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CSE 544: Lecture 11 Storing Data, Indexes
Monday, 5/1/2006
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Outline Storing data: disks and files - 9.5-9.7
Types of Indexes - Chapter 8.3 B-trees - Chapter 10
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Managing Free Blocks By the OS By the RDBMS (typical: why ?)
Linked list of free blocks Bit map
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Files of Records Types of files: Heap file - unordered Sorted file
Clustered file - sorted, plus a B-tree Will discuss heap files only; the others are similar, only sorted by the key
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Pages with some free space
Heap Files Full pages Linked list of pages: Data page Data page Data page Data page Header page Pages with some free space Data page Data page Data page Data page
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Heap Files Better: directory of pages Data page Header Data page
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Page Formats Issues to consider 1 page = fixed size (e.g. 8KB)
Records: Fixed length Variable length Record id = RID Typically RID = (PageID, SlotNumber) Log entries refer to RIDs. Plus, foreign keys may be optimized to RID’s, but I’m not sure if this is implemented in any system Why do we need RID’s in a relational DBMS ?
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Page Formats Slot 1 Slot 2 Slot N Free space N
Fixed-length records: packed representation Slot 1 Slot 2 Slot N Free space N Need to move records around when one is deleted Problems ?
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Page Formats Free space Slot directory Variable-length records
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Record Formats Field 1 Field 2 . . . Field K
Fixed-length records --> all fields have fixed length Field 1 Field 2 . . . Field K
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Record Formats Field 1 Field 2 . . . Field K Variable length records
Record header Remark: NULLS require no space at all (why ?)
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Spanning Records Across Blocks
When records are very large Or even medium size: saves space in blocks Commercial RDBMS avoid this block header block header R1 R2 R3 R2
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LOB Large objects Supported by modern database systems
Binary large object: BLOB Character large object: CLOB Supported by modern database systems E.g. images, sounds, texts, etc. Storage: attempt to cluster blocks together
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Modifications: Insertion
File is unsorted (= heap file) add it to the end (easy ) File is sorted: Is there space in the right block ? Yes: we are lucky, store it there Is there space in a neighboring block ? Look 1-2 blocks to the left/right, shift records If anything else fails, create overflow block
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Overflow Blocks Blockn-1 Blockn Blockn+1 Overflow After a while the file starts being dominated by overflow blocks: time to reorganize
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Modifications: Deletions
Free space in block, shift records Maybe be able to eliminate an overflow block Can never really eliminate the record, because others may point to it Place a tombstone instead (a NULL record)
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Modifications: Updates
If new record is shorter than previous, easy If it is longer, need to shift records, create overflow blocks
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Record Formats: Fixed Length
Base address (B) Address = B+L1+L2 Information about field types same for all records in a file; stored in system catalogs. Finding i’th field requires scan of record. Note the importance of schema information! 9
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Indexes Search key = can be any set of fields
not the same as the primary key, nor a key Index = collection of data entries Data entry for key k can be: The actual record with key k (k, RID) (k, list-of-RIDs) 7
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Index Classification Primary/secondary Clustered/unclustered
Primary = may reorder data according to index Secondary = cannot reorder data Clustered/unclustered Clustered = records close in the index are close in the data Unclustered = records close in the index may be far in the data Dense/sparse Dense = every key in the data appears in the index Sparse = the index contains only some keys B+ tree / Hash table / …
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Primary Index File is sorted on the index attribute
Dense index: sequence of (key,pointer) pairs 10 20 10 20 30 40 30 40 50 60 70 80 50 60 70 80
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Primary Index Sparse index 10 20 30 40 50 60 70 80 10 30 50 90 70 110
130 150 50 60 70 80
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Primary Index with Duplicate Keys
Dense index: 10 10 20 30 40 10 20 50 60 70 80 20 30 40
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Primary Index with Duplicate Keys
Sparse index: pointer to lowest search key in each block: Search for 20 ...but need to search here too 10 10 20 30 20 is here... 10 20 20 30 40
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Primary Index with Duplicate Keys
Better: pointer to lowest new search key in each block: Search for 20 Search for 15 ? 35 ? 10 10 20 10 20 30 40 20 is here... ...ok to search from here 30 50 60 70 80 30 40 50
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Secondary Indexes To index other attributes than primary key
Always dense (why ?) 20 30 10 20 30 20 20 30 10 20 10 30
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Clustered/Unclustered
Primary indexes = usually clustered Secondary indexes = usually unclustered
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Clustered vs. Unclustered Index
Data entries Data entries (Index File) (Data file) Data Records Data Records CLUSTERED UNCLUSTERED 12
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Secondary Indexes index other attributes than primary key
index unsorted files (heap files) index clustered data
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Applications of Secondary Indexes
Secondary indexes needed for heap files Also for Clustered data: Company(name, city), Product(pid, maker) Select city From Company, Product Where name=maker and pid=“p045” Select pid From Company, Product Where name=maker and city=“Seattle” Products of company 2 Products of company 3 Products of company 1 Company 1 Company 2 Company 3
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Composite Search Keys Composite Search Keys: Search on a combination of fields. Equality query: Every field value is equal to a constant value. E.g. wrt <sal,age> index: age=20 and sal =75 Range query: Some field value is not a constant. E.g.: age =20; or age=20 and sal > 10 Examples of composite key indexes using lexicographic order. 11,80 11 12,10 12 name age sal 12,20 12 13,75 bob 12 10 13 <age, sal> cal 11 80 <age> joe 12 20 10,12 sue 13 75 10 20,12 Data records sorted by name 20 75,13 75 80,11 80 <sal, age> <sal> Data entries in index sorted by <sal,age> Data entries sorted by <sal> 13
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B+ Trees Search trees Idea in B Trees: Idea in B+ Trees:
make 1 node = 1 block Idea in B+ Trees: Make leaves into a linked list (range queries are easier)
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B+ Trees Basics Parameter d = the degree
Each node has >= d and <= 2d keys (except root) Each leaf has >=d and <= 2d keys: 30 120 240 Keys k < 30 Keys 30<=k<120 Keys 120<=k<240 Keys 240<=k 40 50 60 Next leaf 40 50 60
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B+ Tree Example d = 2 Find the key 40 80 40 80 20 60 100 120 140 20 < 40 60 10 15 18 20 30 40 50 60 65 80 85 90 30 < 40 40 10 15 18 20 30 40 50 60 65 80 85 90
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Searching a B+ Tree Exact key values: Range queries: Start at the root
Proceed down, to the leaf Range queries: As above Then sequential traversal Select name From people Where age = 25 Select name From people Where 20 <= age and age <= 30
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B+ Tree Design How large d ? Example: 2d x 4 + (2d+1) x 8 <= 4096
Key size = 4 bytes Pointer size = 8 bytes Block size = 4096 byes 2d x 4 + (2d+1) x 8 <= 4096 d = 170
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B+ Trees in Practice Typical order: 100. Typical fill-factor: 67%.
average fanout = 133 Typical capacities: Height 4: 1334 = 312,900,700 records Height 3: 1333 = 2,352,637 records Can often hold top levels in buffer pool: Level 1 = page = Kbytes Level 2 = pages = Mbyte Level 3 = 17,689 pages = 133 MBytes
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Insertion in a B+ Tree Insert (K, P) Find leaf where K belongs, insert
If no overflow (2d keys or less), halt If overflow (2d+1 keys), split node, insert in parent: If leaf, keep K3 too in right node When root splits, new root has 1 key only parent parent K3 K1 K2 K3 K4 K5 P0 P1 P2 P3 P4 p5 K1 K2 P0 P1 P2 K4 K5 P3 P4 p5
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Insertion in a B+ Tree Insert K=19 80 20 60 100 120 140 10 15 18 20 30
50 60 65 80 85 90 10 15 18 20 30 40 50 60 65 80 85 90
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Insertion in a B+ Tree After insertion 80 20 60 100 120 140 10 15 18
19 20 30 40 50 60 65 80 85 90 10 15 18 19 20 30 40 50 60 65 80 85 90
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Insertion in a B+ Tree Now insert 25 80 20 60 100 120 140 10 15 18 19
30 40 50 60 65 80 85 90 10 15 18 19 20 30 40 50 60 65 80 85 90
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Insertion in a B+ Tree After insertion 80 20 60 100 120 140 10 15 18
19 20 25 30 40 50 60 65 80 85 90 10 15 18 19 20 25 30 40 50 60 65 80 85 90
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Insertion in a B+ Tree But now have to split ! 80 20 60 100 120 140 10
15 18 19 20 25 30 40 50 60 65 80 85 90 10 15 18 19 20 25 30 40 50 60 65 80 85 90
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Insertion in a B+ Tree After the split 80 20 30 60 100 120 140 10 15
18 19 20 25 30 40 50 60 65 80 85 90 10 15 18 19 20 25 30 40 50 60 65 80 85 90
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Deletion from a B+ Tree Delete 30 80 20 30 60 100 120 140 10 15 18 19
25 30 40 50 60 65 80 85 90 10 15 18 19 20 25 30 40 50 60 65 80 85 90
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Deletion from a B+ Tree After deleting 30 May change to 40, or not 80
20 30 60 100 120 140 10 15 18 19 20 25 40 50 60 65 80 85 90 10 15 18 19 20 25 40 50 60 65 80 85 90
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Deletion from a B+ Tree Now delete 25 80 20 30 60 100 120 140 10 15 18
19 20 25 40 50 60 65 80 85 90 10 15 18 19 20 25 40 50 60 65 80 85 90
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Deletion from a B+ Tree After deleting 25 Need to rebalance Rotate 80
20 30 60 100 120 140 10 15 18 19 20 40 50 60 65 80 85 90 10 15 18 19 20 40 50 60 65 80 85 90
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Deletion from a B+ Tree Now delete 40 80 19 30 60 100 120 140 10 15 18
50 60 65 80 85 90 10 15 18 19 20 40 50 60 65 80 85 90
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Deletion from a B+ Tree After deleting 40 Rotation not possible
Need to merge nodes 80 19 30 60 100 120 140 10 15 18 19 20 50 60 65 80 85 90 10 15 18 19 20 50 60 65 80 85 90
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Deletion from a B+ Tree Final tree 80 19 60 100 120 140 10 15 18 19 20
50 60 65 80 85 90 10 15 18 19 20 50 60 65 80 85 90
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In Class Suppose the B+ tree has depth 4 and degree d=200
How many records does the relation have (maximum) ? How many index blocks do we need to read and/or write during: A key lookup An insertion A deletion
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