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Instructor: Alexander Stoytchev
CprE 281: Digital Logic Instructor: Alexander Stoytchev
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Karnaugh Maps CprE 281: Digital Logic Iowa State University, Ames, IA
Copyright © Alexander Stoytchev
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Administrative Stuff HW4 is out It is due on Monday Sep 18 @ 4 pm
It is posted on the class web page I also sent you an with the link.
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Administrative Stuff Homework Solutions are posted on BlackBoard
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Quick Review
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Do You Still Remember This Boolean Algebra Theorem?
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Let’s prove 14.a
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Let’s prove 14.a 1
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Let’s prove 14.a 1 1
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Let’s prove 14.a 1 1 1
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Let’s prove 14.a 1 1 1 1
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Let’s prove 14.a 1 1 1 1 They are equal.
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Motivation An approach for simplifying logic expressions How do we guarantee we have reached minimum SOP/POS representation?
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Two-Variable K-Map
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Karnaugh Map (K-map) View the function in a visual form
Same information as truth table Easier to group minterms x x 1 2 x 1 x 2 m 1 1 m m m 1 2 1 m 2 1 m m 1 3 1 1 m 3 (a) Truth table (b) Karnaugh map [ Figure 2.49 from the textbook ]
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Minterms x x x x m m m m m 1 1 m 1 1 1 m 1 1 1 1 m 1 1 1 1 2 1 2 1 2 3
1 2 3 m 1 1 m 1 1 1 1 m 1 1 2 1 1 m 1 1 1 3
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Minterm Example x x x x m m m m m + m 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
2 1 2 m m m m m + m 1 2 3 1 3 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
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Minterm Example _ x1x2 + x1x2 = x2 x x x x m m m m m + m 1 1 1 1 1 1 1
1 2 3 1 3 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 _ x1x2 + x1x2 = x2
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Grouping Example x 1 x 1 x 2 x 2 1 1 1 1 1 1 m0 m1
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Grouping Example + = m0 + m1 = m0 + m1 x x x x x x 1 1 1 1 1 1 1 1 1 1
2 x 2 x 2 1 1 1 1 1 + = 1 1 1 1 1 m0 + m1 = m0 + m1
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Grouping Example + = m0 + m1 = m0 + m1 x x x x x x 1 1 1 1 1 1 1 1 1 1
2 x 2 x 2 1 1 1 1 1 + = 1 1 1 1 1 m0 + m1 = m0 + m1
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Grouping Example + = m0 + m1 = m0 + m1 _ _ _ _ + =
2 x 2 x 2 1 1 1 1 1 + = 1 1 1 1 1 m0 + m1 = m0 + m1 _ _ _ _ x1x2 + x1x2 = x1 Property 14a (Combining)
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Grouping Rules Group “1”s with rectangles Both sides a power of 2:
1x1, 1x2, 2x1, 2x2, 1x4, 4x1, 2x4, 4x2, 4x4 Can use the same minterm more than once Can wrap around the edges of the map Some rules in selecting groups: Try to use as few groups as possible to cover all “1”s. For each group, try to make it as large as you can (i.e., if you can use a 2x2, don’t use a 2x1 even if that is enough).
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Two-Variable K-map (a) Truth table (b) Karnaugh map x x x x m 1 1 m m
2 x 1 x 2 m 1 1 m m m 1 2 1 m 2 1 m m 1 3 1 1 m 3 (a) Truth table (b) Karnaugh map [ Figure 2.49 from the textbook ]
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Step-By-Step Example x x 1 2 1 1 1 1 1 1 1
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1. Draw The Map x x 1 2 x 1 x 2 1 1 1 1 1 1 1 1 1
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2. Fill The Map x x 1 2 x 1 x 2 m 1 3 2 1 1 1 1 m m 2 1 1 m m 1 3 1 1 1
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2. Fill The Map x x 1 2 x 1 x 2 m 1 3 2 1 1 1 1 1 1 1 1 1 1 1 1
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3. Group x x 1 2 x 1 x 2 m 1 3 2 1 1 1 1 1 1 1 1 1 1 1 1
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3. Group x x 1 2 x 1 x 2 m 1 3 2 1 1 1 1 1 1 1 1 1 1 1 1
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3. Group x x 1 2 x 1 x 2 m 1 3 2 1 1 1 1 1 1 1 1 1 1 1 1
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4. Write The Expression x x 1 2 x 1 x 2 1 1 1 1 1 1 1 1 1 1 1 1
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4. Write The Expression _ x1 + x2 x x x x 1 1 1 1 1 1 1 1 1 1 1 1 1 2
1 1 1 1 1 1 1 1 1 1 1 1 _ x1 + x2
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Writing The Expression
Find which variable is constant x 1 x 2 _ 1 x1 is constant 1 1 1
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Writing The Expression
Find which variable is constant x 1 x 2 1 x1 is constant 1 1 1
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These are all valid groupings
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These are also valid But try to use larger rectangles if possible.
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This one is valid too In this case the result is the constant function 1.
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Why are these two not valid?
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Let’s Find Out x 1 x 1 x 2 x 2 1 1 1 1 1 1 m0 m3
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Let’s Find Out + = m0 + m3 = m0 + m3 x x x x x x 1 1 1 1 1 1 1 1 1 1 1
2 x 2 x 2 1 1 1 1 1 + = 1 1 1 1 1 m0 + m3 = m0 + m3
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Let’s Find Out + = m0 + m3 = m0 + m3 x x x x x x 1 1 1 1 1 1 1 1 1 1 1
2 x 2 x 2 1 1 1 1 1 + = 1 1 1 1 1 m0 + m3 = m0 + m3
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Let’s Find Out + = m0 + m3 = m0 + m3 _ _ = + _ _ +
x 1 x 1 x 1 x 2 x 2 x 2 1 1 1 1 1 + = 1 1 1 1 1 m0 + m3 = m0 + m3 _ _ = x1x2 + _ _ x1x2 + x1x2 We can’t use Property 14a here. This can’t be simplified.
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Three-Variable K-Map
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Location of three-variable minterms
[ Figure 2.51 from the textbook ]
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Location of three-variable minterms
Notice the placement of Variables Binary pair values Minterms
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Gray Code Sequence of binary codes
Two neighboring lines vary by only 1 bit 000 001 011 010 110 111 101 100 00 01 11 10
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Gray Code & K-map s x1 x2
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Gray Code & K-map s x1 x2 000 010 110 100 001 011 111 101
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Adjacency Rules adjacent columns
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Adjacency Rules As if the K-map were adjacent drawn on a cylinder
columns
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Adjacency Rules m0 m2 m4 m1 m3 m5 As if the K-map were adjacent
drawn on a cylinder adjacent columns
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These are valid groupings
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These are valid groupings
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These are valid groupings
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These are valid groupings
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These are valid groupings
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This is a valid grouping
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Some invalid groupings
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Examples of three-variable Karnaugh maps
[ Figure 2.52 from the textbook ]
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Four-Variable K-Map
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A four-variable Karnaugh map
[ Figure 2.53 from the textbook ]
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A four-variable Karnaugh map
x1 x2 x3 x4 m0 1 m1 m2 m3 m4 m5 m6 m7 m8 m9 m10 m11 m12 m13 m14 m15
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Adjacency Rules adjacent rows adjacent columns adjacent columns
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Adjacency Rules adjacent rows As if the K-map were drawn on a torus
columns
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Adjacency Rules m8 m10 m0 m2 m14 m12 m6 m4 adjacent rows
As if the K-map were drawn on a torus adjacent columns
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Some Valid Groupings
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Some Valid Groupings
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Some Valid Groupings
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Some Valid Groupings
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Some Invalid Groupings
All sides must be powers of 2.
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Some valid Groupings All sides must be powers of 2.
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Example of a four-variable Karnaugh map
[ Figure 2.54 from the textbook ]
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Example of a four-variable Karnaugh map
[ Figure 2.54 from the textbook ]
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Example of a four-variable Karnaugh map
[ Figure 2.54 from the textbook ]
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Example of a four-variable Karnaugh map
[ Figure 2.54 from the textbook ]
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Five-Variable K-Map
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A five-variable Karnaugh map
[ Figure 2.55 from the textbook ]
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Questions?
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THE END
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