1. Factoring Trinomials Day 2

2. Factoring Trinomials (a>1)
Factor. 3x2 + 14x + 8
This time, the x2 term DOES have a coefficient (other than 1)!
Step 1: Multiply 3 • 8 = 24 (the leading coefficient & constant).
24 = 1 • 24
= 2 • 12
= 3 • 8
= 4 • 6
Step 2: List all pairs of numbers that multiply to equal that product, 24.
Step 3: Which pair adds up to 14?

3. Factoring Trinomials (Method 2*)
Factor. 3x2 + 14x + 8
Step 4: Write temporary factors with the two numbers.
( x )( x ) 2 12 3 3
Step 5: Put the original leading coefficient (3) under both numbers. 4 2
( x )( x ) 12 3
Step 6: Reduce the fractions, if possible. 2
( x )( x ) 4 3
( 3x + 2 )( x + 4 )
Step 7: Move denominators in front of x.

4. Factoring Trinomials (Method 2*)
Factor. 3x2 + 14x + 8
You should always check the factors by distributing, especially since this process has more than a couple of steps.
( 3x + 2 )( x + 4 )
= 3x • x + 3x • • x + 2 • 4
= 3x x + 8 √
3x2 + 14x + 8 = (3x + 2)(x + 4)

5. Factoring Trinomials (Method 2*)
Factor 3x2 + 11x + 4
This time, the x2 term DOES have a coefficient (other than 1)!
Step 1: Multiply 3 • 4 = 12 (the leading coefficient & constant).
12 = 1 • 12
= 2 • 6
= 3 • 4
Step 2: List all pairs of numbers that multiply to equal that product, 12.
Step 3: Which pair adds up to 11?
None of the pairs add up to 11, this trinomial can’t be factored; it is PRIME.

6. Factor These Trinomials!
Factor each trinomial, if possible. The first four do NOT have leading coefficients, the last two DO have leading coefficients. Watch out for signs!! Turn these in before leaving today!!!!
1) t2 – 4t – 21
2) x2 + 12x + 32
3) x2 –10x + 24
4) x2 + 3x – 18
5) 2x2 + x – 21
6) 3x2 + 11x + 10

7. Solution #1: t2 – 4t – 21 t2 – 4t – 21 = (t + 3)(t - 7)
1) Factors of -21:
1 • -21, -1 • 21
3 • -7, -3 • 7
2) Which pair adds to (- 4)?
3) Write the factors.
t2 – 4t – 21 = (t + 3)(t - 7)

8. Solution #2: x2 + 12x + 32 x2 + 12x + 32 = (x + 4)(x + 8)
1) Factors of 32:
1 • 32
2 • 16
4 • 8
2) Which pair adds to 12 ?
3) Write the factors.
x2 + 12x + 32 = (x + 4)(x + 8)

9. Solution #3: x2 - 10x + 24 x2 - 10x + 24 = (x - 4)(x - 6)
1) Factors of 32:
1 • 24
2 • 12
3 • 8
4 • 6
-1 • -24
-2 • -12
-3 • -8
-4 • -6
2) Which pair adds to -10 ?
None of them adds to (-10). For the numbers to multiply to +24 and add to -10, they must both be negative!
3) Write the factors.
x2 - 10x + 24 = (x - 4)(x - 6)

10. Solution #4: x2 + 3x - 18 x2 + 3x - 18 = (x - 3)(x + 18)
1) Factors of -18:
1 • -18, -1 • 18
2 • -9, -2 • 9
3 • -6, -3 • 6
2) Which pair adds to 3 ?
3) Write the factors.
x2 + 3x - 18 = (x - 3)(x + 18)

11. Solution #5: 2x2 + x - 21 2x2 + x - 21 = (x - 3)(2x + 7)
1) Multiply 2 • (-21) = - 42; list factors of - 42.
1 • -42, -1 • 42
2 • -21, -2 • 21
3 • -14, -3 • 14
6 • -7, -6 • 7
2) Which pair adds to 1 ?
3) Write the temporary factors.
( x - 6)( x + 7) 2 2
4) Put “2” underneath. 3
( x - 6)( x + 7) 2
5) Reduce (if possible).
6) Move denominator(s)in front of “x”.
( x - 3)( 2x + 7)
2x2 + x - 21 = (x - 3)(2x + 7)

12. Solution #6: 3x2 + 11x + 10 3x2 + 11x + 10 = (3x + 5)(x + 2)
1) Multiply 3 • 10 = 30; list factors of 30.
1 • 30
2 • 15
3 • 10
5 • 6
2) Which pair adds to 11 ?
3) Write the temporary factors.
( x + 5)( x + 6) 3 3
4) Put “3” underneath. 2
( x + 5)( x + 6) 3
5) Reduce (if possible).
6) Move denominator(s)in front of “x”.
( 3x + 5)( x + 2)
3x2 + 11x + 10 = (3x + 5)(x + 2)