as long as the first step is a fast equilibrium step. c) Mechanism II with the second step as the rate-determining step if the first step is a fast equilibrium step. d) None of the choices (a-c) could be correct. e) At least two of the above choices (a-c) could be correct.
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Chapter 15
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Pseudo-Order Question
Determine the rate law and value of k given the following data. 2H2(g) + 2NO(g) N2(g) + 2H2O(g) EXPERIMENT #1 EXPERIMENT #2 TIME (sec) [NO] [NO] ________ x 10-2 M 1.00 x 10-2 M x 10-3M 5.00 x 10-3 M x 10-3 M 3.33 x 10-3 M x 10-3 M 2.50 x 10-3 M x 10-3 M 2.00 x 10-3 M In experiment #1, [H2]0 = 10.0 M In experiment #2, [H2]0 = 20.0 M
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