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N2(g) + 3H2(g) -> 2NH3(g) ΔHorxn= kJ/mol.

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Presentation on theme: "N2(g) + 3H2(g) -> 2NH3(g) ΔHorxn= kJ/mol."— Presentation transcript:

1 N2(g) + 3H2(g) -> 2NH3(g) ΔHorxn= -92.6 kJ/mol.
Quiz 4 Consider the following reaction N2(g) + 3H2(g) -> 2NH3(g) ΔHorxn= kJ/mol. If 2.0 moles of N2 react with 6 moles of H2 to form NH3, calculate the work done (in joules) against a pressure of 1.0 atm and 25 oC. What is ΔE for this reaction? (Assume the reaction goes to completion.) w= 9.9 kJ ΔE= kJ 2/23/2019 S.A. McFarland©2006

2 2CH3OH(l) + 3O2(g) -> 2CO2(g) + 4H2O(l) ΔHorxn= -1452.8 kJ/mol.
Quiz 4 Methanol is an organic solvent and is also used as fuel in some automobile engines. From the following data, calculate the standard enthalpy of formation of methanol: 2CH3OH(l) + 3O2(g) -> 2CO2(g) + 4H2O(l) ΔHorxn= kJ/mol. ΔHf(CH3OH)= kJ/mol 2/23/2019 S.A. McFarland©2006

3 The Electronic Structure of Atoms
Ch. 7

4 n (principal quantum number) = 1,2,3,…
Some terminology Ground state Lowest energy electronic configuration For H atom, electron is in n=1 orbit Excited state Higher energy configuration For H atom, electron is in n>1 orbit Absorption of photon Requires energy input Quantized Electron moves to higher level Emission of photon Releases energy Electron moves to lower level En = -RH ( ) 1 n2 n (principal quantum number) = 1,2,3,… RH (Rydberg constant) = 2.18 x 10-18J 2/23/2019 S.A. McFarland©2006

5 ( ) ( ) ( ) Ephoton = DE = Ef - Ei 1 Ef = -RH n2 1 Ei = -RH n2 1
nf = 1 ni = 3 nf = 2 ni = 3 Ef = -RH ( ) 1 n2 f nf = 1 ni = 2 Ei = -RH ( ) 1 n2 i i f DE = RH ( ) 1 n2 2/23/2019 S.A. McFarland©2006

6 ( ) DE = RH 1 n2 Ephoton = Ephoton = 2.18 x 10-18 J x (1/25 - 1/9)
Calculate the wavelength (in nm) of a photon emitted by a hydrogen atom when its electron drops from the n = 5 state to the n = 3 state. i f DE = RH ( ) 1 n2 Ephoton = Ephoton = 2.18 x J x (1/25 - 1/9) Ephoton = DE = x J Ephoton = h x c / l l = h x c / Ephoton l = 6.63 x (J•s) x 3.00 x 108 (m/s)/1.55 x 10-19J l = 1280 nm 2/23/2019 S.A. McFarland©2006

7 Why is e- energy quantized?
Electrons in orbits behave like standing waves (De Broglie, 1924) As a wave, the length of the wave must fit the circumference of the orbit exactly Particle (mass) and wave (wavelength) properties are related 2pr = nl l = h/mu u = velocity of e- (in m/s) m = mass of e- (in kg) 2/23/2019 S.A. McFarland©2006

8 What is the de Broglie wavelength (in nm) associated with a 2
What is the de Broglie wavelength (in nm) associated with a 2.5 g Ping-Pong ball traveling at 15.6 m/s? l = h/mu h in J•s m in kg u in (m/s) l = 6.63 x / (2.5 x 10-3 x 15.6) l = 1.7 x m = 1.7 x nm 1 J = 1 kg m2 / s2 Wave-like properties of a large object like a tennis ball cannot be detected… 2/23/2019 S.A. McFarland©2006


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