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Section 10.3 – Inscribed Angles
Chapter 10 – Circles Section 10.3 – Inscribed Angles
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Unit Goal Use inscribed angles to solve problems.
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Basic Definitions INSCRIBED ANGLE – an angle whose vertex is on the circle INTERCEPTED ARC – the arc whose endpoints are are on the inscribed angle is an inscribed angle. is the intercepted arc.
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What Is the Measure of an Inscribed Circle?
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Theorem 10.8 Measure of an Inscribed Angle
The measure of an inscribed angle is ½ of its intercepted arc.
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Example Find the measure of the angle or arc: 20º
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Example Find the measure of the angle or arc: 50º
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Example 60º
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Theorem 10.9 If two inscribed angles of a circle intercept the same arc, then the angles are congruent. 60º
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Properties of Inscribed Polygons
If all the vertices of a polygon lie on a circle, the polygon is INSCRIBED in the circles and the circle is CIRCUMSCRIBED about the polygon
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Theorems About Inscribed Polygons
If a right triangle is inscribed in a circle, then the hypotenuse is a diameter of the circle. Conversely, if one side of an inscribed triangle is a diameter of the circle, then the triangle is a right triangle and the angle opposite the diameter is the right angle <B is a right angle iff segment AC is a diameter of the circle
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Theorem 10.11 A quadrilateral can be inscribed in a circle iff its opposite angles are supplementary D, E, F, and G lie on some circle C iff m<D + m<F = 180° AND m<E + m<G = 180°
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Example Substitute this into the second equation 5x + 2y = 180
In the diagram, ABCD is inscribed in circle P. Find the measure of each angle. ABCD is inscribed in a circle, so opposite angles are supplementary 3x + 3y = 180 and 5x+ 2y = 180 3x + 3y = 180 (solve for x) - 3y y 3x = -3y + 180 3 3 x = -y + 60 Substitute Substitute this into the second equation 5x + 2y = 180 5 (-y + 60) + 2y = 180 -5y y = 180 -3y = -120 y = 40 x = -y + 60 x = = 20
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Example (cont.) x = 20, y = 40 m<A = 2y, m<B = 3x, m<C = 5x, m<D = 3y m<A = 80° m<B = 60° m<C = 100° m<D = 120°
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