1. Group Members: Evan Hudspeth Stuart Haase Charlie Gang Dave Dickenson
Big POPa
Group Members:
Evan Hudspeth
Stuart Haase
Charlie Gang
Dave Dickenson

2. Initial Step

3. Spin It! τ=F·r F=m·a m= 0.032 slugs r= 0.167 ft
The acceleration was found by constant acceleration equation:
V2 2=V12+2ad
d is the distance the ball travels which is ft.
V2= 4.79 ft/s V1= 0 ft/s
(4.79 ft/s)2= (0 ft/s)2 + 2a(1.417 ft)
a= 8.13 ft/s2
F= (0.032 slugs) (8.13 ft/s2) = lb
τ = (0.167 ft)(0.026 lb)= ft-lb

4. The POP
mgh = ½mV2
mass cancels out in the calculation
g= 32.2 ft/s2
h= ft
(32.2 ft/s2)( ft)= ½V2
V= 7.51 ft/s

5. Ball Drop mpd+mbd/mp+mb
(.00014slugs)(1.29ft)+(.0013slugs)(.75ft)/(.00014slugs)+(.0013slugs)
Center of mass=0.88ft from tied side
Y: V22=V12 + 2ad
V1= 0 ft/s
a= 32.2 ft/s2
d=1.29 ft
v22=(0 ft/s) + 2(32.2 ft/s2)(1.29 ft)
V2= 9.11 ft/s
X: V1 (found with conservation of energy)= ft/s
V2= 0 ft/s
d= ft
a= ft/s2 .

6. Final Step Perfectly inelastic collision
mball (Vball) + mcup(Vcup)= (mball+mcup)Vfinal
mball = slugs
Vball =9.11 ft/s
mcup =9.01*10-4
Vcup =0 ft/s
(0.0015slugs)(9.11 ft/s)+0=( slugs) Vfinal
Vfinal= 5.69 ft/s

7. Issues Initial Ramp Hitting the cup reliably
Popping the balloon (placement of needle)
Working out minor kinks