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Published byJevrem Bizjak Modified over 6 years ago
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Some Common Functions and their Graphs – Quadratic Functions
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quadratic functions of x
A function in the form y = ax2 + bx + c or f(x) = ax2 + bx + c, where a, b and c are constants and a 0, is called a quadratic function of x. Example: (i) y = –2x2 + x quadratic functions of x (ii) f(x) = (x + 3)2 + 5
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Graph of y = ax2 + bx + c (a > 0)
axis of symmetry The graph has reflectional symmetry about y x opens upwards for a > 0 a vertical line c The graph and its axis of symmetry intersect at . y-intercept = c a point x-intercepts vertex (It is the minimum point of the graph.) minimum value of y
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Graph of y = ax2 + bx + c (a < 0)
axis of symmetry y x vertex (It is the maximum point of the graph.) maximum value of y opens downwards for a < 0 x-intercepts c y-intercept = c
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Coordinates of the vertex = (–1, 0)
Can you find the axis of symmetry and the coordinates of the vertex of the graph of y = x2 + 2x + 1? axis of symmetry x y 4 3 2 1 1 2 8 6 4 2 y = x2 + 2x + 1 Axis of symmetry: x = –1 vertex Coordinates of the vertex = (–1, 0)
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Follow-up question Consider the graph of y = (x + 1)(5 – 2x). (a) Determine the direction of opening. (b) Find the x-intercept(s) and the y-intercept of the graph. y = (x + 1)(5 – 2x) (a) y = 5x + 5 – 2x2 – 2x ∴ y = –2x2 + 3x + 5 ∵ Coefficient of x2 = –2 0 ∴ The graph opens downwards.
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+ (b) ∵ y = –2x2 + 3x + 5 ∴ The y-intercept of the graph is 5.
The x-intercepts of the graph are the roots of (x + 1)(5 – 2x) = 0. ) 2 5 )( 1 ( = - + x 2 5 or 1 = - + x 2 5 or 1 = - x ∴ The x-intercepts of the graph are –1 and . 2 5
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