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Practice The Neuroticism Measure = 23.32 S = 6.24 n = 54
How many people likely have a neuroticism score between 29 and 34?
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Practice (29-23.32) /6.24 = .91 area = .3186 ( 34-23.32)/6.26 = 1.71
= .1378 .1378*54 = 7.44 or 7 people
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Practice On the next test I will give an A to the top 5 percent of this class. The average test grade is with a SD of 6.98. How many points on the test did you need to get to get an A?
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Step 1: Sketch out question
.05
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Step 2: Look in Table Z Z score = 1.64 .05
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Step 3: Find the X score that goes with the Z score
Must solve for X X = + (z)() 68.26 = (1.64)(6.98)
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Step 3: Find the X score that goes with the Z score
Must solve for X X = + (z)() 68.26 = (1.64)(6.98) Thus, a you need a score of to get an A
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Practice The prestigious Whatsamatta U will only take people scoring in the top 97% on the verbal section SAT (i.e., they reject the bottom 3%). What is the lowest score you can get on the SAT and still get accepted? Mean = 500; SD = 100
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Step 1: Sketch out question
.03
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Step 2: Look in Table C Z score = -1.88 .03
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Step 3: Find the X score that goes with the Z score
Must solve for X X = + (z)() 312 = (-1.88)(100)
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Step 3: Find the X score that goes with the Z score
Must solve for X X = + (z)() 312 = (-1.88)(100) Thus, you need a score of 312 on the verbal SAT to get into this school
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Is this quarter fair? How could you determine this?
You assume that flipping the coin a large number of times would result in heads half the time (i.e., it has a .50 probability)
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Is this quarter fair? Say you flip it 100 times 52 times it is a head
Not exactly 50, but its close probably due to random error
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Is this quarter fair? What if you got 65 heads? 70? 95?
At what point is the discrepancy from the expected becoming too great to attribute to chance?
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Basic logic of research
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Start with two equivalent groups of subjects
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Treat them alike except for one thing
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See if both groups are different at the end
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Or – Single Group
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Do something
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Measure DV
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Compare Group to Population
Population Happiness Score
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The Theory of Hypothesis Testing
Data are ambiguous Is a difference due to chance? Sampling error
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Population You are interested in the average self-esteem in a population of 40 people Self-esteem test scores range from 1 to 10.
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Population Scores 1,1,1,1 2,2,2,2 3,3,3,3 4,4,4,4 5,5,5,5 6,6,6,6 7,7,7,7 8,8,8,8 9,9,9,9 10,10,10,10
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Histogram
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What is the average self-esteem score of this population?
Population mean = 5.5 Population SD = 2.87 What if you wanted to estimate this population mean from a sample?
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What if Randomly select 5 people and find the average score
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Group Activity Why isn’t the average score the same as the population score? When you use a sample there is always some degree of uncertainty! We can measure this uncertainty with a sampling distribution of the mean
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EXCEL
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INTERNET EXAMPLE
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Sampling Distribution of the Mean
Notice: The sampling distribution is centered around the population mean! Notice: The sampling distribution of the mean looks like a normal curve! This is true even though the distribution of scores was NOT a normal distribution
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Central Limit Theorem For any population of scores, regardless of form, the sampling distribution of the mean will approach a normal distribution a N (sample size) get larger. Furthermore, the sampling distribution of the mean will have a mean equal to and a standard deviation equal to / N
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Sampling Distribution
Tells you the probability of a particular sample mean occurring for a specific population
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Sampling Distribution
You are interested in if your new Self-esteem training course worked. The 5 people in your course had a mean self-esteem score of 5.5
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Sampling Distribution
Did it work? How many times would we expect a sample mean to be 5.5 or greater? Theoretical vs. empirical 5,000 random samples yielded 2,501 with means of 5.5 or greater Thus p = of this happening
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Sampling Distribution
5.5 P = P =.5002 2, ,501
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Sampling Distribution
You are interested in if your new Self-esteem training course worked. The 5 people in your course had a mean self-esteem score of 5.8
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Sampling Distribution
Did it work? How many times would we expect a sample mean to be 5.8 or greater? 5,000 random samples yielded 2,050 with means of 5.8 or greater Thus p = .41 of this happening
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Sampling Distribution
5.8 P = P =.41 2, ,300
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Sampling Distribution
The 5 people in your course had a mean self-esteem score of 9.8. Did it work? 5,000 random samples yielded 4 with means of 9.8 or greater Thus p = of this happening
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Sampling Distribution
9.8 P = P =.0008 4,
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Logic 1) Research hypothesis 2) Collect data
Training increased self-esteem The sample mean is greater than general population mean 2) Collect data 3) Set up the null hypothesis H0 Training did not increase self-esteem The sample is no different than general population mean
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Logic 4) Obtain a sampling distribution of the mean under the assumption that H0 is true 5) Given the distribution obtain a probability of a mean at least as large as our actual sample mean 6) Make a decision Either reject H0 or fail to reject H0
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Hypothesis Test – Single Subject
You think your IQ is “freakishly” high that you do not come from the population of normal IQ adults. Population IQ = 100 ; SD = 15 Your IQ = 125
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Step 1 and 3 H1: 125 > μ Ho: 125 < or = μ
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Step 4: Appendix Z shows distribution of Z scores under null
-3 -2 -1 1 2 3
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Step 5: Obtain probability
125 -3 -2 -1 1 2 3
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Step 5: Obtain probability
( ) / 15 = 1.66 125 -3 -2 -1 1 2 3
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Step 5: Obtain probability
Z = 1.66 125 .0485 -3 -2 -1 1 2 3
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Step 6: Decision Probability that this score is from the same population as normal IQ adults is .0485 In psychology Most common cut-off point is p < .05 Thus, your IQ is significantly HIGHER than the average IQ
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One vs. Two Tailed Tests Previously wanted to see if your IQ was HIGHER than population mean Called a “one-tailed” test Only looking at one side of the distribution What if we want to simply determine if it is different?
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One-Tailed -3 -2 -1 1 2 3 H1: IQ > μ Ho: IQ < or = μ
p = .05 μ -3 -2 -1 1 2 3 Did you score HIGHER than population mean? Want to see if score falls in top .05
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Two-Tailed -3 -2 -1 1 2 3 H1: IQ = μ Ho: IQ = μ p = .05
-3 -2 -1 1 2 3 Did you score DIFFERNTLY than population mean?
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Two-Tailed -3 -2 -1 1 2 3 H1: IQ = μ Ho: IQ = μ p = .05
-3 -2 -1 1 2 3 Did you score DIFFERNTLY than population mean? PROBLEM: Above you have a p = .10, but you want to test at a p = .05
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Two-Tailed -3 -2 -1 1 2 3 H1: IQ = μ Ho: IQ = μ p = .025
-3 -2 -1 1 2 3 Did you score DIFFERNTLY than population mean?
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Step 6: Decision Probability that this score is from the same population as normal IQ adults is .0485 In psychology Most common cut-off point is p < .05 Note that on the 2-tailed test the point of significance is .025 (not .05) Thus, your IQ is not significantly DIFFERENT than the average IQ
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Problems Problems with Null hypothesis testing Logic is backwards:
Most think we are testing the probability of the hypothesis given the data Really testing the probability of the data given the null hypothesis!
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Practice A recently admitted class of graduate students at a large university has a mean GRE verbal score of 650 with a SD of 50. One student, whose mom is on the board of trustees, has a GRE score of Do you think the school was showing favoritism? Why is there such a small SD? Why might (or might not) the GRE scores in this sample be normally distributed?
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4.7 Z = ( ) / 50 = -3.2 p = (490 or lower)
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4.8 Because students are being selected with high GREs (restricted range)
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4.9 Would not be normally distributed Negatively skewed
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Practice Last nights NHL game resulted in a score of 26 – 13. You would probably guess that I misread the paper. In effect you have just tested and rejected a null hypothesis. 1) What is the null hypothesis 2) Outline the hypothesis testing precede you just applied.
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4.1 a) Null = last nights game was an NHL game (i.e., the scores come from the population of all NHL scores) B) Would expect that a team would score between 0 – 6 points (null hypothesis). Because the actual scores are a lot different we would reject the null.
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