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REDUCING MATRICES
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A matrix that reduces to this
Can readily be interpreted
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1. Place 1 in the upper left If you follow this order, you will not waste time or go around in circles. 2. Place 0’s in the column under the red 1 3. Place second 1 on the diagonal 4. Place 0’s in the column under the blue 1 5. Place third 1 on the diagonal 6. Place 0 in the column under the green 1 7. Place fourth 1 on the diagonal 8. A 0 in the upper right triangle can be placed at any point after the 1 and the lower 0’s have been placed in its column
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Consider this system. First extract the coefficient matrix
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+2 1 -1 0 -1 L1 becomes: First we want a 1 in this position.
Replace L1 with L L2 L1 becomes:
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+2 L2 becomes 0 -1 -1 -4 Second we want 0’s in these positions.
Replace L2 with L L1 +2 L2 becomes Second we want 0’s in these positions.
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+1 L2 becomes 0 -1 -1 -4 L3 becomes 0 0 1 1
Replace L3 with L L1 +1 L2 becomes Second we want 0’s in these positions. L3 becomes Replace L2 with L L1
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Replace L2 with -1L2 L2 becomes Third we want a 1 in this position.
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Fourth we have a 0 in this position.
And a 1 in this position
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-1 L2 becomes 0 1 0 3 Finally we need 0’s in these positions
Replace L2 with L L3 -1
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L1 becomes Replace L1 with L L2 +1 L2 becomes
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