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Challenging problems Area between curves.

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1 Challenging problems Area between curves

2 Starter: solve the following simultaneous equations
Areas between curves KUS objectives BAT use integration to find the area between a curve and the x-axis BAT use integration to find the area between a line and curve or between two curves Starter: solve the following simultaneous equations 𝑦= π‘₯ 2 +5π‘₯+4 𝑦=π‘₯+1 π‘₯ 2 + 𝑦 2 =13 𝑦=π‘₯+1

3 To calculate the Area between a Curve and a Straight Line
Introduction To calculate the Area between a Curve and a Straight Line To work out the Region between 2 lines, you work out the region below the β€˜higher’ line, and subtract the region below the β€˜lower’ line y Region R y2 y1 x a b οƒ  Sometimes you will need to work out the values of a and b οƒ  Sometimes a and b will be different for each part οƒ  MAKE SURE you put y1 and y2 the correct way around!

4 Expand and rearrange (higher equation – lower equation)
WB13 Below is a diagram showing the equation y = x, as well as the curve y = x(4 – x). Find the Area bounded by the line and the curve. y 1) Find where the lines cross (set the equations equal) y = x Expand the bracket R Subtract x Factorise x 3 2) Integrate to find the Area y = x(4 – x) Expand and rearrange (higher equation – lower equation) Integrate Split and Substitute

5 WB14 The diagram shows a sketch of the curve with equation y = x(x – 3), and the line with Equation 2x. Calculate the Area of region R. 1) Work out the coordinates of the major points.. x y y = x(x – 3) y = 2x R O A B C As the curve is y = x(x – 3), the x-coordinate at C = 3 οƒ  Set the equations equal to find the x-coordinates where they cross… Expand Bracket Subtract 2x Factorise 2) Area of the Triangle… The Area we want will be The Area of Triangle OAB – The Area ACB, under the curve. Substitute values in Work it out!

6 Area of Triangle OAB – The Area ACB
WB14 continued The diagram shows a sketch of the curve with equation y = x(x – 3), and the line with Equation 2x. Calculate the Area of region R. 3) Area under the curve Expand Bracket y = x(x – 3) y y = 2x (5,10) Integrate Split and Substitute 16 1/3 R x 3 5 Area of Triangle OAB – The Area ACB 25 - 26/3

7 1) Find the area enclosed between 𝑦= π‘₯ 2 +2π‘₯+3 and 𝑦=π‘₯+5
Practice 1 1) Find the area enclosed between 𝑦= π‘₯ 2 +2π‘₯ and 𝑦=π‘₯+5 2) Find the area enclosed between 𝑦= π‘₯ 2 βˆ’2π‘₯ and 𝑦=5βˆ’π‘₯ 3) Find the area enclosed between 𝑦= π‘₯ 2 βˆ’3π‘₯ and 𝑦=5βˆ’π‘₯ Solutions Intersection points (-2, 3) (1, 6) Area = 4.5 Intersection points (-1, 6) (2, 3) Area = 9 2 Intersection points (0, 5) (2, 3) Area = 4 3

8 Practice 1 1) Find the area enclosed between 𝑦= π‘₯ 2 +2π‘₯ and 𝑦=π‘₯+5 π‘–π‘›π‘‘π‘’π‘Ÿπ‘ π‘’π‘π‘‘π‘–π‘œπ‘› π‘π‘œπ‘–π‘›π‘‘π‘  βˆ’2, 3 π‘Žπ‘›π‘‘ (1, 6) π‘₯+5 βˆ’ π‘₯ 2 +2π‘₯+3 =2βˆ’π‘₯βˆ’ π‘₯ 2 βˆ’2 1 2βˆ’π‘₯βˆ’ π‘₯ 2 = 2π‘₯βˆ’ 1 2 π‘₯ 2 βˆ’ 1 3 π‘₯ βˆ’2 = 2(1)βˆ’ βˆ’ 1 3 (1) 3 βˆ’ 2(βˆ’2)βˆ’ βˆ’2 2 βˆ’ 1 3 (βˆ’2) 3 = 2βˆ’ 1 2 βˆ’ 1 3 βˆ’ βˆ’4βˆ’2+ 8 3 = βˆ’ βˆ’ = 9 2

9 Practice 2 2) Find the area enclosed between 𝑦= π‘₯ 2 βˆ’2π‘₯ and 𝑦=5βˆ’π‘₯ π‘–π‘›π‘‘π‘’π‘Ÿπ‘ π‘’π‘π‘‘π‘–π‘œπ‘› π‘π‘œπ‘–π‘›π‘‘π‘  βˆ’1, 6 π‘Žπ‘›π‘‘ (2, 3) 5βˆ’π‘₯ βˆ’ π‘₯ 2 βˆ’2π‘₯+3 =2+π‘₯βˆ’ π‘₯ 2 βˆ’ π‘₯βˆ’ π‘₯ 2 = 2π‘₯ π‘₯ 2 βˆ’ 1 3 π‘₯ βˆ’1 = 4+2βˆ’ 8 3 βˆ’ βˆ’ = βˆ’ βˆ’ = 9 2

10 = 4 3 3) Find the area enclosed between 𝑦= π‘₯ 2 βˆ’3π‘₯+5 and 𝑦=5βˆ’π‘₯
Practice 3 3) Find the area enclosed between 𝑦= π‘₯ 2 βˆ’3π‘₯ and 𝑦=5βˆ’π‘₯ π‘–π‘›π‘‘π‘’π‘Ÿπ‘ π‘’π‘π‘‘π‘–π‘œπ‘› π‘π‘œπ‘–π‘›π‘‘π‘  0, 5 π‘Žπ‘›π‘‘ (2, 3) 5βˆ’π‘₯ βˆ’ π‘₯ 2 βˆ’3π‘₯+5 =2π‘₯βˆ’ π‘₯ 2 0 2 2π‘₯βˆ’ π‘₯ 2 = π‘₯ 2 βˆ’ 1 3 π‘₯ = 4βˆ’ 8 3 βˆ’ 0 = 4 3

11 One thing to improve is –
KUS objectives BAT use integration to find the area between a curve and the x-axis BAT use integration to find the area between a line and curve or between two curves self-assess One thing learned is – One thing to improve is –

12 END


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