1. Bellwork Tuesday
5.9 L of carbon dioxide is combined with 8.4 g MgO in a synthesis reaction to form magnesium carbonate. How many grams of magnesium carbonate is created in this reaction?

2. Unit 8 Ch 12 Part 4 % Yield

3. Percent Yield
Theoretical Yield – The maximum amount of product that could be formed from given amounts of reactants. (What you should get).
Actual Yield - amount of product actually obtained in the reaction (What you really get).

4. % yield = Actual Yield x 100 Theoretical Yield
Amount you actually obtain in an experiment
% yield = Actual Yield x 100
Theoretical Yield
Amount you should obtain in an experiment (this we will calculate)

5. EXAMPLE
If 12.5 g of copper are reacted with an excess of chlorine gas, then 25.4 g of copper(II) chloride, CuCl2(s), are obtained. Calculate the theoretical yield and the percent yield.
First write the balanced equation, then find the theoretical yield (amount you “should get”)

6. First write the balanced equation, then find the theoretical yield (amount you “should get”)
Cu + Cl2 → CuCl2
12.5 g Cu
1 mol Cu
1 mol CuCl2
134.5 g CuCl2
63.5 g Cu
1 mol Cu
1 mol CuCl2
GFM
mol-mol ratio
GFM =
26.5 g CuCl2
this is the theoretical yield

7. Now do the % yield calculation
% yield = Actual Yield x 100
Theoretical Yield
given in problem
25.4 g CuCl2
% yield =
X 100 =
95.8 %
26.5 g CuCl2
from calculation