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Momentum Objectives (Mom. and Energy Unit)
Define and calculate the momentum of an object. Determine the impulse given to an object. Interpret and use force vs. time graphs (Base x Height). Apply conservation of momentum to solve a variety of problems. Distinguish between elastic and inelastic collisions.
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Example 2 On a snow-covered road, a car with a mass of 1100 kg collides head- on with a van having a mass of 2500 kg traveling at 8 m/s. As a result of the collision, the vehicles lock together and immediately come to rest. Calculate the speed of the car immediately before the collisions. [Neglect friction]
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On a snow-covered road, a car with a mass of 1100 kg collides head-on with a van having a mass of 2500 kg traveling at 8 m/s. As a result of the collision, the vehicles lock together and immediately come to rest. Calculate the speed of the car immediately before the collisions. [Neglect friction] Pbefore (kg*m/s) Pafter (kg*m/s) Car Van Total
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Car 1100*Vcar = 1100Vcar Van 2500*(-8) = -20,000 Total
On a snow-covered road, a car with a mass of 1100 kg collides head-on with a van having a mass of 2500 kg traveling at 8 m/s. As a result of the collision, the vehicles lock together and immediately come to rest. Calculate the speed of the car immediately before the collisions. [Neglect friction] Pbefore (kg*m/s) Pafter (kg*m/s) Car 1100*Vcar = 1100Vcar Van 2500*(-8) = -20,000 Total 1100Vcar – 20,000
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Car 1100*Vcar = 1100Vcar Van 2500*(-8) = -20,000 Total
On a snow-covered road, a car with a mass of 1100 kg collides head-on with a van having a mass of 2500 kg traveling at 8 m/s. As a result of the collision, the vehicles lock together and immediately come to rest. Calculate the speed of the car immediately before the collisions. [Neglect friction] Pbefore (kg*m/s) Pafter (kg*m/s) Car 1100*Vcar = 1100Vcar Van 2500*(-8) = -20,000 Total 1100Vcar – 20,000
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Car 1100*Vcar = 1100Vcar Mv = (1100+2500)(0) = 0 Van
On a snow-covered road, a car with a mass of 1100 kg collides head-on with a van having a mass of 2500 kg traveling at 8 m/s. As a result of the collision, the vehicles lock together and immediately come to rest. Calculate the speed of the car immediately before the collisions. [Neglect friction] Pbefore (kg*m/s) Pafter (kg*m/s) Car 1100*Vcar = 1100Vcar Mv = ( )(0) = 0 Van 2500*(-8) = -20,000 Total 1100Vcar – 20,000
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Example 3 A 4-kg rifle fires a 0.02-kg shell with a velocity of 300 m/s. Find the recoil velocity of the rifle.
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A 4-kg rifle fires a 0. 02-kg shell with a velocity of 300 m/s
A 4-kg rifle fires a 0.02-kg shell with a velocity of 300 m/s. Find the recoil velocity of the rifle. Pbefore (kg*m/s) Pafter (kg*m/s) Rifle Shell Total
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A 4-kg rifle fires a 0. 02-kg shell with a velocity of 300 m/s
A 4-kg rifle fires a 0.02-kg shell with a velocity of 300 m/s. Find the recoil velocity of the rifle. Pbefore (kg*m/s) Pafter (kg*m/s) Rifle Shell Total
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A 4-kg rifle fires a 0. 02-kg shell with a velocity of 300 m/s
A 4-kg rifle fires a 0.02-kg shell with a velocity of 300 m/s. Find the recoil velocity of the rifle. Pbefore (kg*m/s) Pafter (kg*m/s) Rifle Mv = (4+0.02)(0) = 0 Shell Total
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A 4-kg rifle fires a 0. 02-kg shell with a velocity of 300 m/s
A 4-kg rifle fires a 0.02-kg shell with a velocity of 300 m/s. Find the recoil velocity of the rifle. Pbefore (kg*m/s) Pafter (kg*m/s) Rifle 4*Vrecoil Shell (.02)(300) = 6 Total 6 + 4Vrecoil
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Questions to go over Conceptual: 7 Calculation: 9, 16
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