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Factor Analysis Development
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[ ] [ ] l l D Z Z Z Z Q -1 Z Q Z Q Q Q j Q n Z = D # A + B T j
Factor Analysis Development Z = D # T A + B always a diagonal matrix Sometimes the identity matrix A is (The complete story in two slide) D Z CO Z CM Z RO Z RM Find Q such that [ ] Q -1 A diagonal matrix Z Q If you are successful then = Each of these is an eigenvalue l [ ] l j Z Q Q Q j = Each of these is an eigenvector Each of these columns (eigenvectors) is linearly independent Q n will make a great orthonormal basis set orthogonal
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( ) ( ) D = RC Z Q n Q n Q n D D U Q n D U D I Q n D Q n Q n Q n Q n D
Factor Analysis Development D = RC (The complete story in two slide) Z Q n -1 T Q n -1 Q n ( ) D T D = U Q n D U D = I T Q n D T -1 Q n -1 Q n -1 Q n -1 Q n D T U D Q n = ( ) U T Q n D T U D Q n = U U T U
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( ) D = RC Z Q D n I U -1 T = Factor Analysis Development
(The complete story in two slide)
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