1. 2.1(c) Notes: Quadratic Functions
Date:
2.1(c) Notes: Quadratic Functions
Lesson Objective: Find the maximum or minimum, the A/S and y-intercept from a quadratic equation
CCSS: A.SSE.3a, A.REI.1
You will need: a calculator
This is Jeopardy!!!:
This is the graph of
y = 4x² – 4x + 1.

2. Direction, +a up, -a down: y-int, f(0) = c: A/S: x = −b 2a =
Lesson 1: Using a, b and c
Find the direction, the y-intercept, the equation of the A/S, the vertex, and the domain and range. Deter-mine whether it has a maximum or a minimum.
#6 y = 4x² – 4x + 1
Direction, +a up, -a down:
y-int, f(0) = c:
A/S: x = −b 2a =
V: −b 2a , 𝑓 −b 2a =
Max or Min: y =
Domain: {x| } Range: {y| }

3. Direction, +a up, -a down: y-int, f(0) = c: A/S: x = −b 2a =
Lesson 1: Using a, b and c
Find the direction, the y-intercept, the equation of the A/S, the vertex, and the domain and range. Deter-mine whether it has a maximum or a minimum.
#5 y = -2x² – 8x – 5
Direction, +a up, -a down:
y-int, f(0) = c:
A/S: x = −b 2a =
V: −b 2a , 𝑓 −b 2a =
Max or Min: y = 𝑓 −b 2a
Domain: {x| } Range: {y| }

4. Direction, +a up, -a down: y-int, f(0) = c: A/S: x = −b 2a =
Lesson 1: Using a, b and c
Find the direction, the y-intercept, the equation of the A/S, the vertex, and the domain and range. Deter-mine whether it has a maximum or a minimum.
#4 y = x² – 9
Direction, +a up, -a down:
y-int, f(0) = c:
A/S: x = −b 2a =
V: −b 2a , 𝑓 −b 2a =
Max or Min: y =
Domain: {x| } Range: {y| }

5. Lesson 1: Using a, b and c #9 y = 3 2 x² + 4x – 9 A/S: x = −b 2a =
Find the direction, the y-intercept, the equation of the A/S, the vertex, and the domain and range. Deter-mine whether it has a maximum or a minimum.
#9 y = 3 2 x² + 4x – 9
Direction, +a up, -a down:
y-int, f(0) = c:
A/S: x = −b 2a =
V: −b 2a , 𝑓 −b 2a =
Max or Min: y = 𝑓 −b 2a
Domain: {x| } Range: {y| }

6. 2.1(c): Do I Get It? Yes or No 1.(#7) y = 5x² – 2x + 2
Find the direction, the y-intercept, the equation of the A/S, the vertex, and the domain and range. Determine whether it has a maximum or a minimum.
1.(#7) y = 5x² – 2x + 2
2.(#8) y = -x² + 5x – 10
Direction, +a up, -a down:
y-int, f(0) = c:
A/S: x = −b 2a =
V: −b 2a , 𝑓 −b 2a =
Max or Min: y = 𝑓 −b 2a
Domain: {x| } Range: {y| }