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Model 7: Results and Sensitivity Analysis
Presented by Brian Murphy and Scott Lichtor
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Overview Sensitivity Analysis Overview Review of Model
Solution to the Model Post-Optimality Adjustments Changing Storage Costs Changing Overtime Constraints Conclusion
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Sensitivity Analysis Overview
Linear programming problems are usually in the form: Z=cTx subject to Ax≤b Where c is your cost vector, x is your decision variable vector, A is your inputs matrix, b is your constraint vector, and Z is your objective value. After finding a solution, conditions of the problem may change (either A, b, or c may change). Sensitivity analysis entails evaluating if your original solution is still valid with respect to the new conditions. If not, a new optimal solution can be derived that satisfies the new conditions without redoing the Simplex method.
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Review of Model 7 Ice cream plant manufactures containers of ice cream
Meets the demand for ice cream parlors Plant has overtime and regular time costs and constraints Plant can store ice cream for use in later months Storage has a per month cost, but ice cream can be stored indefinitely Goal: minimize costs while satisfying constraints
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Solutions to the Model Containers produced for each month
Total regular time production cost: $737.25 Total overtime production cost: $376.00 Jan Feb Mar Apr May June July Aug Sept Oct Nov Dec Reg Time 75 100 90 80 Over-time 30 40 50 60
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Solutions (cont.) Storage needed for each month
Total storage costs: $51.50 Total costs: $ Jan Feb Mar Apr May June July Aug Sept Oct Nov Dec No. Containers 250 20 55 15
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Observations Overtime production needed more in later months
Storage needed more in earlier months Total storage costs relatively low.
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Post-Optimality Adjustments
Parameters that can be changed: Regular time and overtime production capacities (A matrix) Regular time and overtime costs (c vector) Storage costs (c vector) Total demand (b vector)
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Change Storage Costs Suppose the storage costs decrease from $.1 per month to $.05 per month
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Changing Storage Costs (cont.)
Containers produced in each month Total regular time production cost: $753.50 Overtime: $354.75 Jan Feb Mar Apr May June July Aug Sept Oct Nov Dec Reg. Time 100 90 80 Over-time 5 40 50 60 30
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Changing Storage Costs (cont.)
Storage needed for each month Total storage cost: $28.25 Total Cost: $ Jan Feb Mar Apr May June July Aug Sept Oct Nov Dec No. Containers 245 40 60 10
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Observations from Changing Storage Costs
Storage level increases Storage costs decrease from $51.50 to $28.25 Regular time costs increase from $ to $753.50 Overtime costs decrease from $ to $354.75 Total costs decrease from $ to $
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Changing Overtime Constraints
Now, suppose overtime production constraints decrease to 40 for every month.
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Changing Overtime Constraints
Containers produced in each month Total regular time cost: $759.00 Total overtime cost: $349.25 Jan Feb Mar Apr May June July Aug Sept Oct Nov Dec Reg Time 100 90 80 Over-time 35 40 30
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Changing Overtime Constraints
Storage needed for each month Total storage cost: $96.00 Total cost: $ Jan Feb Mar Apr May June July Aug Sept Oct Nov Dec No. Containers 200 65 120 30
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Observations from Changing Overtime Constraints
Regular time costs increase from $ to $759 Overtime costs decrease from $376 to $349.25 Storage costs increase from $51.50 to $96 Total costs increase from $ to $ Lower overtime constraints cause higher regular time production and higher storage
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Questions;
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