1. Find: FR [kN] on the door Twater= 30 C 1.5 [m] door water wall 1 [m]
hinge
door
14.7
17.1
25.7
36.7
1.5 [m]
Find the reaction force on the the door, in kiloNewtons. [pause]. In this problem, water is filled to a depth of --- FR

2. Find: FR [kN] on the door Twater= 30 C 1.5 [m] door water wall 1 [m]
hinge
door
14.7
17.1
25.7
36.7
1.5 [m]
2.5 meters, where the bottom 1.5 meters, --- FR

3. Find: FR [kN] on the door Twater= 30 C 1.5 [m] door water wall 1 [m]
hinge
door
14.7
17.1
25.7
36.7
1.5 [m]
is held back by a door, and the top meter is held back, --- FR

4. Find: FR [kN] on the door Twater= 30 C 1.5 [m] door water wall 1 [m]
hinge
door
14.7
17.1
25.7
36.7
1.5 [m]
by a wall, where, the door and the wall are connected by a hinge --- FR

5. Find: FR [kN] on the door Twater= 30 C 1.5 [m] door water wall 1 [m]
hinge
door
14.7
17.1
25.7
36.7
1.5 [m]
[pause]. The temperature of the water is given as, --- FR

6. Find: FR [kN] on the door Twater= 30 C 1.5 [m] door water wall 1 [m]
hinge
door
14.7
17.1
25.7
36.7
1.5 [m]
30 degrees celsius, and the door measures --- FR

7. Find: FR [kN] on the door Twater= 30 C 1.5 [m] door water wall 1 [m]
hinge
door
14.7
17.1
25.7
36.7
1.5 [m]
1 meter wide, by 1.5 meters tall. [pause] The reaction force, --- FR

8. Find: FR [kN] on the door FR = PC *A water wall 1.0 [m] 1 [m] hinge
F R, equals, P C, times A. Where P C, represents, -----
hinge
door
1.5 [m]
1.5 [m]
door FR o
Twater= 30 C

9. Find: FR [kN] on the door FR = PC *A reaction force centroidal
pressure
water
wall
1 [m]
1.0 [m]
the pressure at the centroid of the door, and A represents, ---
hinge
door
1.5 [m]
1.5 [m]
door FR o
Twater= 30 C

10. Find: FR [kN] on the door FR = PC *A area reaction force centroidal
pressure
water
wall
1 [m]
1.0 [m]
the area of the door. [pause] The door is the shape of a rectangle, ---
hinge
door
1.5 [m]
1.5 [m]
door FR o
Twater= 30 C

11. Find: FR [kN] on the door FR = PC *A area reaction force centroidal
pressure
water
wall
1 [m]
1.0 [m]
so we can calculate the area of the door by mulitiplying , ---
hinge
door
1.5 [m]
1.5 [m]
door FR o
Twater= 30 C

12. Find: FR [kN] on the door FR = PC *A area reaction force centroidal
pressure
Adoor= wdoor * hdoor
water
wall
1 [m]
1.0 [m]
the width of the door by the height of the door, which equals, ---
hinge
door
1.5 [m]
1.5 [m]
door FR o
Twater= 30 C

13. Find: FR [kN] on the door FR = PC *A area reaction force centroidal
pressure
Adoor= 1.5 [m2]
Adoor= wdoor * hdoor
water
wall
1 [m]
1.0 [m]
1.5 meters squared. [pause] The pressure acting upon, ---
hinge
door
1.5 [m]
1.5 [m]
door FR o
Twater= 30 C

14. Find: FR [kN] on the door Adoor= 1.5 [m2] FR = PC *A reaction force
PC = ρ * g * yC
water
wall
1 [m]
1.0 [m]
the centroid of the door, equals, rho, g, y c. In this equation, ---
hinge
door
1.5 [m]
1.5 [m]
door FR o
Twater= 30 C

15. Find: FR [kN] on the door Adoor= 1.5 [m2] FR = PC *A reaction force
PC = ρ * g * yC
centroidal pressure
density
water
wall
1 [m]
1.0 [m]
rho represents, density, [pause] g represents, ---
hinge
door
1.5 [m]
1.5 [m]
door FR o
Twater= 30 C

16. Find: FR [kN] on the door Adoor= 1.5 [m2] FR = PC *A acceleration
reaction
force
PC = ρ * g * yC
centroidal pressure
density
water
wall
1 [m]
1.0 [m]
the gravitational acceleration constant, and y c represents,
hinge
door
1.5 [m]
1.5 [m]
door FR o
Twater= 30 C

17. Find: FR [kN] on the door Adoor= 1.5 [m2] FR = PC *A acceleration
reaction
force
PC = ρ * g * yC
centroidal pressure
depth
density
to centroid
water
1 [m]
1.0 [m]
the depth from the surface of the water, to the centroid of the door. We can look up the density of water --- yC
1.5 [m]
1.5 [m]
door FR
door o
Twater= 30 C

18. Find: FR [kN] on the door Adoor= 1.5 [m2] FR = PC *A acceleration
reaction
force
PC = ρ * g * yC
centroidal pressure
depth
density
to centroid
water
temperature
water density
1 [m] o
25 C
997.1 [kg/m3]
from a table, for different temperatures. Sinece we’ve been given the water is --- yC o
30 C
995.7 [kg/m3]
1.5 [m] o
40 C
992.3 [kg/m3] FR o
Twater= 30 C

19. Find: FR [kN] on the door Adoor= 1.5 [m2] FR = PC *A acceleration
reaction
force
PC = ρ * g * yC
centroidal pressure
depth
density
to centroid
water
temperature
water density
1 [m] o
25 C
997.1 [kg/m3]
30 degrees celcius, then we’ll use a water density of, --- yC o
30 C
995.7 [kg/m3]
1.5 [m] o
40 C
992.3 [kg/m3] FR o
Twater= 30 C

20. Find: FR [kN] on the door Adoor= 1.5 [m2] FR = PC *A acceleration
reaction
force
PC = ρ * g * yC
centroidal pressure
depth
density
to centroid
water
temperature
water density
1 [m] o
25 C
997.1 [kg/m3]
995.7 kilograms per meters cubed. In metric units, the acceleration, ---- yC o
30 C
995.7 [kg/m3]
1.5 [m] o
40 C
992.3 [kg/m3] FR o
Twater= 30 C

21. Find: FR [kN] on the door Adoor= 1.5 [m2] FR = PC *A acceleration
reaction
force
PC = ρ * g * yC
centroidal pressure
density
9.81 [m/s2]
water
temperature
water density
1 [m] o
25 C
997.1 [kg/m3]
g, equals 9.81 meters per second squared. And the depth to the centroid, y c, --- yC o
30 C
995.7 [kg/m3]
1.5 [m] o
40 C
992.3 [kg/m3] FR o
Twater= 30 C

22. Find: FR [kN] on the door Adoor= 1.5 [m2] FR = PC *A reaction
9.81 [m/s2]
force
PC = ρ * g * yC
centroidal pressure
depth
ρ= [kg/m3]
to centroid
water
yC = y1 + y2 y1
1 [m] yC
1.0 [m]
equals the depth from the water surface, to the hinge, plus, --- y2
1.5 [m]
1.5 [m]
door FR

23. Find: FR [kN] on the door Adoor= 1.5 [m2] FR = PC *A reaction
9.81 [m/s2]
force
PC = ρ * g * yC
centroidal pressure
depth
ρ= [kg/m3]
to centroid
water
yC = y1 + y2 y1
1 [m] yC
1.0 [m]
the vertical distance from the hinge, to the centroid of the door. 1 meter, plus, --- y2
1.5 [m]
1.5 [m]
door FR

24. Find: FR [kN] on the door Adoor= 1.5 [m2] FR = PC *A reaction
9.81 [m/s2]
force
PC = ρ * g * yC
centroidal pressure
depth
ρ= [kg/m3]
to centroid
water
yC = y1 + y2 y1
1 [m] yC
1.0 [m]
half the door height, which is 0.75 meters, equals, ---
y2=dheight/2 y2
1.5 [m]
1.5 [m]
door FR
y2=0.75 [m]

25. Find: FR [kN] on the door Adoor= 1.5 [m2] FR = PC *A reaction
9.81 [m/s2]
force
PC = ρ * g * yC
centroidal pressure
ρ= [kg/m3]
yc=1.75 [m]
water
yC = y1 + y2 y1
1 [m] yC
1.0 [m]
a depth to centroid, of, 1.75 meters. [pause] This makes the centroidal pressure, P c, ---
y2=dheight/2 y2
1.5 [m]
1.5 [m]
door FR
y2=0.75 [m]

26. Find: FR [kN] on the door Adoor= 1.5 [m2] FR = PC *A reaction
9.81 [m/s2]
force
PC = ρ * g * yC
centroidal pressure
ρ= [kg/m3]
yc=1.75 [m]
water
PC = 17,094 [kg/m*s2] y1
1 [m] yC
equal to 17,094 kilogram per meter second squared. [pause] When plugged in for variable P c, --- y2
1.5 [m]
door FR

27. Find: FR [kN] on the door Adoor= 1.5 [m2] FR = PC *A reaction
9.81 [m/s2]
force
PC = ρ * g * yC
centroidal pressure
ρ= [kg/m3]
yc=1.75 [m]
water
PC = 17,094 [kg/m*s2] y1
1 [m] yC
this makes the reaction force on the door equal to, --- y2
1.5 [m]
door FR

28. Find: FR [kN] on the door Adoor= 1.5 [m2] FR = PC *A reaction
9.81 [m/s2]
force
PC = ρ * g * yC
centroidal pressure
ρ= [kg/m3]
yc=1.75 [m]
water
PC = 17,094 [kg/m*s2] y1
1 [m] yC
25,641 kilogram meters per second squred. After converting to units of kiloNewtons, ---
FR = 25,641 [kg*m/s2] y2
1.5 [m] FR

29. Find: FR [kN] on the door * Adoor= 1.5 [m2] FR = PC *A reaction
9.81 [m/s2]
force
PC = ρ * g * yC
centroidal pressure
ρ= [kg/m3]
yc=1.75 [m]
water
PC = 17,094 [kg/m*s2] y1
1 [m] yC
FR = 25,641 [kg*m/s2]
the reaction force on the door equals, --- y2
kN*s2 1
1.5 [m] *
1,000
kg*m FR

30. Find: FR [kN] on the door * Adoor= 1.5 [m2] FR = PC *A reaction
9.81 [m/s2]
force
PC = ρ * g * yC
centroidal pressure
ρ= [kg/m3]
yc=1.75 [m]
water
PC = 17,094 [kg/m*s2] y1
1 [m] yC
FR = 25,641 [kg*m/s2]
25.6 kiloNewtons. [pause] y2
kN*s2 1
1.5 [m] *
1,000
kg*m FR
FR = 25.6 [kN]

31. Find: FR [kN] on the door Adoor= 1.5 [m2] FR = PC *A reaction
9.81 [m/s2]
force
PC = ρ * g * yC
centroidal pressure
ρ= [kg/m3]
yc=1.75 [m]
water
14.7
17.1
25.7
36.7 y1
1 [m] yC
When reviewing the possible solutions, --- y2
1.5 [m] FR
FR = 25.6 [kN]

32. Find: FR [kN] on the door Adoor= 1.5 [m2] FR = PC *A reaction
9.81 [m/s2]
force
PC = ρ * g * yC
centroidal pressure
ρ= [kg/m3]
yc=1.75 [m]
water
14.7
17.1
25.7
36.7 y1
1 [m] yC
the answer is C. [fin]
answerC y2
1.5 [m] FR
FR = 25.6 [kN]

33. * ΔP13=-ρA* g * (hAB-h1)+… depth to centroid kg*cm3 1,000 g * m3
a monometer contains 5 different fluids, which include, ---
kg*cm3
1,000 *
g * m3