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= 4 7 x = 4 27 x = 4 277 x How many of you would agree with these statements? And you can be honest, I’m a recorded voice, I can’t really see you. Is multiplying.

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Presentation on theme: "= 4 7 x = 4 27 x = 4 277 x How many of you would agree with these statements? And you can be honest, I’m a recorded voice, I can’t really see you. Is multiplying."— Presentation transcript:

1 = 4 7 x = 4 27 x = 4 277 x How many of you would agree with these statements? And you can be honest, I’m a recorded voice, I can’t really see you. Is multiplying numbers with more than one digit really that much harder than multiplying single digit numbers?

2 By now, you understand that multiplication means equal groups
By now, you understand that multiplication means equal groups. So 4 x 7 means 4 groups with 7 in each group. One strategy you could use if you’re a little behind on your facts would be to count by groups of 7s, which, by now we expect you’re able to do.

3 But what happens when one of the factors we’re multiplying is a double digit number, like- say 27? Well, we know we still have our 4 equal groups but this time each group has 27 apples. So, all of the sudden- counting by 27s isn’t looking like so much fun. I mean, I heart-eyes math- like: if math were a person I’d absolutely marry it. I can get from 27 to 54 but after that I have to add 20 then add 7 to get to 81 and from there- forget it. I’m adding to get 108. So trying to solve a single by double digit multiplication problem ends up equaling: Well, it ends up equaling you frowny-facing math.

4 And we want you landing things on Mars, not frowny-facing math
And we want you landing things on Mars, not frowny-facing math. So hopefully, today you’ll find some strategies that will help you heart-eyes math

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6 Let’s Review 7 x 7 5 x = 35 = 21 You know that if you can’t remember a multiplication fact, a good strategy to for finding the correct amount is to recompose one of the groups. In this case, we’re going to pull apart the group of 8. Now we have 5 groups of 7 which equals 35 and we’re left with 3 groups of 7 equalling 21. And if is 8 then 5 groups of 7 totaling 35 added to 3 groups of 7 totaling 21 will equal 8 groups of 7 for a grand total of 56

7 When it comes to multi-digit numbers, this strategy is even more fun than with that measly 7x8. So here’s how this all works. Right now the way our array is set up, to get the total you’d have to count by 27s, which is certainly one way to do it. But, let’s just take a look at the number 27 for a moment.

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9 4 x 4 x 4 x Except now I’m calling it , kind of like if I were to spell out G-E-O-R-G-E instead of saying the name George. Now, instead of 4 groups of 27, I need 4 groups of 10 which hopefully isn’t too exhausting for you. Another 4 groups of 10- well it certainly isn’t now. And finally 4 groups of 7 which equals 28.

10 10 7 4 x + 40 Now all I have to do is put these easily manageable groups back together. I’m choosing to start with with because- come on, 4+4- not exactly something you lose recess over. So I end up with 80 and 28. Ohhh, finally- a challenge. 28 made of plus plus that

11 = 4 x 27 So, 4 x 27 that’s 108

12 4 x 4 x Let’s take a break right here so that I can show you a surprisingly common error- uhhuh- some students make. And then, I’ll show you an even easier way to solve our 4 x 27 problem. I know, you’re probably thinking that there is no possible way there could be an even easier way than what I just showed you. Let’s look at 4 x 17. Sometimes those “jump the gun” students (you know who you are) in a rush look at this and think- all I’ll just split up 17 and that will make my life so much easier. So they recompose 17 like this. And then they multiply each piece by 4 add up the total, pass it in- and I’m left slowly counting backwards from 10 while taking deep breaths.

13 Let’s get this clear. This is George. This is Alexander
Let’s get this clear. This is George. This is Alexander. George wishes he was the one worth 10 and Alexander wouldn’t be caught dead on a measly one. George does not like to be called Alexander and Alexander certainly does not like to be called George.

14 4 x 4 x This. This is Alexander. That is George. Would you rather have an Alexander or a George? We’re going to go ahead fix that so Secretary Hamilton stops rolling over in his grave. And when we do. This 4 becomes a 40 which significantly changes our previous answer. Okay, back to that easier way.

15 You remember our 4 groups of 27 situation?

16 This time when we look at 27 we’re going to save ourselves a step.

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18 4 x 4 x Now we’re thinking smarter. 4 x 2 is 8 and 20 is ten times the size of 2. So what’s ten times the size of 8? Yep, 80 alright. And nothing new over here. 4 x 7 is still 28.

19 7 4 x 20 All that’s left, we cram these guys back together and...

20 = 4 x 27 108 We’ve seen yet another way that 4 x 27 equals 108.

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22 = 6 x 24

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24 20 6 x = 4 6 x = LearnZillion Notes:
--The “Guided Practice” should include 1 practice problem that targets the skill that was used in the Core Lesson. Use the same vocabulary and process you used in the original lesson to solve this problem. You’ll be making a video in which you solve this question using your tablet and pen, so all you need to do is write the question on this slide.

25 = 6 x 24

26 = 3 x 14 Then, draw rectangles around where you’d
split the array into manageable multiples

27 = 4 x 22 Then, draw rectangles around where you’d
split the array into manageable multiples

28

29 = 4 x 37

30 = 4 x 37


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