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Published byRoss Jordan Modified over 6 years ago
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Linear simultaneous Equations: Eliminating the variable π₯ (step 3)
Silent Teacher Intelligent Practice Narration Your Turn 2π¦+3π₯=18 6π¦+3π₯=30 6π¦β3π₯=30 2π¦+π₯=18 6π¦βπ₯=30 Practice
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5π₯+4π¦=23 5π₯+2π¦=19 5π₯+8π¦=31 5π₯+2π¦=19 β6π₯+4π¦=23 6π₯+2π¦=19 6π₯+8π¦=31
Worked Example Your Turn Eliminate a variable from the following sets of equations: Eliminate a variable from the following sets of equations: 5π₯+4π¦=23 5π₯+2π¦=19 5π₯+8π¦=31 5π₯+2π¦=19 β6π₯+4π¦=23 6π₯+2π¦=19 6π₯+8π¦=31 β6π₯+2π¦=19
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1 3 π₯+2π¦=β18 1 3 π₯+6π¦=30 π₯+2π¦=β18 βπ₯+6π¦=β30 β4π₯+2π¦=β18 β4π₯+4π¦=β30 4π₯+π¦=β18 β4π₯+2π¦=β30 π¦+π₯=β18 π¦βπ₯=β30 5π₯+2π¦=18 5π₯+6π¦=30 4π₯+2π¦=18 4π₯+6π¦=30 2π₯+2π¦=18 β2π₯+6π¦=30 βπ₯+2π¦=18 βπ₯+6π¦=30 0.5π₯+2π¦=18 0.5π₯+6π¦=30
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4π¦=12 8π¦=48 4π¦=12 4π¦=48 8π¦=β48 2π¦=β12 3π¦=β48 2π¦=β48 1 3 π₯+2π¦=β18
1 3 π₯+6π¦=30 π₯+2π¦=β18 βπ₯+6π¦=β30 β4π₯+2π¦=β18 β4π₯+4π¦=β30 4π₯+π¦=β18 β4π₯+2π¦=β30 π¦+π₯=β18 π¦βπ₯=β30 5π₯+2π¦=18 5π₯+6π¦=30 4π₯+2π¦=18 4π₯+6π¦=30 2π₯+2π¦=18 β2π₯+6π¦=30 βπ₯+2π¦=18 βπ₯+6π¦=30 0.5π₯+2π¦=18 0.5π₯+6π¦=30 4π¦=48 8π¦=β48 2π¦=β12 4π¦=12 3π¦=β48 2π¦=β48
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