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Mathematics for Computer Science MIT 6.042J/18.062J
Sums, Products & Asymptotics Copyright © Albert Meyer, 2002. Prof. Albert Meyer & Dr. Radhika Nagpal
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C. F. Gauss Picture source:
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Sum for children 8900 + 9003 + 9106 + 9209 + 9312 + 9415 + ···
··· ··· 10,445 + 10, ··· ,372
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Sum for children Nine-year old Gauss (so the story goes) saw that each number was 103 greater than the previous one.
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Sum for children 8900 + (8900+103) + (8900+2·103) +
(8900+3·103) + ··· + ( ·103) = 8900·25 + ( ··· + 24)103
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A ::= 1 + 2 + … + (n-1) + n A = 1 + 2 + … + (n-1) + n
Arithmetic Series A ::= … + (n-1) + n A = … + (n-1) + n
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2A = (n+1)+(n +1) + … + (n +1) + (n +1)
Arithmetic Series A ::= … + (n-1) + n A ::= n + (n-1) + … 2A = (n+1)+(n +1) … + (n +1) + (n +1) = n(n+1)
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Arithmetic Series So
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Geometric Series
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Geometric Series
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Geometric Series xn+1
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Geometric Series n+1
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The future value of $$. Annuities I will promise to pay you $100
in exactly one year, if you will pay me $X now.
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1.03 X = 100. Annuities My bank will pay me 3% interest.
If I deposit your $X for a year, I can’t lose if 1.03 X = 100.
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Annuities I can’t lose if you pay me: X = $100/1.03 ≈ $97.09
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Annuities 97.09¢ today is worth $1.00 in a year
$1.00 in a year is worth $1/1.03 today $n in a year is worth $nr today, where r = 1/1.03.
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Annuities $n in two years is worth $nr2 today
$n in k years is worth $nr k today
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Annuities I will pay you $100/year for 10 years
If you will pay me $Y now. I can’t lose if you pay me 100r + 100r r3 + … + 100r10 =100r(1+ r + … + r9) = 100r(1-r10)/(1-r) = $853.02
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In-Class Problem Problems 1 & 2
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