Presentation is loading. Please wait.

Presentation is loading. Please wait.

Section 10.3 – Inscribed Angles

Similar presentations


Presentation on theme: "Section 10.3 – Inscribed Angles"— Presentation transcript:

1 Section 10.3 – Inscribed Angles
Chapter 10 – Circles Section 10.3 – Inscribed Angles

2 Unit Goal Use inscribed angles to solve problems.

3 Basic Definitions INSCRIBED ANGLE – an angle whose vertex is on the circle INTERCEPTED ARC – the arc whose endpoints are are on the inscribed angle is an inscribed angle. is the intercepted arc.

4 What Is the Measure of an Inscribed Circle?

5 Theorem 10.8 Measure of an Inscribed Angle
The measure of an inscribed angle is ½ of its intercepted arc.

6 Example Find the measure of the angle or arc: 20º

7 Example Find the measure of the angle or arc: 50º

8 Example 60º

9 Theorem 10.9 If two inscribed angles of a circle intercept the same arc, then the angles are congruent. 60º

10 Properties of Inscribed Polygons
If all the vertices of a polygon lie on a circle, the polygon is INSCRIBED in the circles and the circle is CIRCUMSCRIBED about the polygon

11 Theorems About Inscribed Polygons
If a right triangle is inscribed in a circle, then the hypotenuse is a diameter of the circle. Conversely, if one side of an inscribed triangle is a diameter of the circle, then the triangle is a right triangle and the angle opposite the diameter is the right angle <B is a right angle iff segment AC is a diameter of the circle

12 Theorem 10.11 A quadrilateral can be inscribed in a circle iff its opposite angles are supplementary D, E, F, and G lie on some circle C iff m<D + m<F = 180° AND m<E + m<G = 180°

13 Example Substitute this into the second equation 5x + 2y = 180
In the diagram, ABCD is inscribed in circle P. Find the measure of each angle. ABCD is inscribed in a circle, so opposite angles are supplementary 3x + 3y = 180 and 5x+ 2y = 180 3x + 3y = 180 (solve for x) - 3y y 3x = -3y + 180 3 3 x = -y + 60 Substitute Substitute this into the second equation 5x + 2y = 180 5 (-y + 60) + 2y = 180 -5y y = 180 -3y = -120 y = 40 x = -y + 60 x = = 20

14 Example (cont.) x = 20, y = 40 m<A = 2y, m<B = 3x, m<C = 5x, m<D = 3y m<A = 80° m<B = 60° m<C = 100° m<D = 120°


Download ppt "Section 10.3 – Inscribed Angles"

Similar presentations


Ads by Google