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The chromatic gap and its extremes
The chromatic gap and its extremes András Sebő, CNRS, G-SCOP,Grenoble with András Gyárfás MTA SZTAKI, Budapest, Nicolas Trotignon, CNRS, LIAFA, Paris
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THE PROBLEM What is the maximum of the difference chromatic number – max clique that can be reached by graphs on at most n vertices ?
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(G) := min cover by cliques = chromatic number of complement
(G) := max stable (independent) set of vertices (no induced edge) gap (G) := (G) - (G) 0 This is the (integer linear programming) duality gap of a related linear program
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Perfect, critical, extremal
Perfect : gap = 0 induced subgraph Gap is not necessarily monotonous: gap-critical: G, gap(H)<gap(G) induced H Minimal imperfect : gap-critical with gap = 1. t-extremal graph : of min order with gap t t-extremal gap-critical factorcritical? = 3 = 3 gap=0 = 2 gap=1
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Critique, pas critique ? G facteur-critique ? C9 ? C93 ? G
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s(t) = smallest order of a graph of gap t
gap(n)=max {gap(G) : G has n vertices} gap-extremal ? gap(i)=0 i 4, gap-critical ! ... gap(5)=1, gap(10)=2, … ??? s(t) = smallest order of a graph of gap t s(1)=5, s(2)=10, … , s(t)= 5t ?
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… s(3)=15 ? Counterexample: n=13, =2, =4, =7 gap = 3 s(3)= 13
R13= (3,5)-Ramsey n=13, =2, =4, =7 gap = 3 s(3)= 13
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Ramsey: number, graph Ramsey number : R(,):=the smallest integer s.t.: every graph on at least R(,) vertices has either an -clique or an -stable set. (Ramsey theorem: it is finite.) Ramsey graph : Graph on R(,) – 1 vertices having neither an -clique nor an -stable set. Example : R(3,3) =6; (3, 3) Ramsey graph R(3,2), R(3,3), … : 2, 6, 9, 14, 18, 23, 28, 36, ? R(4,4), R(4,5) : 18, 25, ?
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gap(G) + 1 gap(G-Q) gap(G) - 1
EASY FACTS Fact 1 : If C1 , … , Ck the components of G, gap(G) = gap(C1) + … + gap (Ck) G is gap-critical all of its components are. Fact 2 : If G is a graph and Q a clique : (G) (G-Q) (G)-1, (G) (G-Q) (G)-1 gap(G) + 1 gap(G-Q) gap(G) - 1 Fact 3 : If a t-extremal graph has a k-clique, s(t) s(t-1) + k
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How big should be for a big gap ?
gap= - n / large ~ small ~ large (Ramsey) How does gap = - change if varies ? Conjecture: t-extremal graphs are -free (=2). gap2 (n) : max gap of a triangle-free on n vertices s2 (t) : min order of a triangle-free of gap t. Theorem : s(t) = 2t + (sqrt (t log t ) ) = s2 (t) gap(n)=gap2 (n), s(t)=s2 (t) for all n, t
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Inverse Ramsey (n) := min {(G): G triangle-free of order n}
If R(3, ) n < R(3, + 1 ) ,then (n) = For instance : (5) = 2 , (6) = 3 Fact: If n = n1 + n2 , then (n) (n1) + (n2) If ‘’=‘’ n is Ramsey-perfect; (10)=(5) + (5) Conjecture: This is the only nontriv example
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A version of the main result
Theorem: n / 2 - (n) gap(n) n / 2 - (n)+3 and with the exception of Ramsey numbers + 1, … , 14, there is equality with the lower bound The extremal graphs are triangle-free.
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The proof relies on two lucky facts :
(1) gap2 is relatively easy to determine (2) Whenever gap > gap2 the growth of gap slows down while gap2 grows constantly except at Ramsey If s (t+1) s2 (t+1), then s (t+1) s (t)+3 s2 (t+1)=s2 (t) + 2, unless s2 (t)+1 or +2 is Ramsey
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The gap of triangle-free graphs
The more you want, the less you get : For gap-critical graphs,(if they are connected): = n / 2 , so gap = n / 2 - (n) If not connected, apply to components : the components are connected, gap-critical
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If G is gap-critical, (G) > (G-v) for all v.
If G is triangle-free, connected and (G) > (G-v) for all v, then (G) = n / 2 Gallai : For triangle-free : + =n Gallai : If (G-v) = (G) for every vertex v, then G-v has a perfect matching –’’--. In particular, n is odd
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Triangle-free, connected cont’d :
THEN GAP-CRITICAL FACTOR-CRITICAL Proof of Gallai’s Lemma : … Equivalent to Tutte’s theorem ( Tutte-set)
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The gap of triangle free graphs
Theorem : gap2 (n) = n / 2 - (n) , or +1 the latter n is even Ramsey-perfect. Proof: At most 2 comp: from inequalities about Ramsey: if n =n1 + n2 + n3 , then (n) < (n1) + (n2) + (n3) 2 comp : if of only if n is even, Ramsey- perfect, and the components have odd size n1, n2 , (n) = (n1) + (n2) For the connected components by Gallai: = n / 2
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The proof relies on two lucky facts :
(1) gap2 is relatively easy to determine (2) Whenever gap > gap2 the growth of gap slows down while gap2 grows constantly except at Ramsey If s (t+1) < s2 (t+1), then s (t+1) s (t)+3 n / 2 - (n)
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Theorem: 0 gap(n) - gap2 (n) 2 and they are equal everywhere but on small constant size intervals after Ramsey numbers. Corollary: All subgraphs of (3, ) Ramsey-graphs of order at least R(3, -1) are perfectly matchable. T s(t) or 21, 32 or R , 9, , 18, ,28,
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0 s2(t) - s (t) 10 n / 2-(n) gap(n) n / 2 - (n)+3
= almost always NOT YET THE END The conjectures ? Dramatic corollaries for Ramsey ? s(5) = 20 or 21 (= s2(5) ) ?
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